This is the OPPOSITE way of play of a system that a member posted.(plus some tweaks)
So we are looking at the 3 last outcomes and we see the colours.
If we have 2of the same and 1 alone we are betting the 1 that is alone
If we have 3 of the same we bet the opposite one.
Progression +1 on a lose - 1 on a win.
In every new profit we reset to 1 chip.
If we need less chips to be in a new profit than the progression suggests , then we are minus the chips.....e.g.. we are -2 and progression stage say to bet 5 , then we are betting 3 chips in order to be +1(new profit.
Here is the testing grapg I did in 781 spins we have +172 profit.
This also proves that the original way of the system that this member posted can t work....
I am not sayng that the opposite way can sure works , but if the opposite is winning, then the original is losing.
(//)
It would be nice if a programer could code this system to give a fast and big test
thanks
This method is also called "Intermediate Equalization of Even Chances" and was mentioned by "WINKEL" and being discussed several years ago at the PAROLI Roulette Forum.
I did play this method in a B & M casino and the croupier wa NOT too happy. The reason being I had chosen to give action to all EC , B/R O/E H/L.
Some action !!!
Nathan Detroit
HAPPY WINNINGS!!!
This IEEC method is a rather good way to play as long as one selects only 3 dominants.
Following all 6 EC is self defeating and not worthwhile considering.
Occasionally a player might find himself sitting out a few spins while waiting for the next opportunity.
Nathan Detroit
HAPPY WINNINGS!!
I only try to help everyone RoletteExplorer..........
625 games played 1 loss, I have to report.........
Roulette Explorer ,
This is a very sound method you have brought to our attention. The reason being that it is entirely based on the 50/50 expectations of the EC as long as one stays with only one of each category as I have already stated in a previous post
.
HAPPY WINNINGS!!!
N.D.
Quote from: RouletteExplorer on Sep 21, 07:45 PM 2011
This is the OPPOSITE way of play of a system that a member posted.(plus some tweaks)
So we are looking at the 3 last outcomes and we see the colours.
If we have 2of the same and 1 alone we are betting the 1 that is alone
If we have 3 of the same we bet the opposite one.
Progression +1 on a lose - 1 on a win.
In every new profit we reset to 1 chip.
If we need less chips to be in a new profit than the progression suggests , then we are minus the chips.....e.g.. we are -2 and progression stage say to bet 5 , then we are betting 3 chips in order to be +1(new profit.
Here is the testing grapg I did in 781 spins we have +172 profit.
This also proves that the original way of the system that this member posted can t work....
I am not sayng that the opposite way can sure works , but if the opposite is winning, then the original is losing.
It would be nice if a programer could code this system to give a fast and big test
thanks
Hello RX
Yeah its good method. I play something very similar but i start betting with 3 units and
decrease or increase by 1 if i win or lose respectively. I also posted here other similar system when you reset after 3 bets. I bet EC and usually follow the last decision for max 4 steps.
The most crucial thing here in order to be steady in profit is to set your stop loss and win target. I usually stop my session when 10-15 units ahead and if 25 units down.
Its very difficult to recover if deeper in the hole ;D
Its a grind sometimes but if you are satisfied with winning 20 or 30 units in 4 sessions this might be something for you.
Regards
I would like to add that if we have 3 of the same EC e.g. R-R-R then one could chose from 3 options:
a.)betting with the RUN
b.) betting against the RUN
c.) Sitting out several spins.
HAPPY WINNINGS!!!
N.D.
Quote from: Nathan Detroit on Oct 06, 08:44 AM 2011
I would like to add that if we have 3 of the same EC e.g. R-R-R then one could chose from 3 options:
a.)betting with the RUN
b.) betting against the RUN
c.) Sitting out several spins.
HAPPY WINNINGS!!!
N.D.
Hello
I usually go with the flow here ;D But this is of course just a guessing game. If MM and stop-loss are done properly you stand as a good chance of winning as in any other good system. You will lose here quite often but should make a steady profit.
Yesterday i saw 3 DS hit 17 times in row.Things happen. I don't like fancy systems. They all lose sooner or later.
Here you get out at a set stop-loss and have a very good chance of recovering in next sessions.
Regards
Option " c' would be the preferred one . The reason being that it would not deviate from the original intermediate equalization scenario.
Tsi- Nan- Fu