#1 Roulette Forum & Message Board | www.RouletteForum.cc

Roulette-focused => General Discussion => Topic started by: Roulettebeater on May 24, 07:04 AM 2018

Title: Question on roulette progressive probability
Post by: Roulettebeater on May 24, 07:04 AM 2018
What’s the probability of 8 misses in a row for a bet on 17 numbers in roulette ?

Title: Re: Question on roulette progressive probability
Post by: Bigbroben on May 24, 07:32 AM 2018
0,7288%,  or 1/137,2.
Title: Re: Question on roulette progressive probability
Post by: Roulettebeater on May 24, 07:42 AM 2018
Quote from: Bigbroben on May 24, 07:32 AM 2018
0,7288%,  or 1/137,2.

Can you please write down the equation for it ?

Thx
Title: Re: Question on roulette progressive probability
Post by: Nimo on May 24, 07:46 AM 2018
Probability odds that it will hit 99.2711701%

=-(((20/37)^8)-1)
Title: Re: Question on roulette progressive probability
Post by: Bigbroben on May 24, 07:49 AM 2018
Alright Nimo,

your result + my result= 1.
So we're good!

Odds of losing: 19/37.
(19/37)^8=1/137 or 0,7288%
Title: Re: Question on roulette progressive probability
Post by: Bigbroben on May 24, 07:52 AM 2018
(link:://:.pichost.org/images/2018/05/24/temp_374846.png) (link:://:.pichost.org/image/s4YsD)
Title: Re: Question on roulette progressive probability
Post by: Roulettebeater on May 24, 07:54 AM 2018
Alright !
So you would lose one cycle out of 137 rounds.

Now can anybody makes a quick simulation on the profitability of this bet ?

136* 19 - 1*( 1+2+4+8+16+32+64+128)

Like that it will lose but be aware that player can win more than 19 if he progressed the progression

Any idea ?
Title: Re: Question on roulette progressive probability
Post by: Bigbroben on May 24, 07:59 AM 2018
Quote from: Roulettebeater on May 24, 07:54 AM 2018

136* 19 - 1*( 1+2+4+8+16+32+64+128)


Do you really mean this, or should it be:
136*19- 17*(1+2+4+8+16+32+64+128)
?
Title: Re: Question on roulette progressive probability
Post by: Roulettebeater on May 24, 08:00 AM 2018
Quote from: Bigbroben on May 24, 07:59 AM 2018
Do you really mean this, or should it be:
136*19- 17*(1+2+4+8+16+32+64+128)
?

Yes you have right .

Good obeservation bigroben!

Title: Re: Question on roulette progressive probability
Post by: Bigbroben on May 24, 08:16 AM 2018
Quote from: Roulettebeater on May 24, 08:00 AM 2018
Yes you have right .

Yess......

I did a little table,  it actually shows that in a balanced 137 spins, you'll win 3661u in 136 spins and lose 4335 in 1 spin...

(link:://:.pichost.org/images/2018/05/24/temp_248671.png) (link:://:.pichost.org/image/s41Yl)

Do you want to proceed?
Title: Re: Question on roulette progressive probability
Post by: Roulettebeater on May 24, 08:27 AM 2018
Quote from: Bigbroben on May 24, 08:16 AM 2018
Yess......

I did a little table,  it actually shows that in a balanced 137 spins, you'll win 3661u in 136 spins and lose 4335 in 1 spin...

(link:://:.pichost.org/images/2018/05/24/temp_248671.png) (link:://:.pichost.org/image/s41Yl)

Do you want to proceed?

So it’s headed to the hell ?
Title: Re: Question on roulette progressive probability
Post by: vladir on May 24, 08:48 AM 2018
Quote from: Roulettebeater on May 24, 08:27 AM 2018
So it’s headed to the hell ?

Exactly... the place where all methods go  :xd:
Title: Re: Question on roulette progressive probability
Post by: Bigbroben on May 24, 11:01 AM 2018
Quote from: Roulettebeater on May 24, 08:27 AM 2018
So it’s headed to the hell ?

I dunno?
Supposedly if you're using some kind of visual ballistic the accuracy is enhanced...  So if you're good and can bet 17nrs and never lose 8 in row...