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H.P Johnson Method

Started by Le_Chiffre, Nov 22, 08:48 AM 2012

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Jordsie669

Quote from: rusa71 on Dec 29, 01:16 PM 2012
Great explanation! Thanks Jordsie669...Now I got this.

Good to hear that ;D!!!
Can someone code this into RX please?
I think this can work in the long run!

Jordsie669

I accidently posted twice how do I remove this post?

Le_Chiffre

Jordsie, thanks for the explanation.  I kind of got it from what you said earlier.  What I want to know is, the method from the pdf/what i originally posted.  How does that relate to this?  i.e the table consisting of 5s and 45s, then going up in 5s after a loss etc?...

thanks

Jordsie669

Quote from: Le_Chiffre on Dec 29, 01:42 PM 2012
Jordsie, thanks for the explanation.  I kind of got it from what you said earlier.  What I want to know is, the method from the pdf/what i originally posted.  How does that relate to this?  i.e the table consisting of 5s and 45s, then going up in 5s after a loss etc?...

thanks

Well the 5's and 45's were just his starting string and I mailed the author for explanation, because his post was really bad explained.
And what he said comes pretty much to what I posted, and it also does what it says (Only X amount of wins needed despite the many losses)
So I think that this is the real HP Johnson method.

Cheers, Jordsie.

Jordsie669

Now we only need someone to test this (code in RX perhaps?)
to find out if this is a winner in the long run!

Cheers, Jordsie.

Le_Chiffre

ok, thanks Jordsie.  I still don't quite understand why the original method had 5s and 45s....and not equal number of them.  but thanks for getting this explanation out of the author.

Jordsie669

Quote from: Le_Chiffre on Dec 29, 01:52 PM 2012
ok, thanks Jordsie.  I still don't quite understand why the original method had 5s and 45s....and not equal number of them.  but thanks for getting this explanation out of the author.

Because you can choose your starting string.

Le_Chiffre

ok, so ive tested this a bit on demo and it can still get out of hand easily.

are you just splitting the numbers +16 only on the last bet (last 2 numbers) or any numbers in the string that get to +16?

Jordsie669

If any of your numbers goes 16+ Then split them like:
String a.t.m:
9 9

String after loss:
9 9 9 9 (instead of 18 18 because it's 16+)

superman

QuoteCan someone code this into RX please?

I still see no bet selection? do you really think just having a money management is enough? the labby will not work UNLESS you have a solid selection to bet on, good luck.
There's only one way forward, follow random, don't fight with it!

Ignore a thread/topic that mentions 'stop loss', 'virtual loss' and also when a list is provided of a progression, mechanical does NOT work!

cofi

I have studied this mm.

In the beginning X wins is needed. But if (or better to say WHEN) the numbers become too high You have to split these numbers. So then You can have situation that instead X wins, Y wins is needed, and Y > X.

After a bad losing streak this will go out of hands. It is up to bet selection, although that will hapen sooner or later, but that will happen, for sure.

Jordsie669

Okay, I was playing for real money and I had a bad run but I tweaked the method to rescue myself!
I'll explain now, first let me explain my problem:
string after many losses:
16 16 16 16
string after another loss:
16 16 16 16 16 16

So now get the problem? In the method we needed 1 win to recover 2 losses! But now we need 2 wins to recover 2 losses!
So how fix it? Make the amounts smaller!
string tweaked:
16 16 16 16> 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4

So what what changed now? Well after another loss with the tweaked string, the string will become:
string after another loss (tweaked string):
4 4 4 4 4 4 4 5 5 5 5 5 5 5 5 5 (instead of 16 16 16 16 16 16)

So now again we only need 1 win to recover of 2 losses!
But obviously you don't want large strings so what you do in the future is:
When you have to split according to the regular system, you do the following:
SPLIT TWICE!!

So now when you have for example:
string:
16 16 (Hit 16+ unit limit)
make the string like this:
4 4 4 4 4 4 4 4
(OR YOU CAN DO STRING 4 4 4 5 5 5 5 INSTEAD, DON'T KNOW WHAT'S BEST YET!)


THIS WILL KEEP YOU IN THE 1 WIN NEEDED TO RECOVER FROM 2 LOSSES!!
Sorry for the many CAPS it was to help make it clear,
Cheers, Jordsie.

Jordsie669

If anyone else has ideas to tweak this method,
Feel free!! Anything could improve the system!

Cheers, Jordsie.

Jordsie669

By the way, the problem that you have to split twice only happens when all the numbers in the string
are the half of the limit, example:
8 8
8 8 8 8

But after you splitted twice (in that scenario only!!!), it will take a lot of loses before you have to split again!!
Unless the string became only 2 numbers again! (Can only happen after wins)

So now the odds are reversed!! (Unless you're VERY UNLUCKY)
This will give you a huge advantage!

Cheers, Jordsie.

Le_Chiffre

the method started off only needing 3 wins but with the +16 rule the method can end up just like any other labby method needing potentially LOTS AND LOTS of wins if it gets out of hand.


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