Skip Streak System - Playing one number

[ego]

Skip Streak System by Apache:

First I want tell I build this system using Ion Saliu concepts :
Skip, Streak, and Median Value.

Example :

Roulette Number: 6
Hits -> 24 times
Skips -> 51 43 104 1 2 29 37 77 79 15 130 15 12 7 11 131 11 129 8 16 20 14 21 12

* Sorted Skips: 1 2 7 8 11 11 12 12 14 15 15 16 20 21 29 37 43 51 77 79 104 129 130 131

* Median Skip: 16

So number 6 hit 24 times.
The first row - called Skips - show ( to the right to left) the skips of number 6. Number 6 show. After 12 spins, show again, after 21 spins show again, after 14 spins number 6 show again etc. The last three skips of number 6 are 104, 43, 51.


The second row - called - Sorted Skips show all the skips for a particular number in ascending order.

The three row called - Median Skip - show the median value of the sorted skips. The median is the middle value of a string of numbers. In this example the median value of skips is 16.
It should not be confused with the average.
So the Median Value is the middle value in a string of values.

Therefore 50% of the values are within the median or less, and 50% are within the median or more. In my example of number 6, the skip median is 16. That mean that 50% of the time number 6 hits within a skip of 16 or less.

Now if in the string of skips of number 6 I mark :

with sign (+) I mark if the skip is greater than median value of skips
with sign (-) I mark if the skip is small than median value of skips
with sign (=) I mark if the skip is equal with median value of skips

I obtain this :

Code:

51  43  104  1  2  29  37  77  79  15  130  15  12  7  11  131  11  129  8  16  20  14  21  12

+   +    +  -  -   +   +   +   +   -    +   -   -  -   -    +   -    -  -   =   -   -   -   -



1. THE STRATEGY :

We bet on the numbers which have a 3 consecutive streak of skips greater than the median value of skips. ( That mean three consecutive + )

In our example number 6 is qualified because the last three skips ( consecutive ) are 104, 43, 51. We have + + + ( three consecutive value of skips, greater than median value of skips. 16

(104 > 16) (43 > 16) (51 > 16)

St0rm0r, is possible to code this system with this options : ?


1.Bet on numbers with encounter 3 consecutive signs +
2.Bet on numbers with encounter 4 consecutive signs + (tight bettors)
3.Bet on numbers until hit.
4.Bet on numbers for 37 spins
5.Bet on numbers for a number of spins equal with the median value of skips. ( In this example we bet number 6 for 16 spins)

Money managament : Flat bet.

Thank you in advance.


P.S. I use this strategy with success in Bookmakers Lottery. (The Irish, German, Spanish,49s lotteryes where I can bet one number )

[ego]

I am testing this method and compare it with RWD.
I pick the most hitting number for 600 trails and track them for "median value".
Then i pick next day with same wheel and check LW-Registry.
I have just started the test and will continue.



2 7 8 9 10 13 14 15 15 17 21 22 22 25 27 28 30 36 41 42 43 49 101
(22 MEDIAN)
Nr 7
WWLLLWLLLWLWWWWLW

0 0 4 5 5 7 7 8 8 16 17 17 17 36 37 39 49 58 58 58 75 95
(17 MEDIAN)
Nr 12
LLLWLLLWLLWLWLLLLL

0 0 4 5 5 8 8 8 12 15 17 27 27 28 28 28 33 36 44 53 55 57 89
( 27 MEDIAN)
Nr 2
WLLLLLLLLL

0 0 2 2 4 4 5 6 7 10 10 12 16 24 26 35 35 53 54 58 66 68 97
(12 MEDIAN)
Nr 16
LLLLLLWLWLLWL

[ego]

I aks my self many questions.
Should i track a wheel for 1000 trails and then pick median value.
Only play skips around 18 and below flat betting.
Or else progression.

Come with suggestions, because i will buy this to be coded.
But not sure what inforamtion i want with the output file.
I do know it should check all top numbers and skip numbers with low values (hit ratio)