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Kattila

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a,b,c....   pattern 
In that streets groups trigger( 8 streets) example ,
group A have 3 streets , group B also 3 streets,
group C  have 2 streets at that point/trigger.
Bet the last two groups(ab , bc, ca, ab.....) , so against the pattern.
When lose because hit new street , put that street into
the corespondent group  according with the pattern ( cabc...)
c new, a new, b new, c new.... so when lose because hit new street
 the groups can grow until a max. of 4 street each , but we hope for a W before that.

In the ABCABCABC....pattern we have hit only position 3 and 6 (ex. AxxAxxAxx), that is why
bet for positions 1 and 2. If you want to bet less numbers(streets) than attack only one
position , 1  or 2 , not both.

Also can create EC bet s with streets, splits, straights.
Create chops ABABABAB.....then bet for change.... FTL,
or  AABBAABB.....bet for series of  3 ( BBB or AAA).

SWEET

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Thanks Kattila for your interesting methods,
will spend many hours, research them.
Thanks!.

SWEET

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Now,
What the trigger, so that in the next ,
"THREE SPINS,
DOUBLE DOZENS,
WILL HIT THREE TIMES
IN A ROW."
The hit/lose ratios,
of 3in-row/failure,
should around 7/3.

How the staking?
it a popular dd parlay.

br=5units,

lose=5,(total loss/season)

win+br=15
net win=10/season.

How to stake.
br=5units.

first spin, only 4u.
2u on each dozen
if hit, =2+2=2,total=6.

second spin
3u on each dozen
if hit 3+3=3,total=9

third spin
since 9/2=4.5.
add another chip
to make it 10u.

of hit=5+5=5,=15u
total win
=15-5br=10u nett.

SWEET

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OOX
OXO
XOO
OXO
OOX
OXO
XOO
OXO
OOX
OXO
XOO
OXO
OOX
maybe you would like this as your "event signature"???

number25

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OOX
OXO
XOO
OXO
OOX
OXO
XOO
OXO
OOX
OXO
XOO
OXO
OOX
maybe you would like this as your "event signature"???
  How is this Kimo Li signature event?   

SWEET

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  How is this Kimo Li signature event?
Number25,
I didn't say, this
 "his event signature".

I said,
"..maybe you would like this as your "event signature"???"

Event Signature,
is a pattern you bet, against or follow,
it never meant to has "edge", NEVER!
It only meant to avoid EXTREME VARIANCE,
and to have hit, within your PROGRESSION STRATEGY "EXPECTATION"!

eg.
If your intended progression , is, say,
Labby,( 0,1)
Then, your "event",
must always have hits,
that more than 33.34%,
or you need to cut loss!
There's never a strategy to hit 100%,
we must have a "recoupable " cut loss strategy.
eg.
bet next 20 spins, or cut loss,
thus 20x 33.34%=at least 7hit,or if hit less than 7hit, cut loss!
Thus at least 7hit/20spins, is the progression's math EXPECTATION!

UNTIL we truly understand this concept, we cant have a hg.
Hope we understand, before we move on.
Thanks.

CarpeDiem

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American roulette 2 set spins


35.   B O. H
2.      B E.  L

30.    R. E. H
11.     B O.  L   bet B

8.       B E.  L.   W
3.       R O.  L.      Bet L

15.     B O L.  W
31.     B O H     BET B/O/L

29.     B O H.   no Low loss bet
23.     R O H.   B/ O / H

27.     R O H
29.      B O H.  WIN BET O/H

27.     R O H. W
26.     B E H.   BET H/O

10.     B E L
35.     B O H. W. BET B/H

31.    B O H. W
34.    R E H.  BET B/H

35.   B O H. W
8.     B E L.   BET B/H

15.  B O L.  LOSS THIS SET
14.  R E L

35.  B O H
36.  R E H. NO BET

26.  B E H.
29.  B O H  BETB/H

8.   B E L.  LOSS
32. R E H.   BET B E H

8.  B E L
20. B E H WINNER

We would of stopped when in profit,  But we did win most of the sets!

Interesting stuff.
When you bet FTL ( follow the last) on EC, its nemesis is the RBRBRB / OEOEOE or HLHLHL sequences etc.
By clustering the last 4 spins  on 4 rows x 3
Calculating the sum of each appearance on the columns:
If an EC =2 no bet on that EC and no bet on its Opposite EC
If an EC =1 no bet on that EC, bet on opposite EC
If an EC= 3 or 4 bet that EC, do not bet on the opposite EC

RBRB/OEOE/HLHL etc becomes a no bet

Like in Number25' s example:

35.   B O. H
2.      B E.  L
30.    R. E. H
11.     B O.  L 

bet B (because B=3, R=1, O=E=2, L=H=2 )

Does this require a side bet or is this sufficient to win?

For EC, 2 at the power of 2=4, the no bet (equilibrium) is when both EC=2, bet only the EC that appear >2
For Dozens, 3 at power 2=9 spins
the no bet(equilibrium) is when all dozens appear each 3 times in a 9 spin matrix no bet,bet only the dozens that appear >3 times
For lines 12 at power2 =144 spins the no bet equilibrium) is when all lines=12, bet only the lines that appeared>12 in the last 144 spins.

Why wouldn't an approach like this win this game?

