After millions of spin tests it has been shown that there will always be a minimum of 4 repeaters in a 37 spin cycle.
This then implies that 1 dozen, which one we don't know, will always have 2 or more repeaters in it during a 37 spin cycle.
Infact, 1 dozen and 1 column, will always have 2 or more repeaters in it during the same 37 spin cycle.
I wanted to present this observation to see if any good methods can be developed around it?
Any ideas out there : )
I've been chasing the repeaters in the last couple days on BV. My strategy is simple, I always bet on the last five numbers, starting with one unit on each, and after losing two times, I add one more unit to each number until I win.
I first tried in fun mode a couple times, and I always made 2-300 unit profit in about 50 spins. It's seems to be a bit harder to win in real money mode, and of course much more scarier. Two times I was down 6-700 units in real mode, before the repeat finally happened. And this progression has a limit, after betting 7 units on each number, the amount can be win, will not cover the previous losses.
Overall I made some profit, but I'm scared to continue playing this.
Rather than chasing all the repeats, you could track until repeats start showing up and then only bet the units hit in the dozens that have the repeats in them. This should slow down the entry into the betting cycle and minimize the number of spaces covered. Play with whatever number of units need to be bet to cover the losses so far in the 37-spin cycle, thus ensuring a profit with any hit. Play until a hit and start fresh immediately after.
Thanks for the ideas so far!
One idea I have is to randomly select a dozen.
Play all hit numbers in this dozen until 4 repeaters have shown.
If you do not have a win stop, then either start the process again with the same dozen or select another random dozen.
Continue with your progression and play all hit numbers (starting with one) in this dozen until 4 repeaters have shown.
etc....?
Selecting a random dozen puts you in the position of maybe not being in the right place at the right time for a hit. If you wait until 4 repeats have happened, you might have won 1 time or you could have lost to both of the other dozens getting repeats twice or one dozen getting 3. If you only play dozens that have a single repeat so far, you cannot miss the first dozen to get the second repeat. Assuming your initial premise is correct (and I have no reason to doubt it), my method is fool-proof. You cannot bet more than 33 spaces per session, meaning that any hit would yield some sort of profit if you have the same bet on each space. Simply increase the units per unit to cover the bets you have already made and it is a done deal.
I wish I would have come up with this sooner!
Ok....on status...a rough idea.....very much a Turner like idea.
There will be 2 repeats in each doz.
if we see 1 repeat in a doz....we know there will be another in 37.....
We don't know there will be 1 more until we see 1. So wait for 1
So we see a repeat in D1....and see 1,2,2,4,5 have hit, 2 being the repeat. now bet 1,2,4,5 because these are the best candidates to hit double because the others havnt even hit yet.
You can do this by tracking 37....but its hard.
You can also do this by tracking a lower number until you see a repeat. You now add that dozens contents and any future numbers.
I tried this.
In RX.....chose statistics - numbers, then we set Options - configure to track the last 15.
Why 15?
most marques are 15 or so....in other words, look at the marquee
pick the dozen which has 1 repeat and if there are 2, the one with a repeat and the most hits. Add numbers of that doz as they hit.
See attached...play the 3rd dozen,
betting 32,33,34,36
17
6
32 HIT
In summary. Look at the marquee for a repeat. See if its the only one in a doz or col. Play all contents of the D or C...adding hits as you go.
There is better than this, which i will think about.
No need to overthink this.
If we wait until our first repeat in a cycle of 37 spins, we will have already skipped the first 4-10 (just for consideration, not statistically important here). That means that in the next 25 spins or so, we will get a repeat out of a dozen that already has a repeat, taking the original idea from AMK as factual. All we need to do is keep betting the spins that have already shown, but only in the dozen(s) that have already had a repeat. This keeps us in a smaller group of numbers for longer, minimizing our bankroll needs and maximizing our profits when we get the 2nd hit that we expect from at least one dozen in 37 spins from AMK's original premise. I have spent the past couple hours on this getting hit after hit after hit. The only limitation I can see is table limits, as it is going to hit.
Didnt i just day exactly that?
Thanks for your insights Turner and Colbster.
Always appreciate it.
Quote from: ati on Nov 10, 03:20 PM 2013
I've been chasing the repeaters in the last couple days on BV. My strategy is simple, I always bet on the last five numbers, starting with one unit on each, and after losing two times, I add one more unit to each number until I win.
