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A test based on the Rule Of The Third.

Started by ugly bob, Nov 13, 09:13 AM 2012

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0 Members and 1 Guest are viewing this topic.

porkeporkeporke

If there are several tables in the casino ,you will be surprised that there will be 16/17/18 unique nrs on some tables.(so no repeaters yet,only unique nrs)The start playing the unique nrs for a hit ,use prog if needed or play for more then1 win.this is 1 of the best systems to play and pretty safe ,its slow and not very easy to get the bets out on the table in time without making mistakes(real life casino off course).But possible HG ,maybe even THE HG !!To win at poker one needs patience ,it is the same with roulette.
Kind regards to all.....

ugly bob

Although I did just have a quick glance down and look what I found.

xx 1.
34 2.
11 3.
6 4.
18 5.
17 6.
21 7.
30 8.
3 9.
13 10.
16 repeat.10.
xx 11.
xx 12.
14 13.
26 repeat.3.
25 4.
21 5.
34 6.
31 repeat.6.
11 7.
22 8.
x 9.
17 10.
x repeat.2.
28 3.
21 4.
7 5.
24 6.
16 7.
xx 8.
35 9.
10 10.
14 11.
22 12.
xx 13.
9 repeat.12.
30 repeat.7.
18 repeat.3.
19 4.
xx 5.
24 6.
25 7.
10 repeat.3.
20 4.
33 5.
21 6.
24 7.
xx 8.
xx repeat.1.
33 2.
24 3.
14 4.
xx 5.
8 6.
31 7.
23 repeat.7.
11 8.
16 9.
xx repeat.6.
xx repeat.1.
5 2.
35 3.
30 4.
xx 5.
7 6.
x 7.
19 repeat.7.
23 8.
11 repeat.5.
33 6.
20 7.
6 repeat.6.
16 7.
8 8.
xx 9.
xx repeat.1.
17 repeat.1.
19 2.
11 3.
16 4.
x 5.
0 6.
3 7.
7 8.
5 repeat.4.
16 5.
23 6.
9 7.
35 8.
x 9.
34 10.
15 11.
28 12.
x repeat.4.
7 5.
36 6.
6 7.
11 8.
21 9.
30 10.
4 repeat.7.
34
4
25
10
3
15
27
24
15
31
5
6
15
24
26
7
1
9
27
15
22
19
1 1.
6 2.
12 3.
9 4.
33 5.
3 6.
29 7.
32 8.
7 9.
10 10.
16 11.
28 12.
25 13.
35 14.
17 15.
19 16.
31 17.
13 18.  (hooray)
21 19.
11 20.
14 21.
27 22.
14 repeat.
2 23.
15 24.
11 repeat.
28 repeat.
24 25.
25 repeat.
1 repeat.
14 repeat.
22 26.
36 27.
5 28.
29 repeat.
3 repeat.
11 repeat.
10
27
2
9
13
27
18
3
20
32
32
29
19
3
3
34
9
29
34
23
27
9
35
18
2
7
1
16
8
3
4
29
27
1
22
12
18
35
20
22

There was a group that produced 22 original numbers in this batch of 200 before the first repeat.
It produced 9 repeats after that within the 37 spin cycle. (9 within 15 spins) That is what I was looking for. I just am not sure how often that would replicate itself and if there is an optimal way to take advantage.

bob.

macduff

I too have followed this route for 1000s of spins,18 unique numbers is not that uncommon over say 10,000 spins.To me this is the one stable outcome in roulette you will have repeating numbers within 24 spins.How your bank roll handles betting on 18 numbers is another thing,it is a no no flat betting you need a progression with this.  :'(


ugly bob

One idea that keeps running through my head is something I should probably call 'reverse roulette'.
First of all I need to have 18 splits and I keep a count of how many there are.

Here are the first 18. I only keep originals in the list of 18 and knock out the furthest back of a repeat.
The ones knocked out will have an x where the split was.

11. 1
12. 2
7. 3
18. 4
x. 5
x. 6
x. 7
9. 8
13. 9
10. 10
5. 11
4. 12
8. 12
3. 12
17. 12
14. 13
15. 14
6. 15

Now I have my list of 18 and there are 15 originals which is unusually high.
I call it reverse roulette because I am looking for the number of splits to decrease.
I always keep the list at 18 splits.

Here is how it continued.



