Poll
Question:
Do you understand the Rhythmatrix System Logic presented?
Option 1: Yes
votes: 2
Option 2: No
votes: 0
Hello Everyone,
Today is a very special day for you as this is a very special system!
I will begin with the simple version then afterwards when I explain the extras you will then be able to grasp the concept much more easily.
First of all, the tracking and ordering of the roulette results.
Start by splitting red and black numbers into separate strings, black numbers in one string and reds in another, as the results come just write the numbers into strings according to the colour.
Example
Red Number String 12, 3, 21, 27, 1, 25, 16
Black Number String 11, 31, 33, 8, 10, 17, 4
These are strings of red and black numbers.
The strings will be made up of unique numbers and eventually hit a repeating number that is already within the string.
Example
Red Number String 12, 18, 1, 32, 19, 23, 34, 18
Number (18) was the repeating number for this red string.
When a repeating number hits on a string it is time to end that string and start a new one for those colour numbers.
This way of tracking the numbers into strings until the repeating number hits will always be the same and never change.
The logic behind this is based on the law of the thirds, we would expect to only see a maximum average of around 12 unique numbers then get a repeating number that is already in the string.
The truth is the lengths of the strings are generally half this size and after thousands and thousands of fully recorded strings we found that total string lengths of 5 numbers hits the most from all recorded strings, this is only 4 unique numbers then the repeating number for a total recorded string length of 5 numbers.
We are tracking numbers into separate strings depending on which group they belong to either reds or blacks and then recording the strings lengths.
Example
Red Number String 7, 34, 14, 12, 18, 7 String Length --> 6
Length = Total numbers in the recorded string.
Now... Lets take this a step further with positions.
Positions are a position from which the repeated number came from within the completed string.
Example
Red Number String 7, 34, 14, 12, 18, 7 String Length --> 6 - 1 <-- Position
Length 6 and Position 1
This means the string was six numbers long and the repeating number was the first number/position that came in the string.
String lengths can range from 2 to 19
Example
12, 12 (2-1)
This is the shortest possible string length of two and repeated from position one.
23, 21, 18, 12, 14, 27, 19, 1, 25, 32, 3, 5, 7, 9, 16, 30, 36, 34, 18 (19-3)
This is the longest possible string length of nineteen and repeated from position three.
Below are examples of full recorded strings
R) 7 1 36 21 30 32 12 36 ( 8-3)
B) 26 33 2 24 35 35 (6-5)
R) 21 36 36 (3-2)
B) 26 8 31 33 35 15 15 (7-6)
R) 7 30 19 1 34 34 (6-5)
B) 2 6 29 15 17 17 (6-5)
R) 1 7 27 30 30 (5-4)
R) 7 18 3 21 18 (5-2)
R) 19 12 25 34 5 36 19 (7-1)
B) 11 4 10 31 13 31 (6-4)
R) 16 19 14 36 1 12 5 16 (8-1)
B) 20 13 33 31 35 24 4 20 (8-1)
B) 29 2 13 29 (4-1)
B) 31 31 (2-1)
R) 25 21 9 23 16 18 21 (7-2)
R) 27 16 14 18 25 1 3 36 14 (9-3)
The strings are recorded separate and then logged with string results as above.
Once all this information is available we can observe what type of lengths and positions are likely to come and at what time!
From thousands of fully recorded strings something amazing revealed itself....
The data was put into charts and showed the positions were key to locating the single numbers!
I have attached two pie charts, please open and look at the positions chart.
Just in case there is a problem with these pic charts to load on forum I will also type the data.
From all recorded strings the positions results were as follows,
Position 1 Hit 28.2 %
Position 2 Hit 22.6 %
Position 3 Hit 17.4 %
Position 4 Hit 11.9 %
Position 5 Hit 8.1 %
Position 6 Hit 5.5 %
Position 7 Hit 3.0 %
Position 8 Hit 1.6 %
Position 9 Hit 1.0 %
Positions 10+ Hit 1.0 %
This shows the percentage hit for each position over all recorded strings.
Position 1 Hit 28.2% /This means that 28.2% of all strings recorded had a repeating number from the first number within the string.
Position 2 Hit 22.6% /This means that 22.6% of all strings recorded had a repeating number from the second number within the string.
Position 3 Hit 17.4% /This means that 17.4% of all strings recorded had a repeating number from the third number within the string.
Positions 1 and 2 combined have over 50% chance of being the repeating numbers for any string!
