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Using the casino's money for double dozens

Started by GLC, Jan 09, 12:29 AM 2012

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GLC

You can read my "flatbet parlay progression" under this same section.  It's for the even money bets.  Roulette, Blackjack, bacarrat, craps.

This is the double dozen flatbet parlay progression.  It's played almost the exact same way.

We could play with 1-1 as our base bet, but it's a little slow.  I like to play with 2-2 as a base bet.

All we do is bet 2-2 (or 1-1) after each loss.  We only increase our bet size after a win and we never bet more than 2-2 (1-1) with our own money.  To bet larger amounts, we have to have won some of the casino's money.

Here's how to play.  Bet 2-2 on the 2nd dozen and the last to hit of the 1st or 3rd dozen.  So the bet selection is easy.  Bet the same 2 dozens on a win and on a loss bet the 2nd dozen and the dozen you were not betting on last.  If a zero causes the loss, bet the same 2 dozens again.

If we win betting 2-2 we will win 2 units so now we have 6 units, our next bet is 6/2=3-3.  A win on the 3-3 gives us 9 units for our next bet. 

Since we only bet equal amounts and 9 divided by 2 gives us an unequal amount, we only bet 4-4.  The odd unit is a bonus for our profits.

If we win betting 4-4 we will have 12 units for our next bet.  12/2=6 so we bet 6-6.

If we win betting 6-6 we will have 18 units for our next bet.  18/2=9 so we bet 9-9.

If we win betting 9-9 we will have 27 units for our next bet.  27/2=13.5 so we bet 13-13 and put the extra unit in our profits.

If we win betting 13-13 we will have 39 units, 4 of which are our original bets leaving us with 35 units profit.  Oh yeah, plus the extra units from the 3-3 win and the 9-9 win gives us +37 units for our 4 units to start with.

This represents 6 wins in a row which isn't that uncommon when playing double dozens.  We have to do this once every 9 losses to come out +1.

Here's a suggested way to play.  Let's say you start betting 2-2 and win your 1st bet.  Put those 2 units in your profits pocket, so to speak.  As long as you win before your 1st loss you will put the winnings with your profits.  As long as you win the next bet after reaching a new high bank, you will put those won units in profits.

Let's say you lose 3 times in a row betting 2-2.  That puts us 12 units in the hole.  Our next bet is 2-2 since our last bet was a loss.  If we win we will have 6 and bet 3-3 next.  If we win we will have 9 and bet 4-4 next.  If we win we will have 13 which is +1 over the 12 units we were in the hole.  The 1 unit goes into profits and our next bet is 2-2.

If we lose our 1st bet of 2-2 and win our next bet of 2-2 we will be down 2 units and our next bet will be 6/2=3 so 3-3 and if we win we will bet 5-4=+1 which goes into profits.

Let's say we have lost -45 units and we start winning 2-2; 3-3; 4-4; 6-6; 9-9; 13-13.  That's our 6 wins in a row and we're still down 8 units.  If we are playing for 6 wins in a row, we would reduce our units in the hole 45-37=8 and start over with a 2-2 bet.  This is the only time we don't bet more after a win, if it's our 6th win in a row.

Since we are -8 all we need is to win 2-2; 3-3; 4-4 to reach a new high and put the wins in profits. 

Simple!

Here's some suggestions.  Buy-in for 100 units and (be prepared to lose them occassionally.)  Start playing and whenever you win any profits, keep them completely separate from your 100 units.  That means that if you lose 25 each 4 unit bets (2-2) bets eventually, you won't have lost 100 units, you will have lost 100 less all won units.  Another way to think of this is to add all wins to the 100 units, but you can never drop lower than your highest point minus 100 units.  So, if you had reach 125 units and then lost 100 units, you would have really only lost 75 units because you would still have 25 units after losing 100 units and since you started with just 100 units, 100-75=25.  So you only lost 75 units.

Play until you reach your win target.  I suggest 50 units is a reasonable win target.

Give it a try and see what you think.

With this method, you can always control exactly how much you are willing to lose.  That's much better than getting caught up in a steep progression with no end in sight.

Cheers,

GLC
In my case it doesn't matter.  I'm both!

GLC

For those who wish to play using 1-1 as the base bet, here's the steps.  we start betting 1-1 on the first win we will have 3 units.  Not enough to increase our wager on both dozens so our next bet will also be 1-1.

If we win our 2nd 1-1 we will be up 2 units plus our 2 for 4/2=2.  Bet 2-2 on 3rd bet.

If we win our 3rd bet at 2-2 we will have 6 units divided by 2=3.  Bet 3-3 on the 4th bet.

If we win our 4th bet at 3-3 we will have 9 units divided by 2=4.5.  Bet 4-4 on the 5th bet.

If we win our 5th bet at 4-4 we will have 12 units divided by 2=6.  Bet 6-6 on the  6th bet.

If we win our 6th bet at 6-6 we will have 18 units less our original 2 units plus the extra unit we accumulated between 3-3 and 4-4 for a total of +17 units.

Please note that this is just a little less return for the investment as playing with 2-2.

2-2 = +37 after 6 parlay wins.  37/4=9.25
1-1 = +17 after 6 parlay wins.  17/2=8.5

That's not as much as I thought, so I don't really see any reason to play with 2-2 as a base bet.
In my case it doesn't matter.  I'm both!

Gizmotron

This is odd. I was playing around with this idea a few days before you posted it. There are several ways of looking at it.  Getting 15 wins in a row is common in a session. Getting all 15 in a row without one loss is fare less common.

This is even more common. Most of the times when I first arrive and start betting I don't have a full rhythm for the current trend in these bets. Almost all the time I open with a straight down lose every bet streak. So imagine creating  a positive progression for 4 to 6 in a row for single doz/clm bets.

I also have this version where you take off a little as you go:

6  -  6  - 18
9  -  9  - 27  (3)
12 - 12 - 36  (6)
15 - 15 - 45  (5)
20 - 20 - 60  (20)
20 - 20 - 60 --- total=94 -12 = net 82
I am the living proof that Roulette can be beat every time I set out to beat it.

Gizmotron

Try this when a dozen or a column repeats a lot:

6 becomes 18 - subtract (3)
15 becomes 45 - subtract (15)
30 becomes 90 - subtract (30)
60 becomes 180 - net 222
I am the living proof that Roulette can be beat every time I set out to beat it.

Gizmotron

GLC, here is an idea that might work. It's a different way to select the bets. You take an old sequence of spins  with the idea that a sequence will likely not have many sections that repeat. In other words spin one of the old sequence will not be the same as spin one of your new play. Spin two of the old sequence will not be the same as spin two of the new session, etc...
I am the living proof that Roulette can be beat every time I set out to beat it.

GLC

Giz,

Some good ideas.  Thanks for the suggestions.

Give me a while to digest them.  I'm a little busy at work and my home computer is down for the time being.

Cheers,

GLC
In my case it doesn't matter.  I'm both!

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