Been having some deep thoughts about this game today... here's an interesting system to try:
Bet 1 chip on High. If lose then double up on High - but also add 1 chip to the low single street that caused the loss.
If you lose again then add a chip to the 2nd low single street that caused the loss (so you've now got 2 streets covered) and then double up again on High to 4 chips.
If you win on High you can move down 1 level to 2 chips on High (or it might be best to stay at the same level) - but keep the 2 streets covered. If the zero ever comes in then perhaps cover that.
You play until you either get a win on one of the streets or one of the specific high numbers repeats - ending the cycle. Reset everything back to just 1 chip on High and nothing on the streets.
Any time you lose you double up on High and add a chip to the street. When you win on High (but no number has yet repeated) the above is only a rough guide to the new starting bet for High based on how many Streets are in play - perhaps somebody else can figure out exactly how much should be on High with or without the Zero:
1 street + High = ?
2 streets + High = ?
3 streets + High = ?
4 streets + High = about 16
Are you trying to get a profit from all the stakes laid,to clear the debt in one win.
If high is a kip then will the stakes on low make BR in profit, or will there be some loss on high still.
high = e/c unit value lets say 5
str= 11/1 unit value lets say 1
Lost 5, now double 10
str 1 so 16 units out, if str wins -4
It will need some testing/tweaking - should be easy to code - the concept being kind of similar to the system I am going to attempt to code today and tomorrow (Mist Trap).
(link:://i.imgur.com/tAimFL3.gif)
I call this hedging your bets. They do it on Wall Street all the time. Always place one bet/trade in opposition of another. You may not win big, but you won't lose big either and the odds are with you that you will win something.