Because most wonÃ,´t know my good I start from the beginning!
The difference between Lotto and Roulette is that 1 "spin" gives us always 6 "different" numbers.
There will be no double like 6 and 6 or even a triple in one draw of six. We try to make an opportunity of that.
But still we count this way:
we have 49 diffrent numbers.
after the first ball we will have
48 unhit and 1 hit
after the second ball we will have
47 unhit and 2 hit
...
after the sixth ball we will have
43 unhit and 6 hit
there will be no double hits!
1/1/2000: 13 32 33 8 43 1
this draw will give us:
1
48 6 0
0 F0 F1 F>1
1 48 1 0
2 47 2 0
3 46 3 0
4 45 4 0
5 44 5 0
6 43 6 0
IÃ,´m fighting with copying the Excel-sheet. I will find a way.
So we start to make a statistic like shown above.
now we book our second draw
5/1/2000: 20 31 26 16 6 38
1
48 12 0
0 F0 F1 F>1
1 48 1 0
2 47 2 0
3 46 3 0
4 45 4 0
5 44 5 0
6 43 6 0
7 42 7 0
8 41 8 0
9 40 9 0
10 39 10 0
11 38 11 0
12 37 12 0
as we see, there had been a repeater possible, but none came up.
additional we open a second count-sheet which starts a new statistic starting with the second draw.
this will show (and it will ever) the same as the first 6 balls of the first spin
2
48 6 0
F0 F1 F>1
48 1 0
47 2 0
46 3 0
45 4 0
44 5 0
43 6 0
This is a pciture of the summary sheet.
I translated the R or unhit to F0
N the once hit to F1
and all Favourites to F>1
pls give me the third draw
Here it is. . .
8/1/2000: 49 43 14 41 7 11
So we will add these new 6 numbers to our 1st and 2nd statistic and we will open a third as well.
but what do we expect?
We know that the so called Law of third appears in every game that is bound to random factors.
So we expect that after 49 balls 2/3rd of the 49 numbers will have appeared.
This means 32 numbers and 2/3rd of them will have appeard more than once.
so we expect a combination near to F0=17 F1=19 F>1=13
but till now the summary sheet of our first 3 draws.
as we see we have our first repeater.
@mogwai
pls give the next draw.
But I will proceed tomorrow to give people chance to understand and ask questions.
br
winkel
No problem. . . :)
12/1/2000: 29 2 40 19 48 15
There seem to be no questions.
This is our summary-sheet after 4 draws
As you see some counts are marked, I will explain that later.
@mogwai
pls give me now the next 4 draws
br
winkel
15/1/2000: 10 29 19 43 30 26
19/1/2000: 42 21 8 30 36 13
22/1/2000: 12 3 41 22 35 38
26/1/2000: 8 28 22 6 43 42
:)
Thx Mogwai
here is the summary after 8 draws
As I said before this also reacts like the Law of Third
After 8 draws we should be at 18 or 17 sleeping numbers
like at Roulette after 2/3 of the trot of 37 at spin 25 we should have half numbers sleeping (18/19)
here with 49 numbers 2/3 of trot is 32 balls with 24/25 numbers sleeping
Hi Winkel - great thread - so how many previous draws do we need before getting numbers to pick?
Hi Akiraa,
as there were no questions I finished the basic-thread.
next will be number-selection
br
winkel
Nice!
I am looking forward for the bet selection!
My Best Regards
Very interesting thread Winkel..thank you
Thanks for sharing and looking forward to the next explanations.
:thumbsup:
Regards
Max
So letÃ,´s do our first speculations:
As we see if we watch 1 single draw of six balls we always end up at 43-6-0
As we watch every situation after 12 balls we see 4 out of 7 end up at 37
As we watch every situation after 18 balls we see 3 out of 6 end up at 34
As we watch every situation after 24 balls we see 2 out of 5 end up at 29
As we watch every situation after 30 balls we see 3 out of 4 end up at 24
As we watch every situation after 36 balls we see we end up at average at 21
As we watch every situation after 42 balls we see we end up at average at 18
As we watch every situation after 48 balls we see we end up at 16
So we speculate:
at col. 8 we expect 6 new numbers
at col. 7 we expect 3 new numbers
at col. 6 we expect 5 new numbers
at col. 5 we expect 5 new numbers
at col. 4 we expect 3 new numbers
at col. 3 we expect 3 new numbers
at col. 2 we expect 2 new numbers
If we expect 2 out of col. 2
and 3 out of col. 3
where should this additional number come from?
