The question is: how much does a player hope to want to win?

[Asterix]

1 before last
or the progression of the beast.
Hello everyone. Well, as you have already understood, I don't like playing losing progressions, but I also don't like losing a lot coins, to win a little sumn coins.
So I studied myself, a nice progression, which will not cause me to lose much.
It is based on the 1 third and 2 third progression or according to some writers it was attributed to Tomas Garcia. But Tomas Garcia loved playing Baccarat as much as Roulette. But here I have seasoned it into my system.

So according to the progression, the player divides his game capital into multiple small fractions.
Which gives with a basic progression of 9 coins first spin it bet with 3 coins and second spin
 with 6 coins.

i have call it Beast Progression, yes because, here should come a real beast in counter spin, to make me lost my progression.

1-1-1-1-1-1-1-1-1-1-1-1-1-1-1 (So on 15 spin it bet each time with 1 coins)
1 coins yes because here i should win minimum 1 coins and maximum, humhum, 8 coins
But before i raise up to 2, here so 2 coins value should go same 15 spin = 30 coins, so the player should win with 1 coins, 30 coins. So player have the minimum money capital to play 15 spin with 2 coins, and only i have won 1+2 so minimum 60 Coins, so i can go on next bet Step with 3 coins to win +45 new coins, and with +105 coins, i would playing step 4, so with 4 coins 15x to win +60 coins.

1-2-3-4 this is basis start progression from d'Alembert. But to raise to value of 10 coins
Basis 1+2+3+4+5+6+7+8+9+10 = +55 coins or +56 coins if we add 1 more time to win value.
Fibonacci = 1+1+2+3+5+8+13+21+34+55 = +143 ok
But, it not enough to me: So i have a bit transform it.
1+1+2+3+4+9+16+29+54+99 = +218 coins ok?

So: 1x30 coins
2x 30 coins
3x 45 coins
4x 60 coins.

So to now the total win = 165 coins
To play 15x9 = 135 coins, so i have it.
So next step is 16 coins and we have won 165+135 = 300
and to bet 16x15 = 240 coins
So by have won 240 coins more = 540 coins win
To play 29*15 = 435 coins more = 540+435 = 975
To play 54*15 = 840 coins more =840+975 = 1815 coins
And the 10 step = to play with 99 coins 15x = +1485 coins +1815 = +3300 coins wining.

To make a tyrannosaurus Rex beast, so with 1 coins should win 120 coins, before going to step 2 coins bet, here with 2 coins should win 60x....

So by level or step 10, the player win not +3300 but +13200 coins wins.
But this is realy too long to play (not 1 day but in more days or in 1 week), so each new days, should follow with old progression and playing bet side or system.

And to transform a unloos progression, so american labby unloos. wo in 1963 one player have won +19300 Francs in casino from Nice on 6 hours gaming.

1-1-1-2-2-2-2-2-3-3-3-3-3-3-3-3-3-4-4-4-4-4-4-4-4-4-4-4-9-9-9-9-9-9-9-9-9-9-9-9-9-

[Asterix]

ok i have try it with a difficult day series.
pffffff, yes is sure with progression Beast, i speak only on basis 15 spin. on more as 130 spin.
I am only so on win +22 coins to 159 spins. Another variant wo i have test it, was to play only if i win on 1st spin, so i follow new 1 spin to win.
If i lost,1, so i have follow with 4 another try to win +1 coins, so i won many yes of this +1, but win was too short, to realy can say it is a powerfull progression. The progression is too long flat, so to have more win, it should only to make risk. yes, on 15 spin, the maximum lost which i reach was -1 coin. So it need many spins, too many, to reach the 10 level, and so i don't can say it realy a good progression.
Yes why not with high Bet coins value, so with 100 per coins here 22 or 23 coins win, this are good to play.

To compare it with Unloos or Inverted labby, so in win mode. But here variant with 5 won before go to next value, here i have reach +44 coins with 100 spin play.
I have test it another short variant, with 3 spins, but here the break is too high risk. With 5, no risk to break or loss(here by me give a warning with game 12/16 lost, and so i have only one coin to reserve, so -12 one spin, another -16 and with -20 my party was finish), but here come back long endless flat attack, to win +1 coins more, because +1-1+1-1 etc...and after i comme back from -16 to +20 with a serie win.

