I am a guy who feels the most viable way to win at roulette is to beat the probabilities. I want to compose a betting cycle that will allow far more wins than loses. And it will only loss due to one of those crazy, unexplainable, Logically impossible roulette moments.
I have so far but together a nifty little bet placement trail that seems to be working well. This is played on 3CORNERS so 12NUMBERS. No specific reason for picking which corners to play just going random at the minute.
Below is a 10spin cycle chasing 12 numbers (3CORNERS), I also want to put some bet cycles together for Rows, Streets and the 7 number selection.
Bet Stake. Running Total. Bet win.
3 3 9 .+6
6 9 18 .+9
12 21 36 .+15
18 39 54 .+15
24 63 72 .+9
30 93 90 .-3
57 150 171 .+23
81 231 243 .+12
135 366 405 .+39
198 564 594 .+30
Can somebody tell me how I work out probabilities over several spins? for example (lets forget the 0 for a sec) if I pick 12 random numbers the probability for this 1st spin is 33% It didn't hit. So If I stick with the same 12 numbers what is the probability of one of those 12 numbers hitting on the 2nd spin? It didn't hit. So If I stick with the same 12 numbers what is the probability of one of those 12 numbers hitting on the 3rd spin? and so on so on ?
HOW DO I WORK OUT RECURRING PROBABILITIES ?
Quote from: JSG240592 on May 25, 09:52 AM 2016
I pick 12 random numbers the probability for this 1st spin is 33% It didn't hit.
The probability is actually 67% that it does
not hit.
P(hit) = 12/37
P(no hit) = 1 - 12/37 = 25/37
P(no hits in 10 spins) = (25/37)
10The probability of
at least one hit in 10 spins - which I think is what you want - is
1 - probability of no hits in 10 spins
= 1 - (25/37)
10