We have 19 F0 (sleepers) at col. 2 and
we have 22 F0 at col. 3
so the additional number has to be one out of the 3 numbers 16 - 20 - 31
see attachement
QuoteSo we speculate:
at col. 8 we expect 6 new numbers
at col. 7 we expect 3 new numbers
at col. 6 we expect 5 new numbers
at col. 5 we expect 5 new numbers
at col. 4 we expect 3 new numbers
at col. 3 we expect 3 new numbers
at col. 2 we expect 2 new numbers
so we can do that with all the differences:
we expect one # out of the difference between col. 2 + 4
two # out of diff. col. 4 + 6
one # out of diff. col. 5 + 8
If we have same diff. we jump to the col with the higher amount of F0
So we speculate that 5 numbers of the next draw will be selected out of these numbers.
This is only the first step of the way to select.
We will test this speculation
@mogwai: Pls the next 6 balls
br
winkel
Here you go Winkel!
29/1/2000: 20 23 10 39 7 1
In the Box you see the selected numbers
Green is the new draw
So we hit 3 numbers out of 24 selected.
We will test this short selection several times to see what is developing.
The biggest problem is to combine the numbers in a way we get a win.
first a new speculation in tis way we try to learn
we expect:
2 of col. 2
2 of col. 3
3 of 4
4 of 5
4 of 6
5 of 7
5 of 8
6 of 9
in the box we now have 29 selected numbers.
@mogwai pls the next draw
2/2/2000: 6 7 13 2 20 38
:)
Now we have hit 4 of 29 selected.
When you look at image 137 and 139 you will see:
at 137 we missed 3 numbers of col. 1 + 2
at 139 we missed 2 numbers of col. 10
we will miss numbers of the "old" columns if a "longsleeper" is hit
we will miss numbers of the "newest" columns if there are fast "repeaters".
the newest tables
as our datas exceed we can make a statistic of averages
read:
30 25 18,17 5,83
31 24 19,2 5,8
after 30 Balls we have at average 25 F0 18.17 F1 and 5.83 F>1
We take at every col. the last datas and calculate how many new # should appear to reach the average!
dear winkel
I am interested in this topic, like somebody said in the first, I have too never bought a lottery ticket in my life as I have never ever tought this can be predicted.
Anyway, I have the draws of my country's lottery for 6/49 from 1958 to date, and from 5/35 from 1989 to date. How could I take advantage of this, as I don't fully understand this excell sheet in this thread. . .
Quote from: sekuritati on Aug 01, 11:54 AM 2010
...., as I don't fully understand this excell sheet in this thread. . .
pls tell what you exactly donÃ,´t understand.
Winkel can i say what exactly i dont understand too?
Quote from: bene126 on Aug 01, 12:08 PM 2010
Winkel can I say what exactly I don't understand too?
everybody is allowed to ask questions
Quote from: winkel link=topic=685. msg6174#msg6174 date=1280667536
So letÃ,´s do our first speculations:
As we see if we watch 1 single draw of six balls we always end up at 43-6-0
As we watch every situation after 12 balls we see 4 out of 7 end up at 37
As we watch every situation after 18 balls we see 3 out of 6 end up at 34
As we watch every situation after 24 balls we see 2 out of 5 end up at 29
As we watch every situation after 30 balls we see 3 out of 4 end up at 24
As we watch every situation after 36 balls we see we end up at average at 21
As we watch every situation after 42 balls we see we end up at average at 18
As we watch every situation after 48 balls we see we end up at 16
So we speculate:
at col. 8 we expect 6 new numbers
at col. 7 we expect 3 new numbers
at col. 6 we expect 5 new numbers
at col. 5 we expect 5 new numbers
at col. 4 we expect 3 new numbers
at col. 3 we expect 3 new numbers
at col. 2 we expect 2 new numbers
That is what i dont understand.
hi bene,
the difference we speculate between
As we watch every situation after 42 balls we see we end up at average at 18
As we watch every situation after 48 balls we see we end up at 16
is two new numbers
42 balls are statistically written down in col. 2 (or countpage 2)
br
winkel
More questions?
