"Hang Time", My Last Thread

[Norman Bates]

single 0 roulette
2 chips on the first 12
1 chip on the second 12
3 chips on the third 12
4 chips on the first column of 12
2 chips on the second column of 12
6 chips on the third column of 12
3 chips on the numbers 2,5,7,10
4 chips on the numbers 15,19,21. 24
2 chips on the numbers 25,28,31,33
I would suggest a buy-in of 1200 chips.

[Twisteruk]

A:: shame, bye.

[Norman Bates]

You didn't even try it, did you?  I think this is an astonishing break through myself, and you didn't even try it.  Pitty...

[GLC]

Single 0 roulette
2 chips on the first 12
1 chip on the second 12
3 chips on the third 12
4 chips on the first column of 12
2 chips on the second column of 12
6 chips on the third column of 12
3 chips on the numbers 2,5,7,10
4 chips on the numbers 15,19,21. 24
2 chips on the numbers 25,28,31,33
I would suggest a buy-in of 1200 chips.

For anyone betting this way, please, never bet all 3 dozens or all 3 columns at the same time.  With this bet, it makes more sense to bet 1 unit on doz 1, 0 units on doz 2 and 2 units on doz 3.  This saves 3 units if the 0 hits.

On the columns bet 2 units on col 1, 0 units on col 2 and 4 units on col 3.  This saves 6 units if the 0 hits.

Between the two bets, you will save 9 units everytime a zero hits and the payoff is exactly the same.  Work out the math if you don't believe me.

No sense throwing away hard earned $$$$.

By the way, I have not examined this bet to see if it has merit or not so by making the above suggestion, I'm not endorsing this betting method  whether you bet all three doz and col or not.

GLC

[esoito]

" I would suggest a buy-in of 1200 chips. "  

What it is to have more money than cents...

[Norman Bates]

Very well

[Norman Bates]

Another thing that I've found out about this strategy is even if you are playing red. Place the chips the same way as you did with the singles, and just use the same 1250 dollar buy-in.

[Norman Bates]

ER

2 chips on the first 12
1chip on the second twelve
3 chips on the third 12
4 chips on the first column of 12
2 chips on the second column of 12
6 chips on the third column of 12
3 chips on the numbers 2,5,7,10
4 chips on the numbers 15,19,21.24
2 chips on the numbers 25,28,31,33

AR

Bet the same as the ER strategy, except this time you'll add 1 blue chip on the 0, 00 split, and all the other chips must be red 5 dollar chips.  Sorry.

These strategies are all based on combination's that the payoffs are honed to.  These two are based on a 54 chip betting system.  If you add 36, and 18, (the amount of chips won on a straight up bet with a split on the side). it comes to our 54 chip count.  You may notice that these number that I just gave you don't add up to 54 chips.  That's because I use chips on the outside bets that could be removed an still pay off the same way.  For instance, instead of betting 2 chips on the first 12 I would only bet one, and maintain this procedure to all of the outside bets cutting them all by 1 chip on the sections of 12, and then move on to betting half of the specified amount for the columns.  Making the first column 2 chips instead of 4, and so on.  I use these extra chips on the layout, because it seems to work a lot better that way.  I really don't know why. Maybe it's dumb luck.  I don't know, but it does seem to work better that way.  OK?  


One more thing, if you are playing ER I would suggest a buy-in of 1,250 dollars.  But, if you are playing red chips, place the chips the same way as you did with the singles, and use the same 1,250 dollar bankroll. As for AR, you have to playing red chips only with 1 single blue chip on 0, 00 split, and use a buy in of around 2,000 dollars instead of the 1,250 we talked about earlier.  For ER maintain the same 1,250 dollar buy in for both denominations.