Warm ones

[superman]

12,8,15,13,2,35,1,9,14,10,6,6,6,33,4,12,20,32,23,11,33,33,25,18,10,17,29,29,17
,4,29,15,10,35,31,6,26,7,16,25,12,3,20,16,3,28,30,25,32

ok still as clear as mud, so to me from your example, the 12 numbers in red already has numbers with 2 hits in it, looking at the green numbers, what makes your decision for picking them, all I can see is they are 12 numbers that do not appear in the 1st 12 (red ones) is that it?

[chrisbis]

I was confused Dot Com too Neal. 


BTW, I already told him the Usual price for a bot.
Its a standard rate of
                    "THIRTY, MILLION DOLLARS" .................right?


Signed..................buddie Dot Com. 


Stelios is good for it it informed me!

[xxlakis]

Well i'll try to explain it even better i hope.Track the last 24 unique numbers and 12 unique numbers spawn.Exclude the 12 last ones  from the 24 last.The 12 numbers left are the group i play.I just came up with a variation and it's going really well so far.Yesterday i managed to survive from a really hard event when 21 unique numbers came up one after the other with no repeats!If i would play it with my usual 12 step progression i would lose as i would have 14 loses in the raw.


Hey chris our deal stands of course.If you have the time to code 2 methods that's fine by me.A deal is always a deal and i don't like let people down.

[Drazen]

Well isnt this same as Flatino-s roller coaster? But with different progression?

Regards
                  Drazen

[xxlakis]

Yeah it is.Now i divide the last 24 numbers to 2 groups and i play them together with a progression
-2->win,+1->loss and it works good.

[Drazen]

Can you give example in play? How do you divide them? i mean on what is based your dividing?
Regards
             Drazen