Shall I carry on?
Further interest on this?
br
winkel
PLEASE carry on Winkel. . . . . . . . . . .
iggy
Yes, please continue.
Tell me when you need next draw. . .
My Best Regards
Forgive me, but I don't understand either. I would LOVE to hear more!
Yes continue :)
Hi folks,
if you say "I donÃ,´t understand" I canÃ,´t help you.
pls say: I donÃ,´t understand how you count
or
I donÃ,´t understand how to select numbers
or
I donÃ,´t understand ....
So I can refer to my posts and my images posted to explain.
I was thinking about how to explain it better, but I have no idea.
So:
Did you understand to to count?
Did you understand that with every new draw you start a new counting-sheet
did you understand that after 10 draws you have 10 sheets
sheet 1 (transfers to col. 1 in summary-sheet) with 10 draws (all draws)
sheet 2 with the last 9
sheet 3 with the last 8
...
sheet 10 with the last draw only
pls confirm ord ask
br
winkel
to mogwai
we have to pick up people first to continue
Hi Winkel,
I'll explain where I don't completely understand.
I'll go back to your first post.... you give numbers 13 32 33 8 43 1
Yet I don't see where you use them anywhere.
this draw will give us:
1
48 6 0
0 F0 F1 F>1
1 48 1 0
2 47 2 0
3 46 3 0
4 45 4 0
5 44 5 0
6 43 6 0
Why do you call your column names 0 F0 F1 F>1 . Perhaps call it "hit" "unhit" etc. just so that everyone that is interested catches on, and then change it.
I am really interested in your theory and would like to understand. If you can perhaps illustrate on a Excel spreedsheet, but using the given numbers to indicate.
Thank you :thumbsup:
M
This my count-sheet with first three draws.
with every draw I start a new countsheet, which gives the following data
The counts in column I J K are transferred to a summary-sheet
Hi Winkel,
Ok, it's starting to make a bit more sense. What about everyone else? Do you guys understand?
Attached is a spreadsheet, that I put together with your info...
You'll see the green is what I assume should be right, and the orange is the way you have it in your screenshots. Why does the numbering change???
How many draws do you need before you can predict numbers?
Please explain more...
Regards
M
imagine we have only 6 numbers: 16 21 32 43 46 49
now number 16 appears: How many unhit numbers do we have and how many numbers hit once?
then number 49 appears: How many unhit numbers do we have and how many numbers hit once?
now number 16 appears: How many unhit numbers do we have and how many numbers hit once and how many numbers have hit more than once?
now number 49 appears: How many unhit numbers do we have and how many numbers hit once?
br
winkel
The results
now number 16 appears: How many unhit numbers do we have and how many numbers hit once?
5 - 1 - 0
then number 49 appears: How many unhit numbers do we have and how many numbers hit once?
4 - 2 - 0
now number 16 appears: How many unhit numbers do we have and how many numbers hit once and how many numbers have hit more than once?
4 - 1 - 1
now number 49 appears: How many unhit numbers do we have and how many numbers hit once?
4 - 0 - 2
Is this understood now?
Otherwise I neednÃ,´t continue if this basic isnÃ,´t understood.
