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Started by falkor2k15, Jan 16, 03:24 PM 2020
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Quote from: Person S on Feb 10, 05:09 PM 2020VDW - if you use it even for events with an edge, for example 75/25, after a while it also loses. I tried this approach while playing EC loops. Example RR / RBR / RBBVDW - looks like this: RRB - L.When statistics say that the EC will be the same as the previous one at 75%. Inserting this event into VDW, you need to make two bets since we donâ€™t know what rotation R will come in combination number 3 ( RBB).
Quote from: falkor2k15 on Feb 14, 12:42 PM 2020I tested playing vdw only on a color that started the 9 spin cycle, but the result is still break even without any negative or positive edge as per betting front runners in standard cycles.
Quote from: ati on Feb 14, 01:25 PM 2020That's interesting, I don't know why my results were different. I'm not sure how many spins you tested, I recommended at least 50K, because the break even period that you see in the middle of my chart is actually around 32,000 spins. But it's quite likely that I was just lucky, because I don't see the dependencies in that game. In the past few months I have really started to understand more and more the dependencies rrbb was talking about, and how every bet must be dependent on a previous outcome. I even tend to agree with him that to find out if a system is a winner or not, requires zero spins of testing. Just by the description you could tell if the system utilizes the dependencies between events or not.But unfortunately I have still not been able to create a system that has a steady win rate and won't collapse if an unlucky sequence of numbers come out.
Quote from: falkor2k15 on Feb 14, 12:46 PM 2020Could you elaborate? I under EC cycles is 75% defined by same. What's that got to do with vdw or encountering a loss or two bets? You lost me again...
Quote from: falkor2k15 on Feb 14, 01:37 PM 2020so how can you say that you don't see the dependency?
Quote from: ati on Feb 14, 01:46 PM 2020My guess is that he tried to utilize the statistical imbalance of an EC event in a vdw sequence. Unfortunately it cannot be done.We cannot have equal risk and reward ratio for two different cycle lengths. And we have to bet every spin. The 75% only applies to the set of outcomes, never to the next spin. We will always (?) have 50/50 chance of winning on the next spin. There are certain dependencies that makes question this, but for now it remains a fact that the next spin on any EC is always 50/50.
Quote from: ati on Feb 14, 01:56 PM 2020Think about this, the color that started the cycle, has over 50% chance to end the cycle. Therefore during the cycle, there is less than 50% chance to see that color. So in theory the other color should have more chance to win. That's why I said that I don't see the dependency. The result was the opposite of what I expected.The issue here is that above mentioned over 50% fact applies to number cycles, and not to a vdw cycle. There can be a repeat within the 9 spin, which would change what the outcomes are dependent on.
Quote from: Person S on Feb 14, 05:40 PM 2020As we know EC it is 50/50. But the cycles are already 75/25 in favor of the determining one. Using VDW, I tried to use cycles, since this is not an equally possible event, but an advantage event. But as I wrote this did not bring success, dispersion waves carried the win into the abyss. Remember the recipe - you need to combine 2 variables. One independent is events, the second is dependent. Which we are all looking for...