This is a 30 numbers bet, some may not like it? but that's how it is...
consider these 6 groups (red and black are looked at separatly)
Doz 1 RED
Doz 2 RED
Doz 3 RED
Doz 1 BLACK
Doz 2 BLACK
Doz 3 BLACK
Trigger: Wait until one group (either RED or BLACK) Hits two times in a row. (not necessarily in sequence) Now bet the other two groups, (12 numbers) and 12u on the opposite BLACK or RED.
(Most i have seen from the first test is 5 repeats from the same group).
Progression double for each loss. (This is not a perfect progression since it's a 30 numbers bet , but works) double up gives money back (if progression don't go too far)..
There are three options (?) when you get a hit (if you get the money back) like 1-2-4 etc
1. Reset and begin at 1u bet
2. Stay at the same level of bet for 2 hits in a row.--(For the next trigger!) (that will get you some profit)
3. -1 level in the progerssion line 1-2-4-8... etc.
It all depend on the risk/reward you want to take.
First test was played with 1u bets
So if EC wins you are even, and if number is hit it's +12.
It smells on 1 on Low and 1 on 3rd Dozen, but better version.
Good job, I think!
Thanks
Quote from: nextyear on Aug 20, 03:20 PM 2015
So if EC wins you are even, and if number is hit it's +12.
It smells on 1 on Low and 1 on 3rd Dozen, but better version.
Good job, I think!
Thanks
Yes, that's right. :)
Thanks
Test 2