The STAR progression with my own personal 'star group method' to follow.

[flukey luke]

Hello guys and gals.

Here is a progression that some of you may not have seen before.

It is the STAR progression. It was developed by the author in the 80's. There is no copyright on the manual from what I can see. Please pull it if it is against any laws.

I have studied this the last few days and have a bet selection method that seems to compliment it well.

So enjoy the read and I will start typing out my star group method.

[flukey luke]

The picture below gives a snapshot of how my star group method works.

Yo can use all the even chances but in this example I am just using EVEN and ODD.


[attach=#]

Next up will be a detailed description of how the groups work.

[flukey luke]

The star group method is an even chance bet. It is ideal for playing on the bet voyager no zero roulette wheel.

The method works in pairs as you can see by the snapshot.

The groups for all the even chances are as follows.

RED/RED = GROUP 1.  RED/BLACK = GROUP 2. BLACK/BLACK = GROUP 3. BLACK/RED = GROUP 4.

EVEN/EVEN = GROUP 1. EVEN/ODD = GROUP 2. ODD/ODD = GROUP 3. ODD/EVEN = GROUP 4.

LOW/LOW = GROUP 1. LOW/HIGH = GROUP 2. HIGH/HIGH = GROUP 3. HIGH/LOW = GROUP 4.

Take a  look at the snapshot on the spreadsheet which concentrates on the ODD and EVENS to give you an idea of what's going on.

The first three groups out are the 3, 4 and 2. This leaves the 1 as the furthest back group. (In fact it has not appeared yet but I still count it as the furthest back group)

So the 1 is the furthest back group and it consists of EVEN/EVEN.

If the 1 group continues to be absent, I will see either a group 2, 3 or 4.

These groups contain the following.

EVEN/ODD.
ODD/ODD.
ODD/EVEN.

So looking at them three choices, you can see that an ODD has to appear in either the first or second result of the pair.

The next two pairs produced ODD/EVEN (group 4) and ODD/EVEN (group 4). Following the odd, you would have had two wins on the first result of each pair.

The next group that came out was group 1. This was the furthest back group. So now the furthest back group is group 3.

If the 3 group continues to be absent, I will see either a group 1, 2 or 4.

These groups contain the following.

EVEN/EVEN.
EVEN/ODD.
ODD/EVEN.

So looking at those three choices, you can see that EVEN has to appear in either the first or second result of the pair.

The next 5 pairs produced EVEN/EVEN (group 1), EVEN/EVEN (group 1), EVEN/ODD (group 2).
EVEN/EVEN (group 1), EVEN/ODD (group 2). The first 5 results in each pair were EVEN.

Using this idea with the groups combined with the star progression works really well.

The ideal way to play would be track all three even chances if you can and find out which ones are performing best.

The record that I have seen for the furthest back group going to sleep is 27 pairs.

What tends to happen is that the furthest back group will hit in waves. In other words, you will get a period where a few of them hit very close together and they then go missing for long periods. That's why I recommend tracking all three even chances. That way you will nearly always have something to bet on.

I will show some examples and go into more detail as time permits.

[Bayes]

Now here's a blast from the past. 

Much favoured by Johno, I think he adapted it and called it E-star (E meaning 'extended'). 27 without a hit sounds about right to me, that's equivalent to around 50 - 60 spins without a double win.

[flukey luke]

If you have read the original STAR system, you will see that it works in sets.

You try to win a set and then start again or quit with your profit. There are recovery stages should you lose a set. I am impressed with the consistency of the method and that's what made me look for a bet selection to go with it. I think my 'groups' idea fits in well with the whole concept.

So let's look at a set.

1
1
1
â€"
3
6
9
15
24

This could be your starting point. You will know by now that the first three numbers are you pre-progression stage. You look to win with a parlay here. If you lose all three steps, you then move on to the progression stage. You are guaranteed a win at any stage as long as you hit 2 consecutive winning bets.

So now I will show an example of the STAR progression at work with my groups.

34 EVEN
8 EVEN (GROUP 1)

2 EVEN
29 ODD (GROUP 2)

35 ODD
14 EVEN (GROUP 4)  missing group = 3.

So 3 is the missing group here. Which means that if the 3 group continues to go missing, I am going to see either group 1, 2 or 4 appear.

Here are the combinations for those three groups.

