Full System: "3 Sets Of Numbers" / can someone explain?

[Red Nickels]

because it looks interesting but I don't get it.     thanks.   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .  

Roulette System "3 Sets Of Numbers"
1).    We will be working with 3 sets of numbers.  
2).    Those sets are: zero to ten ( 0 to 10 ) eleven to twenty ( 11 to 20 ) and twenty-one to thirty ( 21 to 30 )
4).    Using a simple reduction technique, we are going to reduce those sets until one set has only six numbers remaining.  
5).    We will play those  six numbers for a maximum of six spins.  
6).    When one of the six numbers strikes, we discard that set of six, and proceed to find another six, using the same tequnique.  
7).    We use flat bets only.  
8   We ignore all the numbers above 30.  
9).    THE METHOD.  

For simplicity sake:   ALL the roulette numbers can be represented as >    1.   2.   3.   4.   5.   6.   7.   8.   9.   0.  

(1 is 1.   11.   21.   31.   .   .   .    2 is 2.   12.   22.   32.     .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   0 is 0.   10.   20.   30.    etc etc.   )

Counting back  from (and including) the last number spun, we proceed through the previously spun numbers in sequence, one at a time.  

For every 1 we also reduce a  0 (and vice-versa) for every 0 we also reduce a 1
For every 2 we also reduce a  9 (and vice- versa) for every 9 we also reduce a 2
For every 3 we also reduce a  8 (and vice- versa) for every 8 we also reduce a 3
For every 4 we also reduce a  7 (and vice- versa) for every 7 we also reduce a 4
For every 5 we also reduce a  6 (and vice- versa) for every 6 we also reduce a 5

To simplify the above table:
1  2  3  4  5
0  9  8  7  6

Example: You wish to find six numbers to play from spin number 8.  
Spin numbers: 5.   0.   30.   23.   8.   11.   35.  
First reduce 11 and 20
Next reduce 8  and 3
Next reduce 23 and 28
Next reduce 30 and 21.  
You now have your six numbers to play from spin number 8.   22.   29.   24.   27.   25.   26.  

Example: You wish to find six numbers to play from spin number 11.  
Spin numbers: 12.   30.   0.   5.   21.   25.   35.   36.   22.   28.  
First reduce 28 and 23
Next reduce 22 and 29
You now have your six numbers to play from spin number 11.   21.   30.   24.   27.   25.   26.  

Example: You wish to find six numbers to play from spin number 12:
Spin numbers: 29.   4.   29.   0.   6.   2.   3.   28.   16.   18.   22.  
First reduce 22 and 29
Next reduce 18 and 13
Next reduce 16 and 15
You now have your six numbers to play from spin number 12:
11.   20.   12.   19.   14.   17.  

10).    Clear Profit per Hit for single unit bets.    
Spin number   Profit
1                      30
2                       24
3                       18
4                       12
5                        6
6 break -even
No-hit a loss of 36 units.  

11).    The one exception to the above figures is.  
When playing the first set of numbers and one of the selections is 0 or 10.  
You play 7 numbers instead of 6

Example: You wish to play 6 numbers from spin number 5.  
Spin numbers: 20.   19.   8.   5.  
First reduce 5 and 6
Next reduce 8 and 3
You now have seven numbers to play 1.   0.   10.   2.   9.   4.   7.    for the next five spins.  
For a Clear profit per Hit for this situation.  

Spin number Profit
1                        29
2                        22
3                        15
4                         8
5                         1
No-Hit a loss of  35 units

12).    As you can see it is a simple task to find the numbers to bet.  

Using this simple set of digits:
1 2 3 4 5
0 9 8 7 6
You count back from the last number spun, or from the last number to hit.  
Proceed to reduce using the formula provided.  
Practice with a set of spins.  
It soon becomes very easy to instantly identify the six numbers to bet.  

13).    Bank: and notes:
I would recommend a minimum bankroll of $200.  
The first target would be to double ones bank.  
When that is achieved, pause.  
Resume some time after with a similar target,
Again, with a bank of $200, aim to double it.  
Set your own limits and stick to them.  
I will not attempt to explain for now why I believe it works;
I believe it exploits a mathematical anomaly.  

To refresh:
Always count back from the number just spun; or the number that just hit.  
Reduce the sets of numbers as described and as soon as one as six remaining
Play those numbers.  
Play until one hits.  
Play for a maximum of six spins.  
As soon as one hits; discard that set and proceed to get another six.  
Observe the record of spins following.    The ones highlighted are hits.  
17.   22.   10.   25.   24.   21.   17.   23.   22 .   20.   2.   1.   34.   35.   0.   14.   36.   5.   0.   20.   30.   23.   8.   11.   35.   2 7.  

You wish to bet on spin number 5.  
Counting back from and including spin 4.  
25.    reduce 25 and 26
10.    reduce 10 and 0 and 5 and 6
22.    reduce  22 and 29.  
We now have the numbers to bet from spin number 5:
21.   30.   23.   28.   24.   27.  