Positions 1, 2, and 3 combined have over 67% of repeating for string.
Positions are literally positions, these are not actual numbers, but the positions in which future spun numbers will fall into naturally, so if a string has ended and you start a new string the first number to come is the number that fall into the first position which is named position 1.
The second number within any string is position 2 and the third number is position 3 etc..
The numbers could be any numbers and the only numbers we need to know are the numbers which fall into the positions and in what order!
The most amazing part is knowing that the first two positions in every string hit 50% which is only two single numbers.
This is how to pinpoint only two single numbers with the positions tracking!
Now lets pretend we have tracked and located our two single numbers, what next?
The next part is entry and exit points for betting the two numbers.
String lengths and positions can help determine strong entry and exit points for our betting, we can't enter into a bet without knowing the numbers to bet on so first we have to wait for the first two numbers in the string then once we have them we can enter into the bet or start tracking for a strong trigger or triggers.
It would be logical to wait for say ten unique numbers then bet the positions but in all results these earlier positions hit more on the shorter strings.
It would be logical to bet all ten unique numbers after the 10 unique numbers but this can be costly when having to make too many bets on a bad run.
It would be logical to bet straight away, but then you can have a situation where the string runs all the way up to eleven or twelve in length and you have to make too many bets also the possibility of a higher position repeating.
It would be logical to bet mid range after four or five unique numbers and that is exactly what we do, waiting for five unique numbers helps to hit the sweet spot and settle you in consistent wins on the early positions!
The best way to attack the sweet spot is by keeping entry and exit times short to say only making four to eight bets per trigger.
Flat betting!
The consistency is so good it is possible to safely use a mild base unit progression.
These two numbers will then have 50% chance of being the repeaters for that particular string.
If we bet on three single numbers instead this gives 67% chance of one of them being the repeat.
So tracking 2 or 3 numbers from the beginning of each string then waiting for a certain amount of unique numbers in that hot string before betting those 2 - 3 numbers for 4 - 8 bets.
That's it, simple**
This is for red and black numbers only!
If you would like to get involved with the software project for this system please search for RHYTHMATRIX RS
Thank you for reading my post.
Bonjour,
je suis tres interressé car javais deja travaillé sur un tel systeme
je vous laisse mon mail : peeetou@hotmail.fr
bien a vous
Please feel free to ask any questions
Thank you
No B.S All I can say I have used this for over one month now and it works better than anything I have seen in 30 years playing roulette. End of.
🤔 🤫 🤭
I'm surprised at the lack of comments. This is the most solid I've seen in a while that got completely overlooked!
Position 1. 28.6%
Position 2. 22.6%
â€"--------------------------
String length 2. 4.9%
String length 3. 10.5%
--------------------------------
The question of relevance is,
What are the percentages of position 1 and 2 in detail format for each string length from 4 to 14.
11 sets of seperate data.
Make your deduction based on this detail data. Not the general one presented above.
As I wrote always, the devil is in the details.
Let me give you examples to demonstrate the point.
16 1 23 4 15 32 16 (6-1)
But when you look at the big picture details you get
35 16 1 23 4 15 33 16 (7-2)
0 35 16 1 23 4 15 33 16 (8-3)
14 0 35 16 23 4 15 33 16 (9-4)
And so on.........
If you do this in detail for every possible permutation, what do you expect to see? :question:
I think we already know the answer.
For each string length you should expect to see each position hit the same number of times (percentage) as any other position. It's combining the different string lengths which produces the different percentages.
Quote from: Joe on Aug 31, 04:59 AM 2020
For each string length you should expect to see each position hit the same number of times (percentage) as any other position. It's combining the different string lengths which produces the different percentages.
Correct. 👍
Position on a string length is not a new idea.
Quote from: Steve on Aug 05, 07:30 PM 2020Ultimately there are ways to beat roulette, but repeating strings on any rng or wheel with the same strategy, isn't one.
Steve is correct with his comment. He knows since he's tested it.
Cht as i understand steve doesnt agree that any other method except one based on physics can beat roulette until now and is available , but you have your own winning method based not on physics but something like markov chain,LOTT and other math stuff......so steve passed it or didnt he make his research in this special field? Whats your opinion about that? Thanks in advance 🙂
cht, I'm not defending this system because I haven't tested it, but at least two long time members here seem to think it has merit, and I assume that's because they've actually played/tested it (unlike Steve).