I first tried in fun mode a couple times, and I always made 2-300 unit profit in about 50 spins. It's seems to be a bit harder to win in real money mode, and of course much more scarier. Two times I was down 6-700 units in real mode, before the repeat finally happened. And this progression has a limit, after betting 7 units on each number, the amount can be win, will not cover the previous losses.
Overall I made some profit, but I'm scared to continue playing this.
I play that way from time to time with the last 3 or 4 numbers...I have the most success with a strict stop-loss and lean progression. It usually comes in waves so I wait for a "virtual win" and then play it till I get 2 or 3 wins within 7 or 8 spins per attack or hit the stop-loss and wait for the next opportunity to attack.
You can always separate the dozens into lines or
streets and track the hot numbers in those individual areas.
What I like about this......its something that WILL happen.
As I prefer to call it >>"EVENT BETTING"
Ken
Quote from: Colbster on Nov 10, 05:23 PM 2013
The only limitation I can see is table limits, as it is going to hit.
------------
do we really need a progression?!
vundarosa
Can someone please let me know as to how do you think this "exclusive knowledge" be utilized?
QuoteAfter millions of spin tests it has been shown that there will always be a minimum of 4 repeaters in a 37 spin cycle.
This then implies that 1 dozen, which one we don't know, will always have 2 or more repeaters in it during a 37 spin cycle.
Infact, 1 dozen and 1 column, will always have 2 or more repeaters in it during the same 37 spin cycle.
If there are some repeats (everybody knows law of third and repeaters coming thereby) why and how do we look it to be a part of any dozen or column or any EC?
Everybody know repeats are guaranteed. The question is how to exploit such probability.
Only sure shot way to catch on it to play every number that wins till we get a repeater. This way, we will need a progression that can be even harsher than martingale. >:(
How's this? The first dozen that has a number to show twice (that dozen will
be your playing dozen). Flat-bet that number and the other newest number to show twice in that dozen. Stop at spin 37 win or lose.
Quote from: vundarosa on Nov 10, 09:14 PM 2013
------------
do we really need a progression?!
vundarosa
No....to me...a progression with an idea like this mrans that you forgot you may have bad luck. Factor that one in with a stop loss.
in that case if you get dozens we have,1,2,3, and build up 2 more sets of dozen with any 12 numbers then you can input spins and wait till 20 spins and bet for the event ...just a opinion
Quote from: maestro on Nov 11, 05:56 AM 2013
in that case if you get dozens we have,1,2,3, and build up 2 more sets of dozen with any 12 numbers then you can input spins and wait till 20 spins and bet for the event ...just a opinion
Nice..
Funny enough....I've been trying this.
Wait until the last 12 is unique and when a repeat shows...bet all 11.
Unbeknown to me...I was using AMKs data and Maestros suggestion before they posted it.
On 2 repeats in 12 stop until 1 repeat. If it goes unique again....wait until 1 shows.
Been trying this for weeks.
ok just a hint what you can do is go for repeaters only for 22-25 spins say you have 1 number ,2 and so on as soon as first one you were beting turns 25 spins drop it...no progression
Quote from: maestro on Nov 11, 10:52 AM 2013
ok just a hint what you can do is go for repeaters only for 22-25 spins say you have 1 number ,2 and so on as soon as first one you were beting turns 25 spins drop it...no progression
Isnt that Ball24?
Another way would be to play dozen and column qualifiers.
The example below plays TWO qualifiers from each in the first game.
A rule could be to play the most recent TWO if you have three qualifiers in the dozens and columns.
The first game below plays dozen 1 and column c.
Then dozen 2 and column b qualify as well.
The second game was a quick game with just dozen 2 and column c.
Maestro is right to limit the spins to between 20-25 and reset.
27 3C
16 2A
21 2C
5 1B
6 1C
3 1C
1 1A
36 3C
4 1A
14 2B
12 1C
11 1B
3* 1C PLAY 1,3,4,5,6,11,12/21,27,36.
30 3C PLAY 1,3,4,5,6,11,12/21,27,30,36.
14* 2B PLAY 1,3,4,5,6,11,12/21,27,30,36. 14,16.
16 WIN.
15 2C
16 2A
36 3C
18 2C
18* 2C PLAY 15,16,18/36.
22 2A PLAY 15,16,18,22/36.
13 2A PLAY 13,15,16,18,22/36.
7 1A PLAY 13,15,16,18,22/36.
