#1 Roulette Forum & Message Board | www.RouletteForum.cc

Roulette-focused => Main Roulette Board => Topic started by: RouletteGhost on Oct 30, 08:55 AM 2018

Title: Romanosky bet
Post by: RouletteGhost on Oct 30, 08:55 AM 2018
Large number bet

Each win yields 1 unit
Each loss loses 8 units

For fun only and hit and run. Definitely play this for statistically insignificant number of spins

3 units one a dozen. 3 units in another dozen. 1 unit in a quad. 1 unit on another quad

No HG claim. Just a fun and fast way to win a unit and walk away


(link:://:.pichost.org/images/2018/10/30/sourcec792d.png)
Title: Re: Romanosky bet
Post by: nottophammer on Oct 30, 09:50 AM 2018
RG
I'm doing the 36*1,5,25+ on MPR, had 41 spins and the 1st of the 5 #'s to hit was #1 25th spin. The #4 hit on 40th spin
But as we know it could very well hit 1st spin
Title: Re: Romanosky bet
Post by: nottophammer on Oct 30, 09:55 AM 2018
RG
10 days of J247 air ball
(link:://:.pichost.org/images/2018/10/30/sourced5b1f.png) (link:://:.pichost.org/image/TAbCc)
Title: Re: Romanosky bet
Post by: nottophammer on Oct 31, 10:43 AM 2018
Ghost here's todays numbers from J247 air-ball.
Would you like me to post the spins daily ?  Rich any member from UK can confirm these daily spins, they only have to record the televised show on sky 176 usually after midnight,
(link:://:.pichost.org/images/2018/10/31/source34056.png) (link:://:.pichost.org/image/TV6b1)
Title: Re: Romanosky bet
Post by: Gitano on Oct 31, 11:00 AM 2018
Hi Mr.Nottophammer.
Do you have these numbers in txt format? If not, no problem.
Eheh I Suggest Romanosky study GUT before... :twisted: :twisted: :xd: 

KRegards
Title: Re: Romanosky bet
Post by: nottophammer on Oct 31, 12:00 PM 2018
Ok
Title: Re: Romanosky bet
Post by: ego on Oct 31, 12:43 PM 2018
I did have one idea about a selection for this bet, have not tested it.

There are five uncovered numbers with zero.
Four number that wins within six attempts has 50% probability and six number that wins within four attempts has 50% probability.
That is the binomial estimation.

That would be 50% probability for five numbers to hit within five attempts.
Now assume you pick your four numbers and zero and each time then hit within five attempts you write at what attempt they hit.
For example, 12345 and each time there is no hit within five attempts you write across X

Then it looks like this ...
Assume you would bet against attempt nr 1

X X 1 X X 4 X X 3 3 2 X X 3 X 4 1 X 2 X 3 5 X 2 X X
         WWWWWWWWWWWWLWWWWWWWWW

Any selection you can think of would work ... Cheers
And add Regression if possible.