I understand well :)
Yes Winkel I understand so far mate - please continue as I look forward to seeing how you get the numbers to pick and how to consistently hit 4 :)
So I try to explain the selection again:
this is our first column:
1
48 24 17
F0 F1 F>1
48 1 0
47 2 0
46 3 0
45 4 0
44 5 0
43 6 0
42 7 0
41 8 0
40 9 0
39 10 0
38 11 0
37 12 0
36 13 0
36 12 1
35 13 1
34 14 1
33 15 1
32 16 1
31 17 1
30 18 1
29 19 1
28 20 1
27 21 1
26 22 1
25 23 1
25 22 2
25 21 3
25 21 3
24 22 3
24 21 4
23 22 4
22 23 4
22 22 5
22 21 6
21 22 6
21 21 7
20 22 7
19 23 7
19 22 8
18 23 8
17 24 8
17 23 9
17 23 9
16 24 9
16 23 10
16 22 11
16 22 11
16 21 12
16 20 13
15 21 13
15 20 14
14 21 14
14 20 15
14 19 16
14 19 16
14 19 16
14 19 16
14 18 17
14 18 17
14 18 17
it ends up with 14 F0 and we canÃ,´t predict anything from that.
but the less open numbers we have the more it slows down hitting new numbers.
lets have a look at our second column
2
48 23 16
F0 F1 F>1
48 1 0
47 2 0
46 3 0
45 4 0
44 5 0
43 6 0
42 7 0
41 8 0
40 9 0
39 10 0
38 11 0
37 12 0
36 13 0
35 14 0
34 15 0
33 16 0
32 17 0
31 18 0
30 19 0
30 18 1
30 17 2
30 16 3
29 17 3
29 16 4
28 17 4
27 18 4
26 19 4
26 18 5
25 19 5
24 20 5
23 21 5
22 22 5
22 21 6
21 22 6
20 23 6
20 22 7
20 21 8
19 22 8
19 21 9
19 20 10
19 20 10
19 19 11
19 18 12
18 19 12
18 18 13
17 19 13
17 18 14
16 19 14
16 19 14
16 19 14
16 18 15
16 17 16
16 17 16
16 17 16
this ends up with 16F0
so we just predict it will end up at 14 F0, so 2 new numbers out of these 16 will appear
these are the 14 numbers of col. 1 and the 16 numbers of col. 2
new
0 1 4 5 9 17 18 24 25 27 34 37 44 45 46 47
2 2 4 5 9 17 18 24 25 27 32 33 34 37 44 45 46 47
If we prdict none new number of col 1 and 2 new numbers of col 2, so the 2 numbers only can be that 2 numbers that appear in col.2 but not in col. 1:
these are 32 and 33
now the same one with col.3 and col.2 but a little bit more elaborated:
at ball 54 in col 1 and 2 we see that we have 14 and 16 F0 = average 15
at ball 48 in col 1 and 2 and 3 we see that we have 16 and 16 and 18 F= average 17
target is: 17-15 = 2 new F0
if we compare we find: numbers 16 and 31
so we have now: numbers 16;31;32;33 for numbers that could/should appear
Is this understandable?
Yes got it so far - can I ask have you set up your count sheets with formulas so they feed into the other sheets? I am currently inputting and updating these manually and I think it will be quite easy to make a mistake!
Yes, I think I follow, but I was wondering about these numbers from your earlier posts?
this is our first column:
1
48 24 17
The numbers are the peak of each column, F0, F1 and F>1. Is there any significance to them in the calculations?
Similarly for column 2:
2
48 23 16
Thanks
Sorry, Mikeo,
I didnÃ,´t explain that on top there the max of each Col. F0, F1 and F>1
br
winkel
Hi Winkel
Nice Zone !
Ive loved reading this thread !
Are you makin Predictions on a certain Lotto ?
Regards
Hi Winkel,
I really want to test your system. Can we not perhaps create something in excel that oyu can just input every draw's numbers, then it will calculate new numbers for us.
Instead of doing this whole exercise every time?
Regards,
M
Sorry guys,
I am a bit unhealthy at the moment.
I will proceed in some days.
Quotethen it will calculate new numbers for us.
there is no way of being automatically calculated by a software.
It is like G.U.T it needs gamblers intelligence what and how mto bet.
donÃ,´t think you can beat any game with just using programs or math
br
winkel
there is no way of being automatically calculated by a software.
It is like G.U.T it needs gamblers intelligence what and how mto bet.
donÃ,´t think you can beat any game with just using programs or math
br
winkel
I 100% agree with those words.