15 WIN.
no is not turner,,,you can check dozens and colums and play separate ...or there is always other way,check dozens and colums and track to see which one takes longest repeat...say dozen 2 has 3-4 numbers you bet on and takes you to above 25-26 to hit your repeater, if it goes above drop your numbers and start fresh on same dozen,,,,,,,,,,,,, just spark in my silly brain :thumbsup:
2 more quick examples.
You won't get burnt if you reset around the 20-25 spin mark playing like this.
2 1B
4 1A
9 1C
2* 1B PLAY 2,4,9.
13 2A PLAY 2,4,9.
25 3A PLAY 2,4,9.
4 WIN.
11 1B
16 2A
17 2B
24 2C
3 1C
10 1A
34 3A
17* 2B PLAY 16,17,24/11.
23 2B PLAY 16,17,23,24/11.
32 3B PLAY 16,17,23,24/11,32.
6 1C PLAY 16,17,23,24/11,32.
29 3B PLAY 16,17,23,24/11,29,32.
27 3C PLAY 16,17,23,24/11,29,32.
25 3A PLAY 16,17,23,24/11,29,32.
29 WIN.
Quote from: maestro on Nov 11, 12:01 PM 2013
no is not turner,,,you can check dozens and columns and play separate ...or there is always other way,check dozens and columns and track to see which one takes longest repeat...say dozen 2 has 3-4 numbers you bet on and takes you to above 25-26 to hit your repeater, if it goes above drop your numbers and start fresh on same dozen,,,,,,,,,,,,, just spark in my silly brain :thumbsup:
Silly brain ?.....More like "A beautiful mind"... ;D
Having said that...Russel Crowe was nutz and had imaginary friends :-\
Thanks everybody for the great ideas and analysis!
If you have what you think is a good application for 1 dozen (and column) always having 2 repeats in it within 37 spins PLEASE post your idea.
The more ideas we can gather the more we can fine tune applying this stat.
thanks turner....tell my wife she thinks i am wayyyyyyyyyy of the hooooooooook :twisted: :twisted: :twisted:
Testing my method, I just hit the 26-spin-mark before getting my 4th repeat. If we follow the idea behind the law of the third, we anticipate 12 of the 36 will not hit, meaning that 24 will. 24+4 repeats puts us theoretically at the 28-spin maximum. This is not too far beyond the previous posts regarding 20-25 spins max. Adjust your BR accordingly, but you will get the hits.
Quote from: Colbster on Nov 11, 03:38 PM 2013
Testing my method, I just hit the 26-spin-mark before getting my 4th repeat. If we follow the idea behind the law of the third, we anticipate 12 of the 36 will not hit, meaning that 24 will. 24+4 repeats puts us theoretically at the 28-spin maximum. This is not too far beyond the previous posts regarding 20-25 spins max. Adjust your BR accordingly, but you will get the hits.
That said we could aim for the hottest two dozens
in say 12 spins and bet the unique numbers with a stoploss.
Stop loss is indeed very important, but also really hard to use, because the next spin could always be the winner. Today I was betting every number that has shown waiting for a repeat, and one time there was no repeat for about 25 spins. I had to use an aggressive progression, because I had more numbers covered in every new bet. My last bet was 400 units, and that still wasn't enough to profit. But I kept betting big, and with a win-loss-win-loss-win-win series I managed to get back to even.
I could have busted my roll again, so be careful everyone, and learn from my mistakes. :D Other time this method was successful, and I made 100 units profit in 50 spins. Last week I tried something similar with streets, and one time 11 street out of 12 hit before a repeat!...what can happen, will happen.
Glad you could get back to break even Ati :thumbsup:
I'm a big fan of betting right away so here is a proposal. Look at the last 12 spins (or however many spins are on the marquee.) Note the hottest two dozens and bet continuously the newest number from both dozens--until a new hottest dozen emerges then bet the newest two numbers again from those two.
Hi All . ..
Thanks AMK for alerting me to this thread. I have attached an Excel Tracker that shows the numbers that repeat in a 37 spin cycle and shows them by their respective Dozen and Columns.
Hope this helps.
Nick
Here's an idea...
Repeat numbers...repeat dozens
As soon as you start getting repeat numbers...always bet the last dozen hit.
Ex: say we have our first repeat number ... # 35
Everytime doz 3 hits bet # 35 hoping it wil hit # 35 for the third time.
Do this will all repeats ... play them when their particular dozen hits.
