The Road to Riches has 6 steps

[GLC]

Step 1.  Bet 1 unit on any dozen or column.  If you lose, move 1 step to the right in progression line and repeat step 1.  If you win you will have won 2 units.  Go to Step 2.

Step 2.  Bet 2 units on an even chance.  If you lose stay at same level in progression line and repeat Step 1.  If you win you will have 4 units.  Go to Step 3.

Step 3.  Bet 4 units on an even chance.  If you lose stay at same level in progression line and repeat Step 1.  If you win you will have 8 units.  Go to Step 4.

Step 4.  Bet 4-4 units on 2 dozens.  If you lose stay at same level in progression line and repeat Step 1.  If you win you will have 12 units.  Go to Step 5.

Step 5.  Bet 6-6 units on 2 dozens.  If you lose stay at same level in progression line and repeat Step 1.  If you win you will have 18 units.  Go to Step 6.

Step 6.  Bet 9-9 units on 2 dozens.  If you lose stay at same level in progression line and repeat Step 1.  If you win you will have 27 units, go to Step 1.

Progression Line:
1 = 27 times
2 = 14 times
3 = 9 times
4 = 7 times
5 = 5 times
6 = 5 times
7 = 4 times
8 = 3 times
9 = 3 times
10 = 3 times
11 = 3 times
12 = 2 times
13 = 1 time

If you lose the entire progression line you will have not only lost -354 units, but you will also be the most unlucky person on the planet.


GLC

Sam,  The above is the basic system.


The 1 = 27 times means that you can start an attack betting 1 unit on a dozen 27 times and if you win all 6 steps you will still be +1 and can reset back to the beginning of the bet line.


Where does 27 come from?  If you bet 1 units on 1 dozen and win you  will have won 2 units.  Now bet the 2 units you just won on an even chance.  If you win you will have 4 units.  Now bet the 4 units on an even chance.  If you win you will have 8 units.  Now bet 4 units on each of 2 dozens.  If you win you will have 12 units.  Now bet 6 units on each of 2 dozens.  If you win you will have 18 units.  Now bet 9 units on each of 2 dozens.  If you win you will have won 27 units.  Not only that but you still have your original unit so even if you lost somewhere along the way, you can just replay that attack.


That's where we get the 27.  Since we win 27 units, and we lose 1 unit when we lose, we can attempt to win starting out with 1 unit 27 times.  If we lose 27 times, we will have to start off betting 2 units on a dozen to be able to recover our lost 27 units plus some profit.


That's the conservative approach.  With the aggressive approach, we bet 1 unit on a dozen.  If we win we bet all 3 units on the even chance instead of just the 2 units we won from the casino.  By doing this we end up with 39 won units instead of 27 but we lose our starting unit if we don't win all 6 bets.


Remember, we're betting 1 time on a dozen, 2 times (parlay) on even chances, and 3 times (parlay) on double dozens.  We just keep betting everything we won on the next bet.


The progression I gave you is the conservative approach.  It represents 86 chances to win and fully recover all previous losses just like a martingale.  It will cost you -354 units if you lose all 86 attacks.


This system is really a convoluted parlay system but it uses different bet locations instead of just 1.


It can be shortened quite a bit by the following:


Play 1 unit on a dozen or column.
If it wins play all 3 units on an even chance.
If it wins play 3 units on each dozen of a double dozen.
If that wins we will have 9 units.
9-1 = +8 units net


Our martingale progression line is:


1
1
1
1
1
1
1
1
2
2
2
2
3
3
3
4
4
5
5
6


That's 20 chances to win 3 times in a row.  -50 units if you lose all 20 attempts.


Every time you reach a profit, reset.


If you want you can go much further with the progression line.


I often think that the strongest system on this forum is Flatino's.  He recommends 1000 unit bank to win 100 units.


If you carried this progression line out as far as you could with 1000 units, you would have a good bench mark to test it against Flatino's.


As a matter of fact here's the rest of the progression all the way up to -952 units if you lose the whole line.  That's 44 attempts to win 3 bets in a row, a dozen then an even chance then a double dozen.  The hardest part is winning the single dozen bet.  Once you do that, you should be able to win the even chance bet half the time and once you do that you should be able to win the double dozen bet 2/3rds of the time.


7
8
9
10
11
12
14
16
18
20
22
25
28
33
37
41
47
52
59
66
75
84
94
106


Remember this like a martingale any time you win the 3 bets you will be at a new profit and can start over all the way back to the 1st 1.


If you've got $10 you can test this on the 1 cent roulette table.