12. 2
7. 3
18. 4
x. 5
x. 6
x. 7
9. 8
13. 9
10. 10
5. 11
4. 12
x. 12
3. 12
17. 12
14. 13
15. 14
6. 15
8. 14

The 8 split came here and so I had to delete the furthest back 8 split. You can see where I put the x.
I also need to knock out the very furthest split which was the 11 completely.
I need to do this to keep the list at 18 splits.
Now the number is down to 14 originals from 15 on the previous spin.
This is where it is going in reverse.
My plan would be to bet the splits when they are going in reverse.
I think I would start from around 12.
15 or 14 is artificially high in my opinion.

After the next spin.



7. 3
18. 4
x. 5
x. 6
x. 7
9. 8
13. 9
x. 10
5. 11
4. 12
x. 12
3. 12
17. 12
14. 13
15. 14
6. 15
8. 14
10. 13

Now it is down to 13 and I deleted the furthest back 10 split.
I also knocked out the very furthest back 12 split completely.
The good thing when this is working well is that you will be putting on less and winning more.
That may be excellent for playing some kind of positive progression.
A lot of players bet more when things are going wrong. I believe that is the opposite of what we should do.

After the next spin.




18. 4
x. 5
x. 6
x. 7
9. 8
13. 9
x. 10
5. 11
4. 12
x. 12
3. 12
17. 12
14. 13
x. 14
6. 15
8. 14
10. 13
15. 12

It is down to 12 now which is probably where it should be on average.
I deleted the furthest back 15 split and also knocked out the very furthest back 7split completely.
Now I can back all these 12 splits and hope it continues in reverse.

After the next spin.


x. 5
x. 6
x. 7
9. 8
13. 9
x. 10
5. 11
4. 12
x. 12
x. 12
17. 12
14. 13
x. 14
6. 15
8. 14
10. 13
15. 12
3. 11

It is now down to 11.
I deleted the furthest back 3 split and also knocked out the very furthest back 18 split completely.
Now I only need to back 11 splits on the next spin.

x. 5
x. 6
x. 7

13. 9
x. 10
5. 11
4. 12
x. 12
x. 12
17. 12
14. 13
x. 14
6. 15
8. 14
10. 13
15. 12
3. 11
18. 11

That spin was a loss because the 18 is a new split.
I can not delete a split this time and that is why the count stays at 11.
I did however knockout the 9 split completely because I need to keep the list to 18.
So what would I do here?
It is a no bet because the reversing has stopped.
I will wait to see what happens next.

x. 5
x. 6
x. 7


x. 10
5. 11
4. 12
x. 12
x. 12
17. 12
x. 13
x. 14
6. 15
8. 14
10. 13
15. 12
3. 11
18. 11
14. 10

The 14 split came. I deleted the furthest back 14 and knocked out the very furthest back 13 split completely.
The count has now gone down to 10 and it is in reverse again.
That puts me back in action and I only need to bet 10 splits on the next spin.

x. 5
x. 6
x. 7


x. 10

4. 12
x. 12
x. 12
17. 12
x. 13
x. 14
6. 15
8. 14
x. 13
15. 12
3. 11
18. 11
14. 10
10. 9.

The 10 split came. I deleted the furthest back 10 and knocked out the very furthest back 5 split completely.
The count is now down to 9.

That pretty much gives you a good idea of things.
One thing that caught my mind with this after putting up that rule of the third chart earlier.
I said that you would be unlikely to see just 12 original numbers in a 37 spin cycle.
So you could argue with this that you would be unlikely to see it go down in reverse much further than 6 splits.
You could use that chart to get a rough idea where the hotspot might be with this.

Play around with it and see what you think.
Shoot with any questions.


bob.

ugly bob


Here are some more numbers for reverse roulette.

8
2
5
14
11
2
16
9
5
8
2
13
17
7
10
5
9
6
2
5
8
3

And here is reverse roulette in action.

x. 1
x. 2
x. 3


x. 5

x. 7
x. 7
x. 7
x. 7

17. 9
7. 10
10. 11
x. 11
9. 11
6. 12 (here are the 18 splits. 12 out of 18 have shown which is average)
2. 11 (win. delete the furthest back 2 and knock out the very furthest back 14)
5. 10 (win. delete the furthest back 5 and knock out the very furthest back 11)
8. 9 (win. delete the furthest back 8 and knock out the very furthest back 16)
3. 9 (lose. knock out the very furthest back 13. This halted the reverse)

bob.

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