I made some game to test repeaters of dozen.
If we check old spins, we will notice the dozens
comes out in different frequencies, what we do not
know is which dozen will repeat often in the near
spins.
I have made many trials betting the most frequent
repeating dozen by looking to the last spins.
This work just sometimes, and are not at all sure.
So I got an idea, which should by the play it self
accumulate bets, which favour the most frequent
dozen.
We start with placing one unit on the street
belonging to the last shown number.
If we win do the same bet again.
If a loss,we put a chip on the street belonging
to the number, providing it is not the same
dozen, is such case we put on top of the
street allready there.
We just play one street in each dozen.
So we play until a hit, adding a chip
in every loss at the street in the dozen
belonging to the shown number, if not bet before
in that dozen, otherwise we add to the
street already bet.
If we win, and are on new high, we start
over with one chip belonging to the last shown number.
If we win, but still not are on new high, we
reduce the bet. The dozen with the lowest bet,
we take away, and reduce the two other the same amount.
When the empty dozen got a hit a new street will
start at the number shown, in this way the bets rotate,
to numbers may repeat.
On the play today, it was very successful, 500
chips in not so many spins.
If a dozen repeats much, a hit on the highest pile,
is very likely, and it grows because of the repeating
dozen.
If an other dozen start repeater, that dozen will
probably hit a bet, and then we reduce the bets,
in the former repeating dozen,in case we are not on new high.
This goes automatic by the rules.
I remember I have tested a similar method, using
two streets in each dozen, but found it not so
useful, too many hits not reaching new high.