Spin number 5    24 HIT
You want 6 numbers to bet from spin 6.  
Counting back from and including spin 5.  
24.    reduce 24 and 27
25.    reduce 25 and 26
You now have the six numbers to bet spin 6 onwards.    
21.   30.   22.   29.   23.   28.  

Spin number 6  21 HIT
You want 6 new numbers to bet from spin 7 on.    
Counting back from and including spin 6.  
21 reduce 21 and 30
24 reduce 24 and 27
We now have six numbers to take from spin 7 on:
22.   29.   23.   28.   25.   26.  

Spin number 8  23 HIT
You want 6 new numbers to bet from spin 9 on.  
Counting back from and including spin 8.  
23 reduce 23 and 28
17 reduce 17 and 14
21 reduce 21 and 30
We now have six numbers to bet frome spin 8 on:
21.   30.   22.   29.   25.   26.  

Spin number 9 22 HIT
You want 6 new numbers to bet from spin 10 on:
Counting back from and including spin number 9:
22 reduce 22 and 29
23 reduce 23 and 28
We now have six numbers to take from spin 10 on:
21.   30.   24.   27.   25.   26.  

Spin number 15 0 LOSS
You want 6 new numbers to bet from spin 16 on:
Counting back from and including spin number 14.  
(ignore all the numbers 31.   32.   33.   34.   35.   36.   )
0 reduce 1 and 10
2 reduce 2 and 9
We now have the six numbers to take from spin 15 on:
3.   8.   4.   7.   5.   6.  

Spin number 18 5 HIT
You want 6 new numbers to bet from spin 19 on:
Counting back from and including spin 18:
5 reduce 5 and 6
(ignore all the numbers 31.   32.   33.   34.   35.   36.   )
14 reduce 14 and 17
0 reduce 0 and 1 and 10
We now have the numbers to take from spin 19 on:
2.   9.   3.   8.   4.   7.  

Spin number 24 8 HIT
You now want 6 new numbers to bet from spin 25 on:
Counting back from and including spin 24:
8 reduce 8 and 3
23 reduce 23 and 28
30 reduce 30 and 21
We now have the numbers to take from spin 25 on:
22.   29.   24.   27.   25.   26.  

Spin number 28 27 HIT.    

[GLC]

I agree with Red.  I have read this system numerous times, and have never been able to understand exactly how the author reduces the numbers.  If anyone knows what the heck he's talking about, please help.

Thanks,

G.

[chovek69]

I think I got it.   Let me try to explain it with my poor English. 
As he points first, we divide the layout in 3 10-number sets:  0-10, 11-20, 21-30 excluding numbers from 31 to 36. 

Then we consider cadences (numbers that end with identical digit)
0,10, 20, 30
1, 11, 21, 31 etc. 

Then we go through the sequence of numbers that just has been spun in order to cross off numbers from each set.   We look for the first set in which there has been exactly six numbers left.    We use the following rules:

When there is a previous number ending in 0 we cross off that number and any other numbers ending in 0 and 1 from the same set.   And vice versa if there is number ending in 1 we cross off any number ending in 1 and 0 from the same set
the same rule applies accordingly to:
previous number ending in 2, we cross off numbers ending in 2 and 9 from the same set;
3 <-> 8,
4 <-> 7
5 <-> 6

Example: #17 is a previous number.   We consider the set 11-20 and we cross off numbers 17, 14.   There are now 8 numbers left in this set.   We need to cross off two more numbers in order this set to qualify. 

Example: #10 is a previous number.   We cross off 0, 1, 10.   There are now 7 numbers left in this set (2, 3 , 4, 5, 6, 7, 8, 9) and we play them for the next 6 spins according to exception 11). 

Now look at his examples.   I hope this helps a little. 

P. S the confusion comes from the word "reduce" the author uses.  Change it with discard and all become clear.

[Red Nickels]

thank you chovek, I think your explanation will help a lot.   will try and follow and test it just for the heck of it.   I wonder if there is any logical rationale to this system?

[chovek69]

I think I got it.    Let me try to explain it with my poor English.  
As he points first, we divide the layout in 3 10-number sets:  0-10, 11-20, 21-30 excluding numbers from 31 to 36.  

Then we consider cadences (numbers that end with identical digit)
0,10, 20, 30
1, 11, 21, 31 etc.  

Then we go through the sequence of numbers that just has been spun in order to cross off numbers from each set.    We look for the first set in which there has been exactly six numbers left.     We use the following rules:

When there is a previous number ending in 0 we cross off that number and any other numbers ending in 0 and 1 from the same set.    And vice versa if there is number ending in 1 we cross off any number ending in 1 and 0 from the same set
the same rule applies accordingly to:
previous number ending in 2, we cross off numbers ending in 2 and 9 from the same set;
3 <-> 8,
4 <-> 7
5 <-> 6

Example: #17 is a previous number.    We consider the set 11-20 and we cross off numbers 17, 14.    There are now 8 numbers left in this set.    We need to cross off two more numbers in order this set to qualify.  

