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Roulette-focused => General Discussion => Topic started by: FreeRoulette on Jul 09, 01:18 AM 2019

Title: 24 out of 36
Post by: FreeRoulette on Jul 09, 01:18 AM 2019
On average 24 numbers out of 36 spins.

Start with 1 unit on each number 1 through 36 and remove the winning number each spin for 36 spins.

You win 24 times = 24 x 35 = 840

And lose
36+35+34+33+32+31+30+29+28+27+26+25+24+23+22+21+20+19+18+17+16+15+14+13+(12x10) = 708

840 - 708 = 132  Winner

Is that right?

Title: Re: 24 out of 36
Post by: Bigbroben on Jul 09, 01:37 AM 2019
Have a look at the KTF thread, it's more or less the same concept.
But you are wrong with the 12x10 thing.  It might be 2x31, 3x28, 5x21, along with the others 1xnn.  And why would you play 36 nrs anyway?

With the knowledge that any nr can hit, it does not matter if you remove a hit nr or another.  So you could do like: remove a nr every second hit, or every third hit, or 8x35, 7x34,6x33,...  Or go down until 30, stay there (+6 per winning spin) until a loss then 29 until a loss...

All these variantes are fun to try and test.

But don't code it like I did!  You'll be deluded.!
Title: Re: 24 out of 36
Post by: ati on Jul 09, 02:02 AM 2019
Your calculation is for 24 different numbers in 24 spins. But the 24 number average is in 36 spins, so you have to add 12 more losing spins.

The losing spins can happen anywhere, you might lose five times in a row when you are still betting 25 numbers.
Title: Re: 24 out of 36
Post by: FreeRoulette on Jul 09, 03:04 AM 2019
Quote from: Bigbroben on Jul 09, 01:37 AM 2019
Have a look at the KTF thread, it's more or less the same concept.
But you are wrong with the 12x10 thing.  It might be 2x31, 3x28, 5x21, along with the others 1xnn.  And why would you play 36 nrs anyway?

With the knowledge that any nr can hit, it does not matter if you remove a hit nr or another.  So you could do like: remove a nr every second hit, or every third hit, or 8x35, 7x34,6x33,...  Or go down until 30, stay there (+6 per winning spin) until a loss then 29 until a loss...

All these variantes are fun to try and test.

But don't code it like I did!  You'll be deluded.!

I play 36 spins on the idea that 24 numbers will hit. So it is everything I lose which is the sum of 36 down to 12 plus the 12 spins for the last 12 units that did not hit. Which is 588 plus 144 = 732  but the win is 840. So still profit
Title: Re: 24 out of 36
Post by: FreeRoulette on Jul 09, 03:06 AM 2019
Quote from: ati on Jul 09, 02:02 AM 2019
Your calculation is for 24 different numbers in 24 spins. But the 24 number average is in 36 spins, so you have to add 12 more losing spins.

The losing spins can happen anywhere, you might lose five times in a row when you are still betting 25 numbers.

Good catch. So 588 plus 144 = 732 loss, but I won 840. This would be over 36 spins.
Title: Re: 24 out of 36
Post by: Bigbroben on Jul 09, 08:05 AM 2019
Best thing you can do: it's only 36 spins, so run a session and calculate.  See your plus and minus and count the amount of nrs that hit.