George

[TwoCatSam]

OK, George from Arizona, I really thank you for all that typing and explaining.

I must take it one step at a time.

We must jump six hurdles to win.  Right?

I start with one unit.  I have 27 attempts to jump those six hurdles, right?

Really, that's all I can digest at once.  If I can't even get step one right, I might as well not continue.

Am I right so far?

Samster

[GLC]

You are right my dear friend.

Those 6 bets represent 1 attack or 1 number in the bet line.
The numbers in the bet line represents only the amount you bet on the 1st of those 6 bets.  The other 5 bets are built on the winnings from the 1st bet on the single dozen.

But remember, if you're on the 5th bet of the 6 and you see that you are at a new high bank amount, should consider skipping the 6th bet and reset.

I'm getting ready to post another system similar to this one that's a little easier, but is superb also.

GLC

[TwoCatSam]

Not gonna read it; wouldn't be prudent!

Sticking with the six until I learn them

So, GLC, suppose I cross off 27 ones.  I then start with the 2s and I have five steps to riches.  Is that it?  Then the 3s and so on?

Sam

[GLC]

Not gonna read it; wouldn't be prudent!

Sticking with the six until I learn them

So, GLC, suppose I cross off 27 ones.  I then start with the 2s and I have five steps to riches.  Is that it?  Then the 3s and so on?

Sam

No Samster. 

You always have 6 steps to Riches.

If you lose 27 times without winning, you will be down -27 units.  When you go to  the first 2, it represents the bet on the single dozen.  We win each bet in this example so I won't have to say it each time. 

We bet 2 on the single dozen which gives us 6 units on the table.  We keep our 2 original bets and we bet 4 units on an even chance which gives us 8 units.  Since we bet an even chance 2 times, we bet our 8 units on an even chance which gives us 16 units.  Since we have won our 2 even chance bets we next split our winnings in half and bet half on each of 2 dozens.  So we bet 8 units on 2 dozens and a win gives us 24 units.  The 16 we bet and the 8 we won.  With 24 units we bet 12 units on each of 2 dozens.  This win gives us 36 units which we divide by 2 and get 18 units to bet on each of 2 dozens.  A win here and we have 18-18 bet wins another 18 which = 54 units.

Since we were down 27 units from our series of 1's that we lost, we subtract 27 from 54 and we are +27 units.

Had we lost the first 2 unit attack, we would go to the next 2 unit attack and if we win all 6 bets on it, we would be at +23 units.  That's because we lost 4 units on the 1st 2 unit attack so we have -27 -4 = -31 +54 = +23. 

We keep playing the 2's until we lose enough so that a win on the 6 bet attack leaves us at less than even.  Then we move to the 3 unit attacks, etc... 

[GLC]

One thing I want to point out is when we reached our first 2 in the bet line we were down -27 units.  Here's what happened from there.  We bet 2, won and had 6 less our 2 units we bet and we had 4.  We bet 4, won and had 8.  We bet 8, won and had 16.  We bet 8-8, won and had 24.  Notice that at this point we've won 24 units so we are only down -3 units.  We could stop our 6 bet process and just reset to our 1st 1 unit bet and start our progression line all over.

Or when we have 24 units, our second bet on the double dozens would be 12-12, win and we have 36 units which is 9 units more than we are down.  I would never bet the 6th bet which is 18-18 on 2 dozens.  I would take the 9 unit win and start over.

As you can see, we have option all along the way.  Risk vs Reward comes into play.

The one thing I don't know is whether it's financially advantageous to always play the 6 bets even if it nets us a lot of units above what we need to reach a new high because those units may be important to offset times when we must lose the entire porgression.

If every attack only nets us a few units win, we may not be able to stay ahead of the grim reaper when we lose a 1000 unit bankroll.  Or, it may because there will be times when we get to reset and those 5 out of 6 wins was all that was separating 2 long strings of losses and we never get a 6 step win before we exhaust our bet line.

That may be something we'll never be able to determine.  Just pick whichever one you like to play best and go for it is my opinion.

Just be sure those 1000 units aren't more than you give to your church or you'll be in big trouble.

[vladir]

You could play this with a base unit of 0,10 cents... until loose 27 units (2,7 â,¬)

Then you could play again, using a base unit of 3â,¬, aiming for just 1 win. If loose this, it's a loss of 27*3 = 81 â,¬

Total BR required for this: 83,7â,¬.

I think the likelihood of loosing 2 times this kind of bet is very very low... But it's also a litle boring playing this way just to win 10 cents once in a while (and you still have a very very small risk of a visit from the reaper).

(Just posted this here cause I had the same idea for another system a moment ago)