Yes this will probably take longer to win and you will surely miss some 3peats because we bet on the wrong doz. But hey aren'nt we looking for a way to play this without breaking the bank.
Just a thought.
B
Check out this system
Maison One: A Single Number Thirty-Six Spin System
Procedure: Note the last 10 spins on
the marquee. Which dozen is the hottest?
Bet the last number to show from that dozen for up to 18 spins.
Stop on a win or after 18 consecutive misses. Repeat procedure
once more for 18 spins.
Goal is two wins per session.
Bankroll suggestion: 300 units per one unit
base bet. Six-hundred units per two unit base...
Win-Target/Stop-Loss: +10%/-50% of the original bankroll amount.
------------------------------------------------------------------------------------------
Test: Celtic Casino American Wheel
Monday, November 11, 2013 @ 8:00pm CST USA
...36,9,35,11,22,17,3,26,32,29
Third dozen is dominant. Bet #29 and
any new third dozen number that shows.
Bet #29: 1.) 6(x)-5 2.) 25(x)-5*new trigger number active
Bet #25: 3.) 33(x)-5*new trigger number active
Bet #33: 4.) 36(x)-5*new trigger number active
Bet #36: 5.) 14(x)-5 6.) 34(x)-5*new trigger number active
Bet #34: 7.) 23(x)-5 8.) 25(x)-5*new trigger number active
Bet #25: 9.) 30(x)-5*new trigger number active
Bet #30: 10.) 20(x)-5 11.) 15(x)-5 12.) 34(x)-5*
New trigger number active. Bet #34: 13.) 22(x)-5
14.) 11(x)-5 15.) 00(x)-5 16.) 10(x)-5
17.) 10(x)-5 18.) 34(win)+175
------------------------------------------------------------------------------------------
break even
====================================
Test: Celtic Casino American Wheel-
Monday, November 11, 2013 @ 8:46pm CST USA
...35,1,27,15,7,6,8,31,12,22,31
First dozen is dominant. Bet #12 and
any new first dozen number that shows.
Bet #12: 1.) 28(x)-5 2.) 6(x)-5*
New trigger number active. Bet #6: 3.) 32(x)-5
4.) 23(x)-5 5.) 6(win)+175
---------------------------------------------------------------------
+155*(two hits within 37 spins)
Like that idea as well Buffster.
Will do some thinking about so that I see all angles clearly.
Can get tricky : )
Anybody out there remember the Dyksexlic clues about his method for catching one repeater in 37 spins? He kept people focusing on just one repeat in 37 spins, but this statement was not accurate as there will always be 4 repeats.
That looks good Proof!!
I am always very impressed with the roulette work you do.
I am sure if I just played all the methods you have presented only once for a few games with the advised win/loss percentages, I'd do fine.
One a day sounds good : )
When I start doing this I will make a thread for it.
Thanks again Proof.
Wait for 12 unique numbers without repeats then start betting them with a progression (it must be constructed assuming we will get 4 hits in next 25 spins after start betting...)... not sure its possible, due to table limmits....
Subsequente uniques should be added to our bets....its tricky to get a progression for this....
Quote from: vladir on Nov 12, 09:08 AM 2013
Wait for 12 unique numbers without repeats then start betting them with a progression (it must be constructed assuming we will get 4 hits in next 25 spins after start betting...)... not sure its possible, due to table limmits....
Subsequente uniques should be added to our bets....its tricky to get a progression for this....
I'm not saying this will work perfectly, but Oscar's Grind is always worth a try on any system.
Just play 1 unit on each number until a win. If you're in profit, stay at 1 unit on each number for the next attack.
If you're down after a hit, add a unit to your next attack. So, you'll play 2 units on each number until a hit.
Continue in this fashion on until you have a hit that puts you in profits.
GLC
A thought,
Let's assume that within the 37 spins, we'll have repeaters of both colors (Red & Black), and not just one color. Thus we could wait till we have one or two repeaters of a same Color (Red, let's say), and from there use all the Black numbers that have shown till the end of the 37th spin.
two repeaters ?
Quote from: Carsch on Nov 12, 02:38 PM 2013
Let's assume that within the 37 spins...
First thing to do is drop the 37 spins cycle. It's meaningless and useless.
Quote from: Skakus on Nov 12, 04:49 PM 2013
First thing to do is drop the 37 spins cycle. It's meaningless and useless.
The most important thing is what's happening now /
not happening now....not what happened 20 spins ago or what's going to happen in 20 spins!