Group 1. EVEN/EVEN.

Group 2. EVEN/ODD.

Group 4. ODD/EVEN.

So it is more likely for there to be an EVEN in the first result of the next pair and it is also more likely for there to be an EVEN in the second result of the next pair. So this is what I will be looking for.

29 ODD. So I lost the first bet of the pre-progression stage. Now I will move up to the second step of the pre-progression stage.

18 EVEN. (GROUP 4) missing group = 3. So that was a win on the second stage of the pre-progression stage and now I need to parlay the bet. NOTICE also that the 3 is still the missing group and therefore I will be looking for EVEN  to come up again on the next bet.

15 ODD. So I have lost the parlay attempt on the second step of the pre-progression stage. Now I will move up to the third step of the pre-progression stage.

31 ODD. (GROUP 3) missing group = 1. So that was a loss on the third step of the pre-progression stage and now I need to move on to the full progression.

So far my results are L W L L. I can't win unless I hit 2 consecutive wins.

Notice as well that the missing 3 group appeared and now the new furthest back group is 1. So this means that if the group 1 continues to be the furthest back group, I am going to see either groups 2, 3 or 4.

Here are the combinations for those groups.

Group 2. EVEN/ODD.

Group 3. ODD/ODD.

Group 4. ODD/EVEN.

So it is more likely for there to be an ODD in the first result of the next pair and it also more likely for there to be an ODD in the second result of the next pair. (This is of course assuming that the group 1 continues to be the furthest back group)

So now I am into the full progression stage of the method. You will know by reading the STAR progression that you do not use a parlay here. You are still however looking for 2 consecutive wins.
The great thing here is that if you get a WIN followed by a LOSS, you just stay at that same stage in the progression and do not need to move up.

22 EVEN. So I lost the first level in the progression because I was looking for ODD. Now I need to move up to the second level in the progression and I am betting ODD again.

8 EVEN (GROUP 1) missing group = 2. So I have just lost the second level in the progression.

My record is L W L L L L (I am not having much look)

There is also now a new missing group and that is group 2. This means that if group 2 continues to go missing, I am going to see either group 1, 3 or 4 appear.

Here are the combinations for those groups.

Group 1. EVEN/EVEN.

Group 3. ODD/ODD.

Group 4. ODD/EVEN.

So it is more likely for there to be an ODD in the first result of the next pair and it is more likely for there to be an EVEN in the second result of the next pair.

I am now moving up to the third level of the progression stage.

27 ODD. So that was a win on the third level of the progression stage and now I need to repeat the bet looking for a consecutive win which will take me into profit and allow me to start over again.

28 EVEN. (GROUP 4) missing group = 2. That was another winner and I have now captured the consecutive win and have ended the set with a profit.

I have had 3 winners and 5 losses and yet I have still gained a profit. My total gain is 6 units.

So let me recap the bets.

I started in the pre-progression stage.

Lost the first step. -1.

Won the second step and needed to parlay.

Lost the parlay and needed to move up to the third step. -2.

Lost the third step. -3. (now moving to the full progression)

Lost the first step. -6.

Lost the second step. -12.

Won the third step and needed to repeat the bet looking for a consecutive win. (now at -3)
Won the repeat bet and that ended the set. +6.

So that is a quick example of how I combine my group method with the STAR progression.

I will add more explanations and  a few tweaks that you can add to suit your playing style.

[flukey luke]

Hello Bayes,

Yes, this was one of Johno's favourites. One of my tweaks is to extend it further.

I think using the groups method along with an extended STAR is pretty much unbreakable.

All my tests have yet to show a bust. Of course we all know it is out there somewhere waiting to happen but I think all the wins can add up to make the loss when it comes not a bankroll buster.

[GLC]

Nice post Flukey Luke.

Your group method looks interesting.  Is it a very new idea or have you had a chance to test it some?

I just thought I would post the following.  I had forgotten about this little gem.  Enjoy the read.

Star System Variant

   Here is a little progression that was first introduced by Carsch on GG.

   It is a variant of the original Star System (one of the better public MM systems available on the web), but is better. It requires only about 55% of the original star systems BR and only busts after 30 straight losses...

   Any two wins clear the progression. It allows you to catch streaks, as well as allows you to not go broke with WLWLWL.

   The progression

   Base level:
   1
   1
   2
   2
   4
   4
   8
   8
   16
   16  

See how to play below.  

