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A question for the members that are coding systems.

Started by Jordan, Aug 28, 08:48 PM 2010

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0 Members and 1 Guest are viewing this topic.

Jordan

Can we make a code to quickly RUN a LOT of spins to see if we will bet 3 times with the progression 1,1,2  a dozen or a column that has slept 2 times how much times it is hitting in till the 5th time?

there is a man in a forum of my coutry that claims that he is a roulette pro and the clues that he gives are leading to this system.

that he watch for 2 different dozens or colums and then he is betting the 3d with this progression. ;D

I tested 4 sets of 100 spins so far but a code will make everything quick.

results were

1)+8
2)+22
3)-12
4)+16

he claims that he is going for +15 chips in every visit.
and that only 1 time in 2 years it failed.
and the bR that he say that it needs is 40 chips.

He is also telling in every post that his system is bazed on maths and that only with maths we can win in Roulette :D
He is speaking of 3 consecutive betting spins and that he bets on Dozens or Colums.

He insits that the -2.7 is only for 1 spin betting.and that the 3 consecutive spins aren't efected by it....hahaha

He also says that with this system u need pleanty of desaplin not to get out of the system wile u play and also huge patience...
all these clues are reminding of 1 famous scam!
Do u think that he came in my country? :o :D

Jordan

I asked him why all these 2 years he is betting only with the minimum table bet (5 euros) and he doesn t bet now with 50euro chips after so many winning sessions...
and he told me that with 50euro chips not only this system isn t passing but not even the same teh GOD :D

Jordan

He is probubly a scam but I will give you his clues anyway.

1)I don't bet on red or black(he means all ecs)
2)I do bet on the ouside bets(here the outside bets are the ECs and the DOZ and COL)
3)The only way to beat Roulete is with maths(winwithmath...I gues there are a lot of them!hahahhaha!)
4)It needs huge parience and desaplin)
5) the persentage of losing is 99.9%(sometimes he tells 99%..some times 99.9% LoL)
6)I lost only 1 time in 2 years of plaing it
7)BR needed 40 chips
8)If you will think of the maths behind it you will see that indeed the perentage of failure is 99.9%)
9)I bet on 3 consecutice spins and not just 1 spin
10) the -2,7 is for the 1 spin and not for the 3 consecutive

That was all the clues....I think that they lead you to my conclusion..

what do you think

He also mentioned a story (because he claims that he is 60yo) that before a lot of years in a Casino ,there were some players that was playing small(liek him) everyday and they had systems that was making 50-100euros(with today money) and they were leaving the casino/
And that after the Casino manager noticed it,when he was informed that they were at the Casinos lobby,they were going there and was giving them 100 euros and was asking them to leave! ;D

what do u thik of all these?


buffalowizard

Hi Jordan

Not sure I understand. First you say it is a system based on the dozens or columns, betting on the third spin. You yourself have tried this. Do you think it has any merit?

Then later you state that it only involves a certain amount of fixed rules.

In any case, it sounds highly dubious. Especially that he still only uses minimum stakes. He can't be that confident in it!

BW

Jordan

what I 1st posted was the system that I can understadn that he is playing by reading his clues...

Later I posted the exact clues rules that he said......

and i asked u what do u think????

I can t understand what is ur confusion?

mr.ore

12/37+25/37*12/37+((25/37)^2)*12/37 = 0,69152863601366157977

It is hitting 69,153% of the time.

The progression needs 4 units (1+1+2), and so on average he bets
12/37*1 + 25/37*12/37*2 + ((25/37)^2)*12/37*4 = 1,35486545712988371863 units
per session. So after 1000 sessions we might expect him to bet 100*1,355 units = 1355 units on dozen/column chance.

