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Please can I get help with some math.

Started by Ralph, Jul 30, 07:36 AM 2012

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Ralph

I use to play on multiball table at BV. I use then the same number of balls I got my self(2). The playing chase repeaters. I just pick the six latest numbers, bet 0.02, or 0.2 depending on the bankroll put for it.

The bankroll have to be at least 2000 units.

Every time I got new high, I reset to six latest numbers and on unit each number.

If I win and not reach new high, I spin witout changing the bet value. If I lose the spin I add one more chip on each number. Never decrease the bet, until new high, and new numbers.

I have found (got the feeling) the two ball wheel works a bit better than one ball wheel, playing this method.
I think It may be for reasons as, the balls, can NEVER fall on the same number.

If the payout is  36x  for the first ball, and the odds for the first ball to hit a number is 1/37.
The payout for the second ball is the same as the first, but this ball have one place less to fall into.

Am I thinking right? Can somebody explain the math here. One other reason for more hits is the fact it is two balls. But it is equal to two tables? i do not think so. Playing numbers include zero as an option, and the ball can not land in a slot occupied of the other ball. The odds may be the same as two tables, but you can get both balls on the same number on two tables, opposite to here.

On my English translation on my University diploma I am "Master of Divinity", so some kinds of math I never got into.
The best way to fail, is not to try!

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