Look at number 3
Red Low Odd
1st dozen
1st street
1st line
And so on

Isn't this the famos cycle betting everyone was alluding to?
EC 4 spins
Dozens 9 spins
Lines 144 spins
Single numbers 1369 spins ( if you have the patience for it lol)

X at the power of 2, where x is the total number of unique chances.


mohitomish

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Interesting stuff.
When you bet FTL ( follow the last) on EC, its nemesis is the RBRBRB / OEOEOE or HLHLHL sequences etc.
By clustering the last 4 spins  on 4 rows x 3
Calculating the sum of each appearance on the columns:
If an EC =2 no bet on that EC and no bet on its Opposite EC
If an EC =1 no bet on that EC, bet on opposite EC
If an EC= 3 or 4 bet that EC, do not bet on the opposite EC

RBRB/OEOE/HLHL etc becomes a no bet

Like in Number25' s example:

35.   B O. H
2.      B E.  L
30.    R. E. H
11.     B O.  L 

bet B (because B=3, R=1, O=E=2, L=H=2 )

Does this require a side bet or is this sufficient to win?

For EC, 2 at the power of 2=4, the no bet (equilibrium) is when both EC=2, bet only the EC that appear >2
For Dozens, 3 at power 2=9 spins
the no bet(equilibrium) is when all dozens appear each 3 times in a 9 spin matrix no bet,bet only the dozens that appear >3 times
For lines 12 at power2 =144 spins the no bet equilibrium) is when all lines=12, bet only the lines that appeared>12 in the last 144 spins.

Why wouldn't an approach like this win this game?

Look at number 3
Red Low Odd
1st dozen
1st street
1st line
And so on

Isn't this the famos cycle betting everyone was alluding to?
EC 4 spins
Dozens 9 spins
Lines 144 spins
Single numbers 1369 spins ( if you have the patience for it lol)

X at the power of 2, where x is the total number of unique chances.

excellent first post, thanks

number25

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@ CarpeDiem

Hello,  I was. tracking the B R O E H L.
Then playing dominant of those choices. 

So If the bet was B & O & L .
I would of put chips on all of those numbers.

Good job on thinking out side the box!

Number 25

SWEET

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Guys,
Below,
a very interesting,
for us to ponder.
123=dozen1,2,3.

(Many thanks to raymanz)

Source: raymanz

66k spins euro

123 123: hit 31 times
132 132: 35 times
213 213: 30 times
231 231: 30 times
312 312: 26 times
321 321: 28 times
111 111: 23
222 222: 22
333 333: 26

123: hit 831times
132: 854
213: 824
231: 807
312: 771
321: 802
111: 774
222: 790
333: 795 times
unquote.

123123 mean
dz1,2,3,1,2,3 hit 31 times in a row.
123 appear 831times in 22000row of matrix3.
eg.
123,then
123.
this happened 31times

831-31-31=769matrix not repeating.
66000/3=22000
row of matrix3.


how could this data,
become useful for incorporating our event signature?

SWEET

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thus, if we,
say,
apply 123,123,123,123
as our

"event signature",

then,
apart from the pesky green,
nine losses in row,
will be, when
123,123,123 hit...

if 123, hit once, then the losses, may not hit, more than three times-in -row...

if 123,123 hit,
the losses in row, may not more than six-in-row...

thus, as in raymanz's
data,
if we apply 123,as
"event",
then
3in-row losses, may not
more than
831-31-31=769row/2200row.

and
6in-row, losses, may not
more than
31row/22000row

hope you understand.


SWEET

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if we take,
say,
123,
as a single "event",
then the probability to lose three times in a row, =1/27.
If we only have
123,
then it will sooner or later lose 3in-row, when 123matrix appear.(1/27), and when 123-123 hit, we lose 6in-row.
We have,
LLW
LLW
LLW,
when
121,122 ,hit.
LWL,
LWL, when
113,133 hit.
and
WLL
WLL, when
223,323hit.

Thus having more
eg.
123
312
231
have better math expectation hit.
and lose 9in-row
when the event repeat exactly...
How about
111
222
333
222
111 as your "event"?
We lose 9in-row,
when 111222333hit.


RayManZ

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if we take,
say,
123,
as a single "event",
then the probability to lose three times in a row, =1/27.
If we only have
123,
then it will sooner or later lose 3in-row, when 123matrix appear.(1/27), and when 123-123 hit, we lose 6in-row.
We have,
LLW
LLW
LLW,
when
121,122 ,hit.
LWL,
LWL, when
113,133 hit.
and
WLL
WLL, when
223,323hit.

Thus having more
eg.
123
312
231
have better math expectation hit.
and lose 9in-row
when the event repeat exactly...
How about
111
222
333
222
111 as your "event"?
We lose 9in-row,
when 111222333hit.

You are still doing the same thing you did a couple years back... I see no progress at all

SWEET

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Thanks Raymanz for your view.
Couple years ago, I didnt
understand , there will never, a betselection, that produce "edge".
When we understand, a progression, must matched,
"math-expectation",
 viv-a-vis bet-selection.

SWEET

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we could also bet single dozen,
matrix3,
with marthy,
4,6,9
=19br.

win=8,lose=19.

winning matrix=19
losing matrix=8
except green .
If,
say,
we bet only dz1,
then,
19matrix have dz1.
8matrix have no dz1.


Permutations with repetition (n=3, r=3)
Using Items: A,B,C

List has 27 entries.
{A,A,A} {A,A,B} {A,A,C} {A,B,A} {A,B,B} {A,B,C} {A,C,A} {A,C,B} {A,C,C} {B,A,A} {B,A,B} {B,A,C} {B,B,A} {B,B,B} {B,B,C} {B,C,A} {B,C,B} {B,C,C} {C,A,A} {C,A,B} {C,A,C} {C,B,A} {C,B,B} {C,B,C} {C,C,A} {C,C,B} {C,C,C}







am I wrong somewhere?