68% of time his profit will end up in an interval <BOUNDARY(-1), BOUNDARY(1)>

BOUNDARY(-1) = -1355/37 - 1*(2+1)*sqrt(1355*12/37*(1-12/37)*1,355) = -97 units
BOUNDARY(1) = -1355/37 + 1*(2+1)*sqrt(1355*12/37*(1-12/37)*1,355) = +23 units


95% of time his profit will end up in an interval <BOUNDARY(-2), BOUNDARY(2)>

BOUNDARY(-2) = -1355/37 - 2*(2+1)*sqrt(1355*12/37*(1-12/37)*1,355) = -157 units
BOUNDARY(+2) = -1355/37 + 2*(2+1)*sqrt(1355*12/37*(1-12/37)*1,355) = +83 unit


99,7% of time his profit will end up in an interval <BOUNDARY(-3), BOUNDARY(3)>

BOUNDARY(-3) = -1355/37 - 3*(2+1)*sqrt(1355*12/37*(1-12/37)*1,355) = -217 units
BOUNDARY(3) = -1355/37 + 3*(2+1)*sqrt(1355*12/37*(1-12/37)*1,355) = +143 unit

It is quite possible for him to have positive profit, he just got lucky. No need for programming and simulations with such a simple case.

mr.ore

If his progression wins, he on average wins:

12/37*2+25/37*12/37*(2-1)+((25/37)^2)*12/37*(2*2-2) = 1,1639 units

with 69,153% probability. How should he really play if he wanted to retain his style - playing with 40 units bankroll and having similar probabilities?

There are three of my personal recommendations in a form of a tables which tells what he should bet according to a size of his actual bankroll. It is just another progression.

He always start the progression wit 4 units:

1) He prefer winning 1 unit per session with higher probability:

[tex]\begin{tabular}{clcccc}
bankroll&bet&W&L&Pwin&avg.return\\
0&no.bet&-&-&0.0000%&0.0000\\
1&1.unit.on.2:1&3&0&18.9308\%&0.8931\\
2&1.unit.on.2:1&4&1&38.2902\%&1.8290\\
3&2.units.on.1:1&5&1&58.3699\%&2.8370\\
4&1.unit.on.1:1&5&3&78.6224\%&3.8622\\
5&no.bet&-&-&100.0000\%&5.0000\\
\end{tabular}[/tex]

With this he has 78% probability of winning that one unit, much better than 69%.

2) he would like to play more risky, in order to get more from his 4 units:
[tex]\begin{tabular}{clcccc}
bankroll&bet&W&L&Pwin&avg.return\\
0&no.bet&-&-&0.0000%&0.0000\\
1&1.unit.on.5:1&6&0&16.2162\%&0.9459\\
2&2.units.on.2:1&6&0&32.4324\%&1.8919\\
3&3.units.on.1:1&6&0&48.6486\%&2.8378\\
4&1.unit.on.2:1&6&3&65.3031\%&3.8364\\
5&1.unit.on.1:1&6&4&82.1827\%&4.8619\\
6&no.bet&-&-&100.0000\%&6.0000\\
\end{tabular}[/tex]
There he has 65,3% probability that he would win 2 two units.

3) He wants to win 15 units per visit, while bringing himself 40 units, so his target is 55 units. He should follow this plan, starting on line(=bankroll) 40:

