Hi all ^-^
I was wondering, if we play a 2 number system for 37 spins, what are the odds we will win/lose?
I calculated but i'm not sure if I got it right, I got 12,8% a chance of loss, is that right?
Also do you know of any good 2 number system?
I was thinking of running 37 spins then chooseing the newest two numbers that appeared twice and betting on them for the next 37 numbers till a hit. I figured that way we dont bet cold or hot numbers cause cold numbers can stay cold and hot numbers can go cold, we bet on the "warm" middle ;D
Works fine for now, no losses yet, sometimes even 2 or 3 hits come early, what do you think?
And is betting just 2 numbers a good idea?
If you can get an answer from Mr.J that would be perfect. I remember him saying we're all fools playing more than 2 numbers so you guys would get along ;)
Yes, his thoughts would be highly appreciated because I know he plays only up to 4 numbers and I'm thinking going the same way ;D
Quote from: nitrix on Jan 10, 03:03 AM 2012
If you can get an answer from Mr.J that would be perfect. I remember him saying we're all fools playing more than 2 numbers so you guys would get along ;)
Come on, I never said 'fools'.
Ken
Hello MrJ
I would love to hear your thoughts about the above system or if you have any system you would like to recommend... I'm all ears ;D
Anyone?
Is it really 12,8%?
Have I calculated right?
2/37=0.054 chance of a hit for betting on two numbers for one spin. x37(spins) roughly 2% chance of getting a hit.
A popular tactic is playing the most repeated numbers over a number of spins (which may or may not win).
Here's my favorite two number system. Victor One link:://rouletteforum.cc/index.php?topic=1759.0 (link:://rouletteforum.cc/index.php?topic=1759.0)
Thank you very much Proofreaders2000
I'll have a look at the system, thanks :)