Start with the following 4 spin combinations that run vertically.
(Forget zero).
Spin 1 - 1 1 1 2 2 2 3 3 3
Spin 2 - 1 2 3 1 2 3 1 2 3
Spin 3 - 2 3 1 3 1 2 1 2 3
Spin 4 - 2 3 1 1 2 3 3 1 2
In 4 spins, 1 column must hit minimum of 3 times....
This gives us 4 possibilities of which 1 is guaranteed to happen...
1. Spins 1,2,3
2. Spins 2,3,4
3. Spins 1,3,4
4. Spins 1 2,4
Lets say we choose to play the combination
1,2,4
First let 2 spins pass
For example...
1. Dozen 3
2. Dozen 1
To bet for combination 1,2,4 is to bet against combination 1,2,3 forming.
Now look for the column that cointains dozens "3 and 1" in that order in the first 2 rows...
It indicates to bet against dozen 1 so we bet the remaining 2 dozens
If we win, we parlay our initial 2 units onto the dozen indicated on the 4th spin to form the 1,2,4 combination
Result
If we lose on the first bet result = -2
If we win on the first bet
but lose on the parlay, result = -2
If we win on the "1,2,4 combination"
Result = +7
Simple as 1,2,3,4.
What is determining first decision?
Hey blue what is determining the first decision?
Do you mean, the option that i chose?
I chose that option for the style of play...
Bet 2, if win, parlay the initial 2 units plus the 1 unit picked up for payout of 9 =potential profit of 7 units
What i'm wondering is if these 4 options are as likely as each other???
1. -2
2. -2
3. -2
4. +7
Can anyone help with that???
Cheers
Quote from: mickavelli on Apr 21, 10:32 PM 2022Can anyone help with that???
Can't help there, sorry.
O0 ping
This looks like the 9 Block system that Scepticus plays.
Check out Scepticus' posts on roulettelife forum. Hope that helps.