It's too easy to dismiss something because 'it's not a new idea'. It may not be new but it seems to be a new angle, and as you yourself say : the devil is in the detail.
Steve routinely trashes all systems based on trends repeaters, etc. And it's rather disingenuous of you to reference his comment, since you know full well that he would also dismiss your LOTT/Marcov Chain system.
@CLF7 & @Joe, ok here's why I wrote my posts today on this thread which came to my attention after Colbster's post.
Joe posted the facts about string probability which I agree is correct.
I reference Steve's comments from the other thread becos he sounded confident with his conclusion and he did say he tested this idea 15years ago that made his comment relevant.
OK lets remove his comment as biased, we all agree he trashes all systems. Fair.
Let me show you what I have.
I wrote a position tracker many years ago.
I am not convinced about the reason why any position will show up more often than odds.
I am open to listen to other peoples math and/or science explanation if they care to post on this thread.
RRBB is the premier expert on position roulette or string roulette that's called here.
He made many claims if you check out his threads.
I can confirm none of his claims stats are true. I wish they were.
There were many subscribers to RRBB's position roulette who are still active on this forum, I know who they are.
Their biggest problem is the when factor.
Can I test if the claimed average work ?
When I test something I do it thoroughly in detail.
Easy with the excel sheet I have.
I won't waste my time again. 8)
Rhythmatrix send me this to upload it because he is moderated and he cant answer and defend himself, his posts dont get approval
Which appears to demonstrate that string locations 1 and 2 hit (based on the relatively few instances he has posted) roughly 50/50 with those string locations beyond 2. Flat betting, 2 numbers at a time (4 if you are running both colors at the same time) for a limited length of time (as was suggested in the OP) is solid from the simplistic math side. This is very easy to track, doesn't require a staggeringly large bankroll, and hits at a regular interval. Get in, get out, enjoy the free drinks.
Quote from: cht on Aug 30, 08:58 PM 2020
The question of relevance is,
What are the percentages of position 1 and 2 in detail format for each string length from 4 to 14.
11 sets of seperate data.
If you have it broken down this well, it may serve no purpose other than to fine tune an already favorable bit of data to get an even more profitable entry and exit point, obviously at the cost of possible playing (and therefore, winning) opportunities.
Quote from: Colbster on Sep 01, 12:57 PM 2020
If you have it broken down this well, it may serve no purpose other than to fine tune an already favorable bit of data to get an even more profitable entry and exit point, obviously at the cost of possible playing (and therefore, winning) opportunities.
Can you or anyone explain why would position 1 & 2 hit at a higher rate than the others?
Joe wrote this and I wrote I agree. Nope I have not run tests which I can do easily if someone post an explanation why this presumed higher hitrate. What's special about position1&2?
Quote from: Joe on Aug 31, 04:59 AM 2020
For each string length you should expect to see each position hit the same number of times (percentage) as any other position. It's combining the different string lengths which produces the different percentages.
Quote from: cht on Sep 01, 08:31 PM 2020
Can you or anyone explain why would position 1 & 2 hit at a higher rate than the others?
Joe wrote this and I wrote I agree. Nope I have not run tests which I can do easily if someone post an explanation why this presumed higher hitrate. What's special about position1&2?
A special waste of time is what it is. Go out on the field and implement your game theory. It's like wanting know if you're shooting % is at 89 or 90 before you shoot the free throw.
Just shoot it.
Why don't you try recording some strings and see for yourself, the file provided earlier is totally legit and clearly shows positions 1 and 2 hitting much more than any other positions, this to me is obviously because position 1 has an opportunity to repeat on every length string where as higher positions sometimes never get a chance as the lengths of strings are generally quite low.
It's obvious why positions 1 and 2 hit more frequently when you actually do some testing instead of just being a negative know it all!
cht you're coming across as a cht.
Do some research before you start slating the basics as you're literally doubting the most solid part of the system.
Cheers
There was a academic paper published in the math journal few years back that hypothesise that spins after a certain spin length is more likely to appear. The length is 7 if I recall correctly. But there was no hypothesis about the positions on a string which can be tested easily.
Quote from: Colbster on Sep 01, 12:55 PM 2020
Which appears to demonstrate that string locations 1 and 2 hit (based on the relatively few instances he has posted) roughly 50/50 with those string locations beyond 2. Flat betting, 2 numbers at a time (4 if you are running both colors at the same time) for a limited length of time (as was suggested in the OP) is solid from the simplistic math side. This is very easy to track, doesn't require a staggeringly large bankroll, and hits at a regular interval. Get in, get out, enjoy the free drinks.
