Quote from: bigmoney on Feb 20, 03:26 AM 2019
Gees sixth sense ,proofreaders hand others are calling u out by saying  your not clear and consise and  from what they have tested ...its not profitable  ....thoughts on that mate ?

None at all ..thought though more bashing to be honest from that system 6 months ago..

Hmmm great answer

Guys but i think that what 6th have saying it's really good, put directly on real money and +1000 units (playing with 1 cent unfortunately but results are results)  37 spins and stop loss are good and i think gives you discipline. Just thoughts.
Nico

Quote from: nichedelico on Feb 20, 09:01 AM 2019
Guys but i think that what 6th have saying it's really good, put directly on real money and +1000 units (playing with 1 cent unfortunately but results are results)  37 spins and stop loss are good and i think gives you discipline. Just thoughts.
Nico

Good job Nico, keep it up! 

Quote from: 6th-sense on Feb 20, 02:32 AM 2019

I like your idea of what you propose though and if it’s easily calculable please feel free to post it on this thread it would be interesting to look at ..

It's all based on permutation and combinations.

nPr = n!/(n-r)!   and nCr = n!/(n-r)!r!

Take two numbers and 2 cycles. 4 cases.

We can have 2 numbers ocurring no repetition

12
21

Number of cases = 2!/(2-2)! =2

Or we can have 1 repeater occuring

11
22

Number of cases = 2!/(2-1)! =2

Probability of a repeater = 2/4 = 50%

Take 3 numbers and a 3 cycle. 27 cases

We can have no repeaters, all 3 numbers come up

123
132
213
231
312
321

Number of cases =3!/(3-3)! = 3!/0! =6

We can have 1 repeater, 2 numbers coming up

122  212  221
112  121  211
133  313  331
113  131  311
223  232  322
233  323  332

Number of cases =3!/(3-2)! x 3!/(3-2)!2!
=  6x 3  = 18

Or we can have 2 repeats, 1 number coming up

111
222
333

Number of cases = 3!/(3-1)! = 6/2 = 3 ways.

Probability of 1 repeat = 18/27 = 2/3. Quite large already and only 3 numbers

Can do similar calcs all the way up to 37 numbers and 37 trials. The numbers get pretty big, pretty quick.

Greater chance of repeats are due to the fact that there are more ways to arrange repeating numbers in terms of permutations in a set than there are to arrange unique numbers or the same numbers.

But after the numbers 1 and 2 come up there is a greater chance of a repeat (1 or 2) than there is a unique (3). In fact twice the chance, but we don't know which number will repeat. So we have got nowhere in practical terms. It appears attractive to bet on repeats but that's just an illusion.

All that knowledge about thirds or permutation/combination formulae gets us no advantage whatsoever.

But agreed, it helps to generate inspiration. I'm just pretty sure it won't lead anywhere in this case

thanks firefox for the time doing this...

No problem.  I did the fours too, but an error somewhere, there should be 256.

It gets tricky as the numbers get large. 4 numbers can repeat 3 times or vice versa with everything around and in between. But the ways they can do so can always be calculated and compared to the total number of ways to get a probability.

Quote from: Herby on Feb 19, 12:40 PM 2019
Already the 2.nd sentence in this advertising page is wrong:
"A German roulette tinkerer published his way to look at roulette in several online forums and called it Great Universal Theory or short G.U.T. "

He was Austrian, I was in PM contact with him more than 10 years ago.

LOL
I always was German

Quote from: winkel on Feb 20, 04:45 PM 2019I always was German

Hi winkel,
you remember the Austrian math boy RCEC ?
don't know what happened to him.

Quote from: Herby on Feb 20, 04:54 PM 2019
Hi winkel,
you remember the Austrian math boy RCEC ?
don't know what happened to him.

Due to drug and alcohol abuse he is now mentally ill and in a psychatric hospital

Quote from: 6th-sense on Feb 17, 03:04 AM 2019
number 26 repeats..we bet 1st available space to right..which is number 27...

numbers 10..17..21..24..26..30..32..35..are taken we now add number 27 to this group as although not out we have a unit on it

Now this is what i call out of the box thinking.
If we ever find this HG it has to be a continuous PROCESS.
Maybe the solution is in there.

6th, do you still believe it can win every 37 spins permutation?

Quote from: Frodo on Feb 21, 02:06 PM 2019
Now this is what i call out of the box thinking.
If we ever find this HG it has to be a continuous PROCESS.
Maybe the solution is in there.

6th, do you still believe it can win every 37 spins permutation?

It’ll be two steps forward one step back...not every game is the same..that’s the truth..
That system I hope people can work with and realise that you can’t carry on betting indefinitely the empty boxes ..you wouldn’t be betting every number in hi and lo in the end..after all 18 numbers per side won’t show ..there are averages each side ..sometimes one is out more than the other...again just throwing it out there

It has to be contained in a cycle..

Quote from: 6th-sense on Feb 21, 04:19 PM 2019
It’ll be two steps forward one step back...not every game is the same..that’s the truth..
That system I hope people can work with and realise that you can’t carry on betting indefinitely the empty boxes ..you wouldn’t be betting every number in hi and lo in the end..after all 18 numbers per side won’t show ..there are averages each side ..sometimes one is out more than the other...again just throwing it out there

It has to be contained in a cycle..

6-th,

I had mentioned the idea of narrowing down the table, meaning maybe just focusing on hits in a dozen or say half of the table. When you are playing, are you using the entire table or wheel or playing shall we say in a more confined area shall we say.

Thank you

Quote from: 6th-sense on Jun 12, 07:13 AM 2018
Ok the basics is if you know what the average gaps between numbers at each stage you can work out what is expected to happen..how 1 standalone number will either become two or three or four...
That’s the basics ..there will be an average distance between number groups..
If you the average 24 numbers are near enough the normal and 12 unhit are normal...then in the vey1st pic you will see how many standalone numbers with no touching numbers are out...we think 12 unhit numbers are not going to come out and we know the average unhit ie empty blocks are only going to be so wide..then you can conclude that from the very 1st pic your definitely going to link some of them stand alone numbers up..becouse at the end of 37 spins you will only have the average standalone numbers left ..which means the unhit will be either side or in a small block..
This is the basics..
Towards balancing

I think this might the most important post in the thread. But I admit I am having a little trouble interpreting it. There is someway of playing the numbers out and connecting them. I am just not sure what the trigger is, maybe you are starting with two numbers as bookends and playing all numbers in between 12-16 numbers if that makes sense. Why? Because as we know there will never be 12 empty boxes in a row. The hits will expand in a line. Just need to figure out the starting point. Any ideas?

For sure the gaps are bound to be reduced in size as the spins go by.  Of course anything is possible but at the end of 37 spins, the widest gaps between blocks are 2 or 3, hardly ever 4.  Maybe with unbalance of distribution?  If at spin 10 there is 1 block of 5, 1 block of 2 and 3 standalone, play neighbours of standalones or play for a repeater in the main block?

Maybe this type of observation could result in seeing a new way of considering inbalance?