So i can only rating, so another old player have announced, play only short time, don't would reach a days win party. on one day here the risk is too heavy, as what else progression you use, as the break from counter series coming.

So with unloos labby, here with 4 time 0 coming out, to win this +43 coins, so as more flat, so it give to play nothing real start to play more as 1-4 1-5 1-6.

or to compare another tier et tout as writer have says was Garcia playing method.
Here my variant was 1-1-1 and 2-2-2 so six chance to win, but here necessary to win 3 time so to have enough money to been able to calculate next betting step.
here same missadventure, one time i was to play with last coin high value.
So here i have won or control it only to 60 spins, and i have won +3 +6 and +9 also won +18 coins. So here new bankroll should calculate to can play 4-4-4 and 8-8-8.

[Asterix]

  With Martingales, we attentive players know well that martingales pay little and cause you to lose a large amount of money in the event of a severe loss.

Basis Paroli 1-2-4-8-16-32..... So each time we are able to win only +1, if this are on first wining spin, or if on 9 spin, you win. And here the 9th. spin should are last betting in positive win value.

Any player have transform it to 10th. spin. with sequence 1-1-2-4-8-16-32.... so with second winning spin, so he will play with the bank's money, not his own money.

but when is it if instead of playing the double of the value the first time, we would only play it with the double of one of the other values, we would always arrive with a total of 10 spins.

so as 1-2-2 or 1-2-4-4
yes it correct:
-1 =-1
-2 =-3
-2 =-5
and here on 4th.
+4 =-1
+8 =+7

To compare
-1 =-1
-1 =-2
-2 =-4
+4 = 0
+8 =+8

and with:
-1 =-1
-2 =-3
-4 =-7
+4 =-3
+8 =+5

And with basis sequence here player have only win:
-1 =-1
-2 =-3
-4 =-7
+8 =+1
+1 =+2

And if now,we would play double sequence, what happend?
Sure here, the player should lost double on his money, but only on 20th. spin

-1= -1
-1= -2
-2= -4
-2= -6
-4= -10
-4= -14
-8= -22
-8= -30
-16= -46
-16= -62
So the player if by basis sequence on 10th. spin lost. it have lost:
-1
-1
-2
-4
-8
-16
-32
-64
-128
-256 old -255 = -511

So with transformed sequence to double, here only if the player lost 20 spin it lost double = -1022
But series of 20, don't each day comming out.

But to secure better, yes, you can transform it to triple sequence.
Because with double sequence:

-1 =-1
-1 =-1
-2 =-4
-2 =-6
-4 =-10
-4 =-14
-8 =-22
-8 =-30
-16 =-46
-16 =-62

So on 11th spin win
+32=-30
+32= +2
But with losse= =-62
So as exemple if player have play Odd, E-E-E-E-E-E-E-E-E-E-O-E-O, so with this pattern, player don't need to bet 64.
-1 =-1
-1 =-2
-1 =-3
-2 =-5
-2 =-7
-2 =-9
-4 =-13
-4 =-17
-4 =-21
-8 =-29
+8 =-21
-8 =-29
+16 =-15
-16 =-31
+16 =-15
+32 =+17

This would mean, the player can play to 30th lose spin, before it lose -1533 coins, so it sure, here player would play triple secure martingale should have a bankroll from 1533 coins, or bankroll from 1022 coins, if it would play double secure martingale.

But to play martingale, so as you can see, you don't are able to win heavy sum, only bit of money part, from player have to bet to win minimum.

[TRD]

0.2 - 0.3 units/spin.
 As a base layer.

Pressing on the base unit + compouding escalates thst over time to much more.

[bellamysuthur]

In the world of eSports, a player's desire to win is often fueled by multiple factors, extending beyond mere monetary gain. While the prize pool certainly serves as a tangible incentive, many players are driven by a passion for competition, the pursuit of excellence, and the desire to leave a mark on their respective game's history.