Interesting! I too was into lotto system prediction and have developed one for one of my state's lottery. However, i could never make it work without being able to program it into a computer. So, it's been sitting. Once this thread comes back, i'll share some of my ideas, which, i bet, combined with Wincles method, it could be a killer. ;)
so anything new about the lotto? where is Herr Winkel, is he OK?
Winkel, did u lose interest in lotto? Danke
I was also hoping someone would like to get this fired up again...
Hopefully Winkel is OK!!!???!!!
M
hopefully
Winkel,
I understand completly you Gut bet strategy.
I do however have a problem understaining the quoite below would you kindly explain in more detail? Koolkat
Quote from: winkel on Aug 01, 08:58 AM 2010
So letÃ,´s do our first speculations:
As we see if we watch 1 single draw of six balls we always end up at 43-6-0
As we watch every situation after 12 balls we see 4 out of 7 end up at 37
As we watch every situation after 18 balls we see 3 out of 6 end up at 34
As we watch every situation after 24 balls we see 2 out of 5 end up at 29
As we watch every situation after 30 balls we see 3 out of 4 end up at 24
As we watch every situation after 36 balls we see we end up at average at 21
As we watch every situation after 42 balls we see we end up at average at 18
As we watch every situation after 48 balls we see we end up at 16
So we speculate:
at col. 8 we expect 6 new numbers
at col. 7 we expect 3 new numbers
at col. 6 we expect 5 new numbers
at col. 5 we expect 5 new numbers
at col. 4 we expect 3 new numbers
at col. 3 we expect 3 new numbers
at col. 2 we expect 2 new numbers
So:
Did you understand to to count?
Did you understand that with every new draw you start a new counting-sheet
did you understand that after 10 draws you have 10 sheets
sheet 1 (transfers to col. 1 in summary-sheet) with 10 draws (all draws)
sheet 2 with the last 9
sheet 3 with the last 8
...
sheet 10 with the last draw only
Guten Tag, Winkel!
nice to see u back, hope you well!
this is not off-topic i think so i am gonna move it to general discussion and stick it.
thanx!
Hi Winkel, Thank you for your response Yes i can count, at 45 i should be able to :twisted:
And yes i understand the different sheets What i don't get is what you mean by this statement?
we see 4 out of 7 end up at 37
Your Koolkat
Hi,
if you have several sheets of counting and you compare only the results after 2 draws you will find that (in my example) in 4 out of 7 you will have 12 hit an 37 unhit.
it is only the explanation of my count-sheet. Should be attached.
br
winkel
btw: I ment by counting not your ability to count but how the results are getting their counts
Hi Winkel,
Do you mean 4 out of 7 sheets?
Koolkat
Quote from: winkel on Mar 19, 02:57 PM 2014
Hi,
if you have several sheets of counting and you compare only the results after 2 draws you will find that (in my example) in 4 out of 7 you will have 12 hit an 37 unhit.
it is only the explanation of my count-sheet. Should be attached.
br
winkel
btw: I ment by counting not your ability to count but how the results are getting their counts
Yes
It has been a long time since I have been here :)
Winkel I hope you do OK, any chance we could continue/revive this thread??? I believe you covered only the initial stages of the bet selection. I could provide numbers If you wish to keep going! Please do tell!
My Best Regards
mogwai:
I think winkel will not appear for a while: :sad2:
link:://:.rouletteforum.cc/index.php?action=profile;area=showposts;u=209 (link:://:.rouletteforum.cc/index.php?action=profile;area=showposts;u=209)
Oh crap... That's too bad.
Hi Winkel,
What I don't understand is there will be no diffenet numbers in column 2 as this column is just a reflection of column 1 other than the first 6 number drawn.
Koolkat
Quote from: winkel on Aug 07, 09:44 AM 2010
these are the 14 numbers of col. 1 and the 16 numbers of col. 2
new
0 1 4 5 9 17 18 24 25 27 34 37 44 45 46 47
2 2 4 5 9 17 18 24 25 27 32 33 34 37 44 45 46 47
If we prdict none new number of col 1 and 2 new numbers of col 2, so the 2 numbers only can be that 2 numbers that appear in col.2 but not in col. 1:
these are 32 and 33
32 and 33 are in line 2 (sorry col. is wrong) different to line 1
No worries Winkel its hard when you trying to explian to an audience.
