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Resources & Downloads => Mathematics => Topic started by: Big EZ on Mar 23, 09:43 AM 2013

Title: Even chance runs
Post by: Big EZ on Mar 23, 09:43 AM 2013
What are the odds/probability that you will see back to back runs of 4,5,6, and 7?




RRRRBBBB


RRRRRBBBBB


RRRRRRBBBBBB


RRRRRRRBBBBBBB


Can someone please lead me in the right direction
Title: Re: Even chance runs
Post by: GLC on Mar 23, 04:11 PM 2013
Reminds me a little of the following post:
link:://:.rouletteforum.cc/index.php?topic=11987.msg104646#msg104646 (link:://:.rouletteforum.cc/index.php?topic=11987.msg104646#msg104646)

GLC
Title: Re: Even chance runs
Post by: nitrix on Mar 23, 04:11 PM 2013
Exactly the same as having:

BBBBBB
or
RRRRRR.

That is (1/2)^6 chances of losing the entire series.

In 1M spins, you can expect the longest series to be about 29 repeat long.
If I remember my testings correctly.

Good luck.
Title: Re: Even chance runs
Post by: Big EZ on Mar 23, 04:23 PM 2013
Nitrix,


so are you saying the chance of back to back 6 in a row is going to be


((1/2)^6(1/2)^6) = 0.00024414062
Title: Re: Even chance runs
Post by: maestro on Mar 23, 07:04 PM 2013
big ez i do not know if helps but i have seen 11 blacks then 0 and 13 reds after
Title: Re: Even chance runs
Post by: ego on Mar 24, 07:43 AM 2013
 
That is a pretty good bet selection ...
First you bet three times against one color.
If you lose you will have RRRR then you wait for the next otucome to show, red or black.
Lets say R then you again play three times against it and if you lose then you have RRRRRRRR and now wait for the next outcome.
Lets say it is B then you bet three times and if you lose you get RRRRRRRRBBBB and it looks like any common pattern, but it is not ...
.
If you take the principal of 1/3 with 8 patterns you just got this sequence where one side out of 8 repeat 4 times in a row ...

RRB
RRB
RRB
RRB

Following that simple algorithm you will bet against that any of does 8 patterns will repeat for 4 times in a row.
Pretty cool and could be any depending on your betting sequences ...
Title: Re: Even chance runs
Post by: nitrix on Mar 29, 09:36 AM 2013
Ez, it's in relation to the big "1".

For example, (1/2) * (1/2) will give you 0.25, which means, you have 1 / 0.25 = 4.
That event will happen once every 4 spins (statistically).

In our case:
1 / 0.00024414062 = 4096.

You have 1 chance on 4096 for the event to happen.

For a simpler solution, if the numerator is always 1, you can simply multiply the denominators together: 2*2*2*2*2 = 32.  One chance on 32 to lose a color bet 5 times.

The reason I'm doing it with this notation is to accommodate bigger fractions, like 2/3, 5/6, 35/36, that some people play.
Hope that helps.