Need your help!

[Blue_Angel]

I want to figure out a progression of 6 steps for multiple bet sections.

1) Bet last dozen
2) Bet again the same dozen and the last line
3) Bet again the same dozen, line and the last corner
4) Bet again the same dozen, line, corner and the last street
5) Bet again the same dozen, line, corner, street and the last split
6) Bet again the same dozen, line, corner, street, split and the last number

The progression must profit with only one win regardless of which bet will succeed.
Different payouts make it difficult to calculate all 6 steps, however, I've found the first 4 steps:

1) 1 unit on last dozen, if win +2, if loss -1

2) 2 units on same dozen plus 1 unit on last line, if win +2, if loss -4

3) 5 units on same dozen, 3 units on same line plus 2 units on last corner, if dozen wins +1, if line or corner wins +4, if a loss -14

4) 19 units on same dozen, 10 units on same line, 7 units on same corner plus 5 units on last street, if dozen wins +2, if line or street wins +5, if corner wins +8, if a loss -55

5) ?

6) ?

Can you help?

[RouletteGhost]

Im interested.

As i have thought about similar before

[Blue_Angel]

Another progression of only 3 steps but the last one is very steep.

1) Bet last high or low with 1 unit, +1/-1

2) Bet the previous decision of high or low with 6 units plus the 1st or 3rd dozen with 4 units, if it was one of the two lines of the 2nd dozen then bet 2 units on that line plus 2 units on one of the rest, +1/-11

3) Repeat the same selection as above and add the corner of the number which just make you lost.
111 units on EC + 74 units on dozen (or 2 lines * 37 units) + 25 units on corner +1 from EC or dozen or lines, +4 from corner, -222 units for one of the other three numbers.

I don't have names for those two yet, but I'm open for suggestions.