With this idea we can go on forever and ever.
Just remember to have a break now and then :)
Continue the experiment another day
and ignore all the spins you missed!
An endless number of lines are being filled in.
There are twelve spaces or columns - one for each street in area 1-36.
Within one street the probability that the LATEST number there is coming again is exactly 1/3.
And obviously there are twelve streets. 12/3 = 4. There is nothing like stating the obvious!
SO if the Goddess of Fortune behaves as expected,
we should expect to see FOUR repeats both here and there (line 2, 3, 4, 5 etc.).
And there are THREE DOZENS, I assure you. If the Goddess of Fortune behaves as expected,
we should expect to see at least TWO repeats within one dozen or other. Within one line.
When one number from the previous line has reappeared, we beg for another repeat
within the same dozen and the same line.
An example:
1 4 8 10 15 17 23 26 35
1 7 11 14 25 36.
Obviously #1 is a repeat (2nd line, 1st dozen). Bet #4.
Have fun forever and a day!
Read 256 times and not one reply.
Dane,
Thanks for the idea. One thing that has me puzzled is where you say "we should expect to see four repeats both here and there lines 1,2,3,3,5 etc"
Is there a limit on how many lines you would follow this for?
Sorry if this is a stupid question......it's still early!
Cheers
Jon
Quote from: TwoCatSam on Jan 26, 10:38 PM 2015
Read 256 times and not one reply.
NEVERTHELESS
I´ll tell you what happened in the meantime:
I found out that a more limited bet selection might be better.
If we expect four repeats (from the previous line as explained)
then a pattern like this might appear somewhere on the line: R00R (R = Repeat. 0 = Not a repeat).
Besides, it is not a coincidence that I the same day
also started the topic titled "THE ABSENT MINDED WINNER".
Why not combine those two methods??????
I did that :)
And after thousands of spins (in fun mode) I am not disappointed!
to jon: no limits no limits no limits :)
I worded the question badly. I understand that it's perpetual but I wasn't sure if we were looking for four repeats over x number of lines or two repeats over the next line.
I will now have a look at the other thread and see how it works combining both ideas.
Cheers
Jon
Quote from: jon on Jan 27, 03:28 AM 2015
I worded the question badly. I understand that it's perpetual but I wasn't sure if we were looking for four repeats over x number of lines or two repeats over the next line.
I will now have a look at the other thread and see how it works combining both ideas.
Cheers
Jon
Good luck! I notice that you are a new member! Welcome!
It might not be a good idea to overflow you with more suggestions;
but here is one more: Begging for a
FIFTH repeat on the same line might be worth trying!
Maybe its me with my stupid head on but I don't understand this at all.
Could somebody please exp-lane please (So dummies can understand) Thanks Guys
An example. Begging for a FIFTH repeat on the same line.
2 4 8 10 15 17 20 22 25 30 31 34
2 5 7 10 13 16 20 23 26 28 33 35
2 5 8 10 14 20 31
Structured in twelve streets!
Please notice the repeats in the second line: 2, 10, 20. Three repeats there.
Looking at line 2 & 3 we find 2, 5, 10 & 20 in both lines. FOUR REPEATS.
There is still room for a FIFTH repeat in line 3.
Bet 16, 23, 26, 28 and 35.
Thanks :)
Dane, I'm trying to get my brain around this and I'm tentatively getting some good results but I have ran into a few questions.
First, I'm seeing 3 and 4 in a row of the qualifying repeater. For instance, if we have 2, 7, and 11 in the first dozen, followed by another 2, that qualifies 7 and 11. Are you also betting the 2?
Next, what if in our training we get a large concentration in one of the 4 lines within a dozen before the first repeat. If we have 5 results in the first line, 1 in the 2nd, 1 in the 3rd, and 0 in the 4th line of a dozen when we get a repeat on our 6th result within the first line, do we make any bets? None of the other three lines would have a candidate "in the same line" as you described it. Would we have to continue to track until any of the other numbers finally reached their 5th results before we could bet on them?
Quote from: Colbster on Jan 27, 04:04 PM 2015
Dane, I'm trying to get my brain around this and I'm tentatively getting some good results but I have ran into a few questions.
First, I'm seeing 3 and 4 in a row of the qualifying repeater. For instance, if we have 2, 7, and 11 in the first dozen, followed by another 2, that qualifies 7 and 11. Are you also betting the 2?
Next, what if in our training we get a large concentration in one of the 4 lines within a dozen before the first repeat. If we have 5 results in the first line, 1 in the 2nd, 1 in the 3rd, and 0 in the 4th line of a dozen when we get a repeat on our 6th result within the first line, do we make any bets? None of the other three lines would have a candidate "in the same line" as you described it. Would we have to continue to track until any of the other numbers finally reached their 5th results before we could bet on them?
Hi Colbster,
I have suggested more versions.
Choosing the earliest one (mentioning the dozens), we´ll hit a number in most lines.
First,
2 7 11
2
In this situation we´ll bet 7 and 11. Not 2
But if you add "THE ABSENT MINDED WINNER" to betting, you´ll bet street 1-3!
Next, we "would have to continue to track". But we might not have to wait too long.
Quote from: Dane on Jan 27, 10:18 AM 2015
Good luck! I notice that you are a new member! Welcome!
It might not be a good idea to overflow you with more suggestions;
but here is one more: Begging for a
FIFTH repeat on the same line might be worth trying!
Thanks Dane
I had the wrong idea regarding 'The Absent Minded Winner'. I thought you were suggesting if I one street went ahead then you would
bet on the others.
Quote from: jon on Jan 28, 09:50 AM 2015
Thanks Dane
I had the wrong idea regarding 'The Absent Minded Winner'. I thought you were suggesting if I one street went ahead then you would
bet on the others.
I´m glad that you have improved :)
We should be broadminded
but not bet too broad!
Does any body else understand this or just me being thick :question:
Quote from: sturrock on Jan 28, 12:56 PM 2015
Does any body else understand this or just me being thick :question:
I think there are several systems that you could create here and that's why Dane isn't being too specific regarding any hard and fast rules.
I thought I understood using the 'Absent Minded Winner' part of this but now I'm not sure.
Please remember that "THE ABSENT MINDED WINNER"
is a topic that I started the same day I started this topic.
So far no reply there.
I tested various versions (together with the ABSENT MINDED WINNER) on more or less trustworthy online casino software.
Now I have also tested one version with the free roulette simulator (Steve´s simulator) :) with a good result: Right after approx. 1400 spins: 440 chips won.
The strategy version I chose was not with the dozen groups, but with four main groups with three streets in each one (maybe a small difference).
Tomorrow I´ll go to BERLINALE (the film festival), so I am offline the next week or so.