Example: #10 is a previous number.    We cross off 0, 1, 10.    There are now 8 numbers left in this set (2, 3 , 4, 5, 6, 7, 8, 9).   We need to cross off one more number to play them for according to exception 11).

Now look at his examples.    I hope this helps a little.  

P.  S the confusion comes from the word "reduce" the author uses.   Change it with discard and all become clear. 

[Red Nickels]

I am still having trouble following this system.   below are 75 consecutive spins from a real double zeroe wheel.   chovek (or anyone) is it possible you could show where and what the betting opportunities would be here as per this system and if they won or not?  thanks so much.

33
21
15
24
35
28
11
32
4
3
21
35
17
8
2
26
11
28
15
14
4
14
27
25
22
6
3
12
31
30
24
28
9
25
17
11
22
8
1
25
27
14
5
0
18
16
16
1
4
21
22
36
4
6
5
35
22
33
2
25
20
21
16
9
16
25
9
36
4
9
25
10
12
16
6

[Hermes]

I remember, I gave this confusing puzzle system to the old Steve's forum to clear up. Nobody answered in 3 months and I am still in clouds! I almost reduced my brain to walnut and still didn't find the answer.
Create Holy Grail is easier than explain that system.
hermes

 

[Red Nickels]

in above sequence of numbers I started out crossing off the 33 and 28, then the 24 and 17, then the 26 and 15, and then I got lost what to do next and where the bet is.  .  . 

[ScoobyDoo]

Maybe we need to get Victor or TwoCatSam to look at this. They are usually pretty good at figuring things out.

Scooby Doo

[Red Nickels]

chovek gets it.   as I understand it we want to eliminate four of the numbers in any number group and then bet on the other six numbers in the group.   my question is where is the first betting opportunity where you can do this in the above outcomes?

[Compa]

There are several ways to play this concept in a much simpler fashion. I will present a Matrix below that does Exactly the same but much more easy;)

Here's my Favourite Global Pies Constellations. The way I belive they fall consistently:

So You want to play each of the 3 Matrix separatly/simultaneously Like this:

Example:

Outcome:

4
17
16

x                 closing vertical line of 4 numbers
32 15 19
4   21  2  x   closing horisontal line of 3 numbers 
31 14  9 
22 18 29

     x           closing vertical line of 4 numbers
25 17 34 x  closing horisontal line of 3 numbers..
6  27 13
7  28 12
35 3  26

          x     closing vertical line of 4 numbers
36 11 30
8  23  10
5  24  16  x closing horisontal line of 3 numbers..
33 1   20

You all see where to put the marks that "Closes" the Lines of numbers.
Repeat this procedure until You have 3-12 numbers "Open" for play. Then bet.

Very simple. This is also refered to as the "Raindrop"-Method.

Cheers!

/Compa

[Red Nickels]

thanks.      unfortunately I have no idea what above is about.      I still want to see how the system does on the sequence of numbers I showed.    I will work on it.  .  . 

[Compa]

Good Luck

[2BobBet]

Hello Red
I'm going to have a go at explaining this method,I will work on the numbers that you posted ;

Set out 3 tables like the author ;

0-1-2-3         11-12-13         21-22-23
4-5-6-7         14-15-16         24-25-26
8-9-10           17-18-19        27-28-29
                     20                    30

Ok now every time a number is spun in those tables we cross it off with its corresponding partner.


Partners Table

For every 0 we cross off the 1,for every 1 we cross off the 0
For every 2 we cross off the 9,for every 9 we cross off the 2
For every 3 we cross off the 8,for every 8 we cross off the3
For every 4 we cross off the 7,for every 7 we cross off the 4
For every 5 we cross off the 6,for every 6 we cross off the 5


The above table applies ONLY to the cadences of the spun numbers
Example    33 cadence is 3

                  26 cadence is 6

                   13 cadence is 3
       
                  7 cadence is  7
                                 

[2BobBet]

Sorry Red,

Now to your numbers,

33 we ignore all numbers over 30
21     Tables   21-22-23
                      24-25-26
                      27-28-29
                       30    cross out number 21 and its partner in the cadence table 1=0,so that's
                                the number 30 as the only number in this table with a 0
15    Tables    11-12-13
                       14-15-16
                       17-18-19
                         20    cross out the number 15 and its partner in the cadence table5=6,so
                                  that's the number 16 as the only number in this table with a 6
24   Tables      21-22-23
                       24-25-26
                       27-28-29
                        30     cross out the number 24 and its partner in the cadence table 4=7,so
                                  that's the number 27 as the only number in this table with a 7
Now we have our betting opportunity as the 21 to 30 table has 4 numbers crossed off
35 L bet 22-23-25-26-28-29
28W