[tex]\begin{tabular}{clcccc}
bankroll&bet&W&L&Pwin&avg.return\\
0&no.bet&-&-&0.0000%&0.0000\\
1&1.unit.on.35:1&36&0&1.7305\%&0.9115\\
2&1.unit.on.35:1&37&1&3.4637\%&1.8253\\
3&3.units.on.17:1&54&0&5.2915\%&2.8219\\
4&3.units.on.17:1&55&1&7.0424\%&3.7541\\
5&1.unit.on.35:1&40&4&8.7804\%&4.6734\\
6&6.units.on.8:1&54&0&10.5830\%&5.6437\\
7&6.units.on.8:1&55&1&12.3542\%&6.5967\\
8&1.unit.on.35:1&43&7&14.0996\%&7.5215\\
9&1.unit.on.5:1&14&8&15.8243\%&8.4656\\
10&1.unit.on.5:1&15&9&17.5496\%&9.4393\\
11&4.units.on.11:1&55&7&19.4607\%&10.4132\\
12&1.unit.on.35:1&47&11&21.2155\%&11.3478\\
13&1.unit.on.35:1&48&12&22.9734\%&12.2850\\
14&1.unit.on.35:1&49&13&24.7356\%&13.2263\\
15&5.units.on.8:1&55&10&26.4631\%&14.2297\\
16&1.unit.on.35:1&51&15&28.2347\%&15.1774\\
17&1.unit.on.35:1&52&16&30.0101\%&16.1289\\
18&1.unit.on.35:1&53&17&31.7909\%&17.0856\\
19&1.unit.on.35:1&54&18&33.5774\%&18.0483\\
20&1.unit.on.5:1&25&19&35.3083\%&19.0226\\
21&2.units.on.17:1&55&19&37.1678\%&19.9916\\
22&3.units.on.11:1&55&19&38.9630\%&20.9633\\
23&4.units.on.8:1&55&19&40.7582\%&21.9350\\
24&1.unit.on.17:1&41&23&42.5107\%&22.8717\\
25&1.unit.on.5:1&30&24&44.2513\%&23.8783\\
26&1.unit.on.17:1&43&25&46.0179\%&24.8207\\
27&2.units.on.11:1&49&25&47.8127\%&25.7894\\
28&3.units.on.8:1&52&25&49.6218\%&26.7708\\
29&13.units.on.2:1&55&16&51.5099\%&27.7415\\
\end{tabular}[/tex]
second table
[tex]\begin{tabular}{clcccc}
bankroll&bet&W&L&Pwin&avg.return\\
30&1.unit.on.5:1&35&29&53.2447\%&28.7899\\
31&1.unit.on.17:1&48&30&55.0292\%&29.7486\\
32&2.units.on.11:1&54&30&56.8649\%&30.7560\\
33&2.units.on.11:1&55&31&58.6754\%&31.7420\\
34&1.unit.on.5:1&39&33&60.4389\%&32.7220\\
35&1.unit.on.5:1&40&34&62.2079\%&33.7353\\
36&1.unit.on.17:1&53&35&64.0289\%&34.7242\\
37&1.unit.on.17:1&54&36&65.8594\%&35.7231\\
38&1.unit.on.17:1&55&37&67.7049\%&36.7381\\
39&2.units.on.8:1&55&37&69.5503\%&37.7530\\
40&1.unit.on.5:1&45&39&71.3475\%&38.7680\\
41&1.unit.on.11:1&52&40&73.1784\%&39.7639\\
42&1.unit.on.11:1&53&41&75.0204\%&40.7719\\
43&6.units.on.2:1&55&37&76.9321\%&41.8129\\
44&1.unit.on.11:1&55&43&78.8024\%&42.8551\\
45&1.unit.on.5:1&50&44&80.6333\%&43.8973\\
46&1.unit.on.8:1&54&45&82.4992\%&44.9305\\
47&1.unit.on.8:1&55&46&84.3912\%&45.9921\\
48&1.unit.on.5:1&53&47&86.2570\%&47.0251\\
49&3.units.on.2:1&55&46&88.1751\%&48.1152\\
50&1.unit.on.5:1&55&49&90.0927\%&49.2046\\
51&2.units.on.2:1&55&49&92.0102\%&50.2941\\
52&3.units.on.1:1&55&49&93.9278\%&51.3835\\
53&1.unit.on.2:1&55&52&95.8971\%&52.5294\\
54&1.unit.on.1:1&55&53&97.8931\%&53.7043\\
55&no.bet&-&-&100.0000\%&55.0000\\
\end{tabular}[/tex]

He has 71,3475% probability of success with this plan. This last plan is what I recommend most. The plan is really simple, all what he needs to know is his actual bankroll and the table which tells him what to bet on. W and L columns tells to what line should he go, so as he do not have to count his bankroll. He can print it. Because there would be a lot of bets, I would recommend following some dealer's signature with this.

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