How we all wish this fantasy is true 👍
All these gamblers must be blind and stupid to miss such a mouth watering money making machine. Thank you and OP for pointing this out.
Quote from: RHYTHMATRIX RS on Sep 01, 09:08 PM 2020
Why don't you try recording some strings and see for yourself, the file provided earlier is totally legit and clearly shows positions 1 and 2 hitting much more than any other positions, this to me is obviously because position 1 has an opportunity to repeat on every length string where as higher positions sometimes never get a chance as the lengths of strings are generally quite low.
It's obvious why positions 1 and 2 hit more frequently when you actually do some testing instead of just being a negative know it all!
cht you're coming across as a cht.
Do some research before you start slating the basics as you're literally doubting the most solid part of the system.
Cheers
Good now that your post is approved.
Post on here the explanation why positions 1&2 carry higher probability to hit than the rest of the positions on the string.Or you have no idea.
I expect you to know since this is the most solid part of your system.
Tell us exactly.
At least I am open minded and prepared to listen. Shoot.
The logic behind this is based on the law of the thirds, we would expect to only see a maximum average of around 12 unique numbers then get a repeating number that is already in the string.
The truth is the lengths of the strings are generally half this size and after thousands and thousands of fully recorded strings we found that total string lengths of 5 numbers hits the most from all recorded strings, this is only 4 unique numbers then the repeating number for a total recorded string length of 5 numbers.
You posted this on the other forum.
This idea is no different from Winkel's idea except you merely split the data into 2 parts. This can be done for high low, red black, odd even, left right, top bottom.
The missing link in your claim is,
Why do positions 1&2 carry higher probability than say position 11 and 12 in a 12string length?
Provide this explanation. Convince us.
I don't believe people like Winkel, Steve, dyslexic, TurboG, rrbb and their large number of followers missed this position part since they looked at it from various angles more than a decade ago.
Quote from: cht on Sep 01, 11:55 PM 2020
Why do positions 1&2 carry higher probability than say position 11 and 12 in a 12string length?
1 and 2 obviously are more likely to hit than later because they have the advantage of more opportunities to hit. If you bet 1 number for 1 spin, you have a 1/37 chance of hitting. In 4 spins, the same number has nearly a 1/11 chance of hitting. As the spins increase, the odds of it not hitting become drastically less as demonstrated by (36/37)^x. Position 11 is 1/37, Positions 1 & 2 are at almost 50/50 to have hit by the time the 12th string rolls around.
Quote from: Colbster on Sep 02, 01:42 PM 2020
1 and 2 obviously are more likely to hit than later because they have the advantage of more opportunities to hit. If you bet 1 number for 1 spin, you have a 1/37 chance of hitting. In 4 spins, the same number has nearly a 1/11 chance of hitting. As the spins increase, the odds of it not hitting become drastically less as demonstrated by (36/37)^x. Position 11 is 1/37, Positions 1 & 2 are at almost 50/50 to have hit by the time the 12th string rolls around.
I think it's best members who are competent in math to discuss in detail from a math standpoint about the relevant probabilities on numbers on a string in the complete picture.
It's possible to calculate the exact probability of each position on a string.
Joe, why not you take up this project?
I am not convinced. There's nothing factual to compel me to look into this idea.
Good luck with this thread.
cht, if you know how to count? simply count the strings with positions 1 and 2 from the file provided!
If you can't count or can't be bothered you should buzz off back to your post of riddles and carry on with your pile crap you keep pushing trying to gain attention for your new YouTube channel.
Cheers
Hello there,
Long time lurker, 1st time poster....
CHT, why do you have to be such a rude arrogant tosser all the time? Just because someone isn't a math's genius it doesn't mean they aren't entitled to an opinion. It's screamingly obvious why position's 1&2 hit more. What gives you the right to demand a scientific answer from the OP as to why?
It's people like you that ruin forum's for the majority. Many people are just like me. We may not be Steven fricken Hawkins but we just enjoy playing around with Roulette in it's many forms.
So this method may not be entirely new. It is however a solid way to play. It's non-progressive, easy to follow, backed up by testing and FREE.
Instead of bashing the OP demanding he provides this and that why not help? If you think it's a load of BS tell people why. Just try and do it without sounding like a pompous prick if that's possible....