Ok now, we assume there will be no new numbers in column 1 because?
at ball 48 we should have an average of 16 this is ball 61 how do work out the average?
Koolkat
it´s simpy the binomial distribution
Many Thanks Winkel. Bet selection if we calculate the averages of every column, we then find the difference in numbers correct?
If a column is currently showing more then average i.e average should be 16 at ball 48 but the column is showing 14 do we disregard this in our bet selection?
Koolkat
pls read again page 2 of this thread and you will find the answer
Gotcha, I understand now Winkel. Do we only Concentrate on the F0, or do we consider the others?
Koolkat
If you have a F0 in col. 13, they might be a F1 or F>1 in col. 6
Hi Winkel I have been playing some Pick 3 lottery for fun here in Virginia, take a look at this..
Pick 3 Lotto Strategy Guide
First Tier Numbers 049 058 059 067 068 077 139 148 149 157 158 166 167 229 238 239 247 248 256 257 266 337 338 346 347 355 356 445 446 455
Second Tier Numbers 039 048 057 066 069 078 129 138 147 156 159 168 177 228 237 246 249 255 258 267 336 339 345 348 357 366 444 447 456 555
Third Tier Numbers 029 038 047 056 079 088 119 128 137 146 155 169 178 227 236 245 259 268 277 335 344 349 358 367 448 457 466 556
Fourth Tier Numbers 019 028 037 046 055 089 118 127 136 145 179 188 226 235 244 269 278 334 359 368 377 449 458 467 557 566
Fifth Tier Numbers 009 018 027 036 045 099 117 126 135 144 189 225 234 279 288 333 369 378 459 468 477 558 567 666
Sixth Tier Numbers 008 017 026 035 044 116 125 134 199 224 233 289 379 388 469 478 559 568 577 667
Seventh Tier Numbers 007 016 025 034 115 124 133 223 299 389 479 488 569 578 668 677
Eighth Tier Numbers 006 015 024 033 114 123 222 399 489 579 588 669 678 777
Ninth Tier Numbers 005 014 023 113 122 499 589 679 688 778
Tenth Tier Numbers 004 013 022 112 599 689 779 788
Eleventh Tier Numbers 003 012 111 699 789 888
Twelveth Tier Numbers 002 011 799 889
Thirteenth Tier Numbers 000 001 899 999
Welcome to our Pick 3 Lotto Predictor Chart. It is only intended for use as Theory and not of fact (the Lotto fluctuates way too much for guarantees). It just may surprise you, though, with how accurate it can turn out to be when picking "Three numbers, any order". Let's read on to learn how to use it.
I have listed all of the available numbers in the Pick 3 Lotto to the right, broken down into what I call "Probability Tiers". With duplicated numbers excluded, their are 220 available numbers to pick from. What this means is that 0-1-6, for example, covers that number and also 6-1-0, 6-0-1, 1-0-6, and all other combinations of those three numbers. For convenience, I have also listed the numbers from left to right, lowest to highest. So if the numbers picked by your Lotto were 7-2-6, on the chart it would be listed under 2-6-7 in the Second Tier.
The available numbers are also broken up and seperated into tiers, thirteen in total. At the top is the first (and best) tier, and dwelling at the bottom is the thirteenth (and worst) tier. In general, the higher the tier is to the top, the more likely the number drawn will match a number from that group.
However, I did say that this was the general way to read the chart. Sometimes you may notice that numbers in a certain tier keep coming up in your Lotto. When I was testing this chart, the Texas State Lotto had four consecutive numbers drawn that matched numbers from the Eighth Tier (normally not that likely of a tier), while a California Lotto had picked 6 straight numbers out of the Third tier (that was not so suprising of a tier). Be aware of "Tier Trends" when studying past results!
Additionally, some of these tiers are not that far apart in probability. The top five tiers, in fact, are only seperated by a few percentage points each. But the top tier is still the most likely according to this theory.
Hi Winkel,
is there any chance to continue this topic?
Thanks