Ok, so I haven't posted for some time now...work...family etc. etc.


To get back into the swing of things I started reading up, playing around and using bits and pieces I found all over, to form what I think might be worth while.


I call it - the Inverted Repeat 6 (Registered Trademark bla bla bla    just kidding!)


Each line (double street) is marked with a number - 1-6

For example - if the number 11 fell - we would be in line 2
If the number 26 fell - we would be in line 5


We track 6 spins - each spin is written down from top to bottom as a line number
(This is just an example - you will only be writing down the corresponding line nr. 6)



35| 6
28| 5
32| 6
20| 4
7  | 2
29| 5


We then start betting after the 6th line number, that the first number will NOT be a 6.
So place 1 chip each on line 1,2,3,4,5 = total 5 chips.


If we lose this bet, we double the chip count on each line, BUT we move to the next bet.
The line number is 5, so we bet 2 chips on each line 1,2,3,4,6


And so on and so forth...  a bit of magic comes in .... I don't think it's that easy to repeat your previous pattern - so for this to fail, you would need to have an EXACT repeat of the previous string of line bet numbers. Almost similar to last weeks lotto numbers the exact same this week 


Zero is ignored,
Progression is 1,2,3,4,5,6 chips - for a total of 105 units.
Only play for for 1 win per 6 numbers. The then played line becomes the next trigger.
In 48 spins you can walk away with +6, perhaps more.


If you had to have an exact repeat of the previous line, I would call it a day.


I've attached a picture to try and explain better. I have circled a "win" with a red circle to show how this works. (Zero has been marked with X) ((Actual numbers))


Please feel free to ask any questions, give any feedback or criticism.


Regards,
M

Hi Maui,

I'm a big fan of this type of betting utilizing strings of numbers sectors etc.

However isn't the progression wrong on this - you don't recoup your losses if lose previous bet.

Many thanks for the idea though.

Paulus

You risk up to 105 units to win 1 on first step or lose more and more on any other? O.o

And these repeated situations will occur more then once in 105 sessions, most probably.

Another perfect session.   

Quote from: Maui13 on Apr 05, 02:56 AM 2012
....Progression is 1,2,3,4,5,6 chips - for a total of 105 units.
Only play for for 1 win per 6 numbers. The then played line becomes the next trigger.
In 48 spins you can walk away with +6, perhaps more.

Hi Maui13,

At 5:1 odds using the progression you outlined, unless you win on first step, you will be in the negative quite quickly, namely:

                                       If Loss   If Win
Step 1 =   1   1   1   1   1   -06      01
Step 2 =   2   2   2   2   2   -10      -03
Step 3 =   3   3   3   3   3   -15      -12
Step 4 =   4   4   4   4   4   -20      -26
Step 5 =   5   5   5   5   5   -25      -45
Step 6 =   6   6   6   6   6   -30      -81
                                        -106   

Regards

B27

Bettor,


You are correct! I somehow stuffed up between all my notes... thank you for pointing that out.


Doing progressions has always been my weak point! BUT - I firmly believe that the odds are in our favor with this.


So can we play 1,3,36 perhaps for the first 3? Maybe I have to relook at the betting all together.
Should have picked this up.


EDIT - Perhaps Keep the progression as I had it, on a lose, step up the progression, then play it 2 times on that level to reach new high, then drop down the progression?
On a win up, lose down? Or vice versa? What would work the best?


Regards
M

Al things being equal you will have about 5 wins for every loss.  Discounting the zero that is.

So, I would step up the progression by 3 for every loss and step down 1 for every win.  You could step up by 4 or even 5 but things may get a little hairy if you hit a run of losses sprinkled with a few wins.  I would be comfortable with 3 up 1 down if you want to go with that type of progression.