I test random against random playing one dozen.
Follow the last six times, if a loss follow the last hit six times.
(link:://img354.imageshack.us/img354/8523/dozen6against6nw6.png)
Now this is one very intressant tweak you can experiment with, reverse towards the chart above.
As one dozen should hit with in average at step 5 then if you have two dozen hit you only have to place three bets for the dozen that has no show, if a loss the dozen sleep over 6 times, that is reverse to the method above.
Then you wait until the unhit dozen hit and play the new sleeping dozen and you repeat that formula over and over again, so you play reverse.
(link:://%5Burl=link:://i56.tinypic.com/whjuow.jpg%5Dlink:://i56.tinypic.com/whjuow.jpg%5B/url%5D)
(link:://i56.tinypic.com/whjuow.jpg)
Well i run one simulation testing the option one for even money bets using same selection - did pretty good.
(link:://i51.tinypic.com/eoths.jpg)
Hello
It looks interesting, but do not quite understand how to make the first bet, do not quite understand this "Follow the last six times, if a loss follow the last hit six times," could clarify a little please? I would make a test of this system.
Do you use any tipe of progression or its a flat bet?
Thanks
Quote from: jarabo002 on Oct 09, 05:54 AM 2011
Hello
It looks interesting, but do not quite understand how to make the first bet, do not quite understand this "Follow the last six times, if a loss follow the last hit six times," could clarify a little please? I would make a test of this system.
Do you use any tipe of progression or its a flat bet?
Thanks
Well the first method mention does follow the first dozen hit.
If dozen 1 hit you play dozen one until six loses.
Then if six loses and dozen 3 is last hit you play dozen 3 six times.
Progression 1 1 1 2 2 3 4 6 8 12 and so on ...
For the even money bet test i just wait for dozen 1 or 3 to hit once.
Then i follow the one that hit and play it until six loses and change to opposite.
Progression 1 1 1 2 3 5 - 8 13 21 34 55 89