I will list some instances of the EC:S: (x = L)
BE-
x
x
x
BE W
RE-
RE W
BO-
BO W
RO-
x
x
x
x
x
RO W
RE-
x
x
x
x
x
RE W
BE-
x
x
BE W
BO-
x
x
x
BO W
RE-
x
x
x
x
x
..and so on..
As noticed, there is often a repeat
of an EC-outcome within 6 spins. Not to mentions the Runs..
Another observation i made is that BE will go BO and the opposite. Just as RO will go RE and the opposite.
So, i claim that the old BE to RO and the opposite is a "myth" more or less.
Why is this?
I noticed that when we want to Bet, we must bet the SAME(LD). DBL is also a myth. Roulette is pretty much a game of repeat i think.
In Doz 1 we have:
5 RO but only 1 RE
5 BE but only 1 BO
In Doz 2, the most evenly distributed Dozen, we have:
3 BO
3 RE
3 BE
3 RO
In Doz 3 we have a majority of BO and RE:
4 BO but only 2 BE
4 RE but only 2 RO
So according to the Odds its:
for a RO-hit, Dozen 1-2
for a RE-hit, Dozen 2-3
for a BO-hit, Dozen 2-3
for a RE-hit, Dozen 1-2
BUT
1.
Since we can not beat the Odds, this will not work.
2.Because of the 2-1 payout will drag us down.
We should play INSIDE 8-10 numbers for 6 spins.
1. Follow the last Colour outcome, ex 16 = RE = Doz-2-3 = 8 Numbers
or: ex. 23 = RO = 10 numbers, mostly doz 1-2
or: ex. 29 = BO = 8 numbers, mostly Doz 2-3
or: ex. 2 = BE = 10 numbers, mostly Doz 1-2
2. Play the last Colour-outcome and BOTH E/O on that Colour.
This will require to pick the numbers from the Last 2 Dozens in order to play as less numbers as possible.
Example 1: last outcome is 5.32
numbers will be 1.3.5.7.9.30.32.34.36
Example 2: last outcome is 2.20
numbers will be 2.4.6.8.10.11.13.15.17.20
So i will chose my Bet depending of whats going on.
Either BO alt RE, or BE alt RO in the Last Dozens.
You may use a 111224-progression..
i play for ec to repeat whitin 10 spins in progrssion if lose retrack
Hi Compa,
Nice post. I will test this myself and hopefully get good results
Thanks
BW
Hi Compa
Is the last one RE or BE ?
So according to the Odds its:
for a RO-hit, Dozen 1-2
for a RE-hit, Dozen 2-3
for a BO-hit, Dozen 2-3
for a RE-hit, Dozen 1-2
TCD
Hi mate. Long time no see! :) It should be a RE!
Cheers
Hi Compa,
How come in your example below you bet on odd reds as well as even? I'm a bit confused.
Also, what do you do when you lose the progression...stop and retrack or quit?
Example 1: last outcome is 5.32
numbers will be 1.3.5.7.9.30.32.34.36
BW
That is no problem mate. If You once again look here:
1.
Since we can not beat the Odds, this will not work.
2.Because of the 2-1 payout will drag us down.
We should play INSIDE 8-10 numbers for 6 spins.
1. Follow the last Colour outcome, ex 16 = RE = Doz-2-3 = 8 Numbers
or: ex. 23 = RO = 10 numbers, mostly doz 1-2
or: ex. 29 = BO = 8 numbers, mostly Doz 2-3
or: ex. 2 = BE = 10 numbers, mostly Doz 1-2
2. Play the last Colour-outcome and BOTH E/O on that Colour.
This will require to pick the numbers from the Last 2 Dozens in order to play as less numbers as possible.
And Yes, Retrack after losing a progression.
Hope it helps;)
Cheers!
hey compa. a bit slow on my end, i don't get it. could you please explain how you'd play it with some examples?
vundarosa
There are only 7 red even numbers in dozens 2 + 3?
Val,
I think basically if you get a BE for example you play dozens 1 +2 BE's so 8 numbers
RE you play all the RE in dozen 2 + 3 etc
6 spins to win!
BW