I am going of track a bit...BUT....if you think about different forms of winning gambling...they more or less concentrate on the here and now!
The 'true count' in a game of Blackjack tells you your advantage now...not what it's going to be in 10 hands time.
Why should it be any different when coming up with a winning strategy for roulette!
....................and now back to our programme. ;D
Quote from: Skakus on Nov 12, 04:49 PM 2013
First thing to do is drop the 37 spins cycle. It's meaningless and useless.
But isn't the whole idea here about repeaters.........
what has happened and
what is going to happen?
What
'has happened' is a count of repeaters..........and if we know that we can only have a minimum of 4 repeaters within 37 spins, knowing how many repeaters we've had in the past, isn't it right to assume that we can tell more or less how many more repeaters we will have within the next few spins within the 37 spin limit?
There are two certainties here,
1) There will always be repeaters.
2) The 37 spin window will always shift along 1 spin at a time blurring into infinity.
Quote from: Skakus on Nov 12, 06:30 PM 2013
There are two certainties here,
1) There will always be repeaters.
2) The 37 spin window will always shift along 1 spin at a time blurring into infinity.
In other words, you don't agree with the test which says that "after millions of spin tests it has been shown that there will always be a minimum of 4 repeaters in a 37 spin cycle." Am i getting you right?
Cause that is exactly what i suggested in my propose thought above.........that if we have had 2 repeaters, it is ok to assume that within 37 spins (including the 2 repeaters) we should have a least 2 more repeaters. Unless there is something about the test that i'm missing here.
What I mean is you are always within a 37 spin window because it shifts along with you after every spin.
That fact mitigates the applicability of the 37 spin cycle.
I’m not saying you can’t look back to recent repeaters for a trigger of some sort, just that it probably doesn’t help or there probably are better pointers than a rigid 37 spin limit.
i got you.
Quote from: Skakus on Nov 12, 06:30 PM 2013
There are two certainties here,
1) There will always be repeaters.
D1 -no repetition
I've always been on the fence with this...... 37/38 spin cycle stuff. Lets say we start to keep track and 10 spins into it, we have the 23 hit twice.
Would (or could) those 23's be part of the 37 spins OR those 23's could be part of a PRIOR 37 spin cycle, which is now at its tail end. EVERY number that hits, is the beginning, the end and the middle of SOMEBODYS 37 spin cycle. I'm not saying I'm against it, just sayin it can get quite confusing.
Ken
My answer to the confusion (at least as related to this particular thread) is to track until I get my hit and then backtrack to the spin immediately AFTER whichever spin would have given us 2 repeats.
For example
[reveal]
18
------------------------
4
23
17
19
22
5
14
29
36
0
8
22
1
22
18
Even though the 18 is the most recent double, we go as far back as we can without having another repeat in the list.
[/reveal]
By doing this, we minimize tracking. It gives us the most information possible while retaining a single repeat, allowing us to be constantly after the initial tracking stage. As a variation, rather than tracking back until there is only 1 repeat total, we can track back until there is only 1 repeat per dozen. This gives us more information typically, although we will usually have more dozens active right off, driving up our hit percentage but also giving us the fewest spins before it starts marching up the progression.
Quote from: MrJ on Nov 13, 12:57 PM 2013
I've always been on the fence with this...... 37/38 spin cycle stuff. Lets say we start to keep track and 10 spins into it, we have the 23 hit twice.
Would (or could) those 23's be part of the 37 spins OR those 23's could be part of a PRIOR 37 spin cycle, which is now at its tail end. EVERY number that hits, is the beginning, the end and the middle of SOMEBODYS 37 spin cycle. I'm not saying I'm against it, just sayin it can get quite confusing.
Ken
Thats the true dilemma for sure
I still don't see how this can be effectivly used...
Quote from: MrJ on Nov 13, 12:57 PM 2013
I've always been on the fence with this...... 37/38 spin cycle stuff. Lets say we start to keep track and 10 spins into it, we have the 23 hit twice.
Would (or could) those 23's be part of the 37 spins OR those 23's could be part of a PRIOR 37 spin cycle, which is now at its tail end. EVERY number that hits, is the beginning, the end and the middle of SOMEBODYS 37 spin cycle. I'm not saying I'm against it, just sayin it can get quite confusing.
Ken
I'm thinking that any 37 spin cycle will do. Of course, the person who did the test is the one who could confirm this.
