Below is test of ten million trials to see when a repeat occurs ...

[birdhands]

I think the idea is that 5 numbers will repeat in 8 spins.  Plus the high/low thing, which I don't understand.  It seems to me that if we have 5 high in a row then either the chances are 50/50 that high will hit again or they are in favor of low, since a run of 6 is less likely than a run of 5.


Sam

[ego]

I think the idea is that 5 numbers will repeat in 8 spins.  Plus the high/low thing, which I don't understand.  It seems to me that if we have 5 high in a row then either the chances are 50/50 that high will hit again or they are in favor of low, since a run of 6 is less likely than a run of 5.


Sam

Sam the idea was that if we get repeats after previous five numbers with no repeat with regularity - then if i would only pick high/low numbers using previous five does should also with same regularity also get one repeat - then i ride two horses regarding probability - as one as follow the the previous five high or low to become a serie of 6789 witch is as you state a 50/50 situation - but we have one extra parameter in our favour - repeats appears at 6789 with regularity and is one reason why some one would not play against as follow the previous five high low with no repeats should be a better option.

The question is witch attack window is best - 3 or 4 attempts.
Let me illustrate this with out using high/low and just use regular numbers with previos five.
Today's file from random org ...

33
0
21
27
22 Previos five numbers with no repeat

6
28
11
7  Attack four times no repeat

7
35
23
10
5 Previos five numbers with no repeat

25
22
23 Attack three time one repeat one win

21
29
1
27
32 Previos five numbers with no repeat

23
9
15
27 Attack four times one repeat one win

6
10
22
25
35 Previos five numbers with no repeat

7
3
22 Attack three times one repeat one win

Now it should not be any difference if i add one extra parameter and only clustering high/low numbers with previos five with no repeats - witch then should apper with same regularity and give us two hourses to ride as we would only play high/low as previos five with no repeats.
Is like playing even money bets using two parameters of probabiltiy.

7 attacks with previos high/low had 3 with repeats among the next 4 attempts for attack.
6 won and one loss.

25
22
23
21
29 Previos five high numbers with no repeat

1 Low Loss
27 High Won
32
23 Repeat

8
9
4
18
6 Previos five low numbers with no repeat

21 High Loss
11 Low Won
7
22

13
4
14
5
10 previos

27
34
30
27

2
16
6
13
12 previos

22
12 repeat won
24
6 repeat

4
2
1
8
9 previos

35
25
21
12 won

18
1
15
3
12

8 won
23
19
15 repeat

32
36
35
22
34 previos

4
30 won
14
17

Maybe this that i show is not the ultimate way using two parameters - but i find it intressting