   1 win & parlay (lose and move on to the next bet)
   1 win & parlay (lose and move on to the next bet)
   2 win & repeat the same bet (In here, in order to move on to the next step, you must lose this bet the first time, or win it and then lose it twice in a row)
   2 win & parlay (lose and move on to the next bet)
   4 win & repeat the same bet (In here, in order to move on to the next step, you must lose this bet the first time, or win it and then lose it twice in a row)
   4 win & parlay (lose and move on to the next bet)
   8 win & repeat the same bet (In here, in order to move on to the next step, you must lose this bet the first time, or win it and then lose it twice in a row)
   8 win & parlay (lose and move on to the next bet)
   16 win & repeat the same bet (In here, in order to move on to the next step, you must lose this bet the first time, or win it and then lose it twice in a row)
   16 win & parlay (lose and move on to Recovery 1)

   Recovery 1 (this is played just like above)

   2
   2
   4
   4
   8
   8
   16
   16
   32
   32

   Recovery 2  (This too is played just like above)

   6
   6
   12
   12
   24
   24
   48
   48
   96
   96

As you can see, it requires 558 units to play base level, recovery 1 and recovery 2.

Base level = 62 units
Recovery 1 = 124 units
Recovery 2 = 372 units

LoL,

George

[flukey luke]

Thank you George for the Carsch variation.

I know a lot of people don't think bet selection really comes into it. However if we can just combine the two (bet selection + MM) I really think we may be on to something.

Here is another snapshot.

[attach=#]

Using all three even chances can point out some really strong trends using the groups.

In this example looking at the EVEN and ODD. The 1 and 4 groups are consistent all the way through.

Group 1 consists of EVEN/EVEN.

Group 4 consists of ODD/EVEN.

So the common denominator here is the EVEN in the last result of each group. It is really just an even chance event which is streaking. So instead of playing on every spin here, I would be tempted to play on every second spin looking to catch the EVEN. This takes some effort to try and read everything that is going on. However it can really pay if you have a very solid and elongated MM plan like STAR or the carsch variant. It is going to be hard when combining strong bet selection and MM for you to lose.

cheers.

[GLC]

Hey FL,

I agree with everything you've posted so far.  I'm starting to see the power of your group method to identify trends.  It is a little complicated to get your mind around it at first, so give me some time to digest it and I'll get back to you.  With questions, probably.

G

[flukey luke]

No problem George and not to confuse the issue but another variation could be as follows.

Another option for the groups could be the use of the D'alembert.

Let's assume the 1 group is the furthest back.

This leaves the possibility of either groups 2, 3 or 4 showing.

Here are the different combinations for EVEN and ODD.

Group 2. EVEN/ODD.

Group 3. ODD/ODD.

Group 4. ODD/EVEN.

So what are the possibilities here. I would be betting for the ODD to show in the first result of the pair and also betting the ODD to show in the second result of each pair.

I am going to flat bet 1 unit to begin with.

If group 2 appears, I lose 1 unit on the first spin and gain that unit back on the second spin.

If group 3 appears, I win 1 unit on the first spin and don't need to bother betting on the second result. I am happy with a 1 unit profit.

If group 4 appears, I win 1 unit on the first spin and again don't need to bet on the second result.

If group 1 appears, I lose 2 units in total having lost 1 unit on the first result of the pair and a further 1 unit on the second result of the pair.

So 3 of the 4 possibilities are not a losing proposition.

On a loss, using some kind of D'alembert would see me raise the initial bet from 1 unit to 2 units.

Doing it this way would not lead to the bets escalating too quickly. Another advantage is not having to hope for a successful parlay or back to back wins.

I have spent the last few years mostly looking at bet selection and not really studying the MM side of things. In some respects, that is like driving a car with a wheel or two missing, LoL.
So my goal for the rest of the year is to try and come up with something really powerful on the MM side of things to go with what I think is a half decent bet selection.

cheers.