Actually, upon further thinking, it does make sense that it would apply to any 37 spin cycle.
I went over 100 sets of 50 spins from Wiesbaden, betting on the last number and adding new numbers as they show up, stopping on a win. Over 90% hit repeat in under 14 spins, once in 17 spins, twice in 19 spin. Not sure what kind of progression could accommodate this, it gets expensive in a hurry. Maybe stop or reduce the increase after 14 spins.
Jeromin
That's why it's critical to use qualifying of numbers to determine where to bet. This is the single method that I keep coming back to and that I believe has the most potential. If we know that at least one dozen will have two repeats, we qualify by waiting for a dozen to get one repeat. At that point, we can bet on just those numbers that have hit in that particular dozen or dozens where there have already been repeats this cycle. It keeps bet numbers to a bare minimum, allowing us to last longer.
The problem I have had in the past with this is that we bump up against table limits when we have too many numbers to play at a time, particularly when each dozen has had exactly one repeat and we have all hit numbers so far to cover. This situation rectifies itself quickly, with a couple repeats clearing the table over the course of a couple spins. Until then, I have two possible solutions:
1. Only play when there are fewer than X spaces to play. This gives us greater returns for our hits but it does give us periods where we are not betting and we can be missing hits along the way that might lessen our drawdown.
2. Play up to the maximum allowed on the table, regardless of whether we are covering our drawdown in a single hit. I have always played to be positive after a single win, but a leveler could easily be used to solve this conundrum. Additionally, you could just keep a running drawdown tally and carry it through to the more profitable spins that will come on the heels of a dry spell. As the stated statistics imply, 4 repeats is a bare minimum and we are likely to get many more hits than this on average. When we have a slow spot, carry on. The down side: Bankroll.
Colbster, That was a long think !
Close on 2 years ^-^
2 years to branch off in numerous other directions, get some feedback, start a business, and sit back down to the computer to say this still makes a heck of a lot of sense to me. Or maybe my brain just fires a little slower than some ^-^
Hello again Colbster!
Havent checked the forum for a while and wanted to check my old messages when I saw this thread which I started apparently 2 years ago and you just posted today! I fully agree with you on the methods strength.
Theres definitely something to this!
I made this comment a LONG TIME AGO, it goes for ANY roulette method >>
There are only TWO choices (imo).....
We are either betting on unhit numbers (for whatever reason) from the last/future "X" number of spins
*OR*
We are betting on already hit numbers (for whatever reason) from the last/future "X" number of spins.
I dont see much of a grey area on this. I wish there was more certainty in roulette (lol), our number(s) will either hit or they won't. (no kidding Ken). We will either go home with a profit or we won't (no kidding Ken). Its very tough to PLAN a SURE WINNING day at the casino. This damn game will even kick you in the nuts while you lay helpless on the casino floor.
Its a very non-bias game. It doesn't care about your race, gender, religion, finances, politics, age etc.
The job of the roulette ball is to slice your throat and watch you bleed out. Sorry for being so blunt but its the truth.
Ken
The job of the roulette ball is to slice your throat and watch you bleed out. Sorry for being so blunt but its the truth.
Very true. I just tried this theory (in extensive testing) and it doesn't hold up. :q
Been working on this and law of the 3rd for alot of years. I have researched 700k real Numbers and 1 million rng Numbers. Ive been loggin real roulette spins from royal casino, Aarhus Denmark for almost a year. Some of my results:
52% of the time A repeat happens before 8 unique Numbers have shown.
The absolute winner is a repeat on the 8 spin after 7 unique Numbers have shown.
Example:
22
2
11
9
0
32
29
2 - repeat.
Longest streak without a repeat was 27 spins. All spins on single zero wheels.
The percentage Was higher than if i had selected 7 random Numbers for betting on.
Like op Said a minimum of 4 repeats on 37 spins.
Hope anyone Can use my observations.
I meant 52% of the time the repeat happened before or on the 8th Spin (7 unique Numbers).
Derp
You are correct about repeat in 1st 10 spins.
9/10; a repeat is more common than 10/10.
the biggest fly in the ointment, AKA the general, posted 10330 spins from is archive and 9/10 happened more than 10/10 no repeat.
Just look up the non-hit time tables; all show 9/10 is the most common for 10 spins.
In fact repeats show over 40 spins in groups of 10 spins as; 1-3-5-7 and at 60 spins repeats are 30/60