[ZeroBlue]

You are really into something especially if you track all 3 ECs
and observe them for imbalance. 

this is for even odd
0 is even if in a neutral spot.

if you take simple groups of 3 and bet on what is trending you get something like this

20   20   18   X   X   X   
6   36   11   X   X   O   
35   5   28   X   X   O   
21   17   21   X   X   X   w
20   15   5   X   O   O   lw
31   6   28   X   O   O   lw
18   36   29   X   X   O   lw
28   32   0   X   X   X   ll
33   31   29   X   X   X   w
12   2   12   X   X   X   w
23   7   36   X   X   O   w
9   19   17   X   X   X   w
36   12   8   X   X   X   w
3   24   22   X   O   O   ll
27   10   19   X   O   X   lw
3   2   32   X   O   O   w
15   6   19   X   O   X   w
12   34   35   X   X   O   ll
32   6   7   X   X   O   lw
9   1   20   X   X   O   w
18   28   21   X   X   O   w
25   15   13   X   X   X   w
30   26   10   X   X   X   w
31   5   1   X   X   X   w
15   13   21   X   X   X   w
33   14   12   X   O   O   ll
0   16   9   X   X   O   w
33   16   5   X   O   X   ll
4   32   31   X   X   O   lw
10   22   9   X   X   O   w
17   4   26   X   O   O   lw
5   6   30   X   O   O   lw
17   10   36   X   O   O   w
11   26   11   X   O   X   w
12   35   23   X   O   O   w
26   28   33   X   X   O   lw
10   17   4   X   O   X   w
24   7   8   X   O   X   w
31   32   35   X   O   X   w
30   24   6   X   X   X   lw
22   3   36   X   O   X   w
26   13   36   X   O   X   w
29   33   0   X   X   O   ll

this is fun
try to sink any progression in this random bet selection. 

[flukey luke]

@ZeroBlue,

I looked at your post last night for about 10-15 minutes and could not get my head around it. Then I looked again first thing this morning and it was as clear as daylight. (Too many late nights I think)
I am going to look at your idea using all three e/c as well. Improving our choices is a worthwhile tactic in my opinion.  When you look at games like bac, you only have either Banker or Player. You could sit through a 60 hand shoe and it could be all over the place.
By using the three e/c bets, even if one or two of them are all over the place, it may be the other one is giving out a really long streak of some description.

[flukey luke]

Another option using the groups.

Let's say that group 4 BLACK/RED (assuming we are playing the colours) is the furthest back.

My records over quite a few years show that the longest a furthest back group has not appeared for is 27 consecutives pairs.

So I came up with a 19 step parlay progression which is just a little under 500 units.

1) bet 1. win 4. +3/-1.
2) bet 1. win 4. +2/-2.
3) bet 1. win 4. +1/-3.
4) bet 2. win 8. +3/-5.
5) bet 2. win 8. +1/-7.
6) bet 3. win 12. +2/-10.
7) bet 4. win 16. +2/-14.
8} bet 5. win 20. +1/-19.
9) bet 7. win 28. +2/-26.
10) bet 9. win 36. +1/-35.
11) bet 12. win 48. +1/-47.
12) bet 16. win 64. +1/-63.
13) bet 22. win 88. +3/-85.
14) bet 29. win 116. +2/-114.
15) bet 39. win 156. +3/-153.
16) bet 52. win 208. +3/-205.
17) bet 69. win 276. +2/-274.
18) bet 92. win 368. +2/-366.
19) bet 123. win 492. +3/-489.

The average win is 2 units and I would suggest playing it on all even chances to provide more betting opportunities.

What you would do is place the first bet and if it wins, let it ride. If you win that bet, you have completed the parlay and go back to the beginning.
If you lose the first bet of a parlay attempt, you go up to the next level.
If you lose the second bet of a parlay attempt, you go up to the next level.

This progression only covers 19 steps. It may be prudent to wait for a few virtual spins before betting.
So let's say the group 4 BLACK/RED is the furthest back. Wait a few further pairs for it not to show before starting the 19 step progression.
Like I said, the longest I have seen  the furthest back group sleep is 27 pairs. However it is a bit time consuming to wait for the furthest back to appear and then wait a further 8 pairs for it to continue to sleep before betting. A happy medium could be waiting for it to sleep a further 3/4 pairs.
The object here would be to build up a cushion of several bankrolls to play this way.
Unfortunately, it is still gambling and this would be costly if it went pear shaped.

As for how many times I have seen the furthest back group hit consecutively.
The answer is 7 times. That is also over a few years and I have seen a few 5's.

It pays to try and build any MM plans around the worst results that you have encountered in real life play or testing. You don't want any nasty surprises at the tables.