A B C dozens and cycles explained

[6th-sense]

Not put a system on here for a very long time but after grassroots 123 i thought i would give my take on this.....
where to begin...this is for any group of 12 numbers only ..or dozens..columns or you split the wheel itself into 3 sections the end results will work the same....use 3 groups split into 12 of your favorite numbers it matters not...the principle will be the same...each group should be labeled a..b..c...i like that better than 1..2..3

so we have 3 groups of whatever numbers you have...a..b..c
now i,ll try explain this to the best of my ability...rouletteghost nearly did it this way but didn't get quite as far...aim is for 10 unit win then reset...the cycle of the a..b..c..will become apparent with simple tracking as you jot the results down....ok here we go ..i presume you will have your 3 groups of numbers labeled a..b..c...at hand...

okay i,ll give an example of results and how you bet and track the cycle..there are two ways to bet here...against the last two results in any given column...if you lose the two bets...you then transfer the play to the next available column...never bet same column if you have just lost the two previous bets above ..unless you win on next column....

OR you can bet for the cycle to repeat or not to repeat when due...on any given column...cycles are automatically made by the state of play of a repeat of a column...a cycle can be as less as 1 as much as 10...we only bet for or against the very 1st result for a cycle bet ... this is self explanatory as you play...sounds complicated but is probably one of the easiest systems you can come across.. can you tell rng from real wheel with this cycle method?

ok here is 60 spin result set in order  ..we will list these as they come out in there corresponding columns and give them there numbers as they come out in there trio group and how the cycle works..
ok 1st 12 results are b..b..c...c..a..b...b..a..a...b..b...b.

we jot this down as number 1 group is 1st result is B.then we put the next two letters in run b..c..
so 1=BBC we will bet against BC the last two letters if and when we get a B at the start of this column again

next three results are C.. a..b  we jot this down as 2nd group as its the 2nd trio out so 2= CAB we will bet against the last two letters if and when we an A at the start of this column again

SO WE NOW HAVE 1 =BBC   2=CAB

ok 3rd lot of results are out which are B a  a we now have a repeat of B column ...so we need to bet against the two 2nd letters BC and label this 3=BAA..we did win here as we bet against B coming out..

SO WE NOW HAVE            1 =BBC   2=CAB
                                         3=BAA   

so now we have group B as a cycle bet of 2.... thats the difference between 1and 3...so we could expect that group B will hit on the 5th..7th..9th..11th..cycle etc 

next out is BBB so again we label that trio 4=BBB ...we always bet against the result at the top of the group which for B is BC...we cant bet against the 1st letter b as that is where we place our trigger ie B...which has just come out...

so lets carry on with another 12 results ..a..b..c..a...c..b..c.a .b..b..a...c

next result is trio 5 so we label it 5=ABC ..no bets there as its 1st in its column...we will be betting against b..c.. when its triggered..
   
SO WE NOW HAVE     4=ABC    1 =BBC   2=CAB
                                                   3=BAA
next out is a..c...b..we would have put a in column a which triggers to bet against b then c if we would have lost or we would have bet on just B numbers to hit that 5th cycle  1st bet...or against..

SO WE NOW HAVE     4=ABC    1 =BBC   2=CAB
                                  5=ACB     3=BAA

column a now has a cycle of 1...thats the difference between 4 and 5...we would expect every trio that comes out to be start with A ...

next out is C A B ..we would have lost that cycle bet on column A as we would expect that cycle to run at 1..ie would have been the 1st formation of a trio...

SO WE NOW HAVE     4=ABC    1 =BBC   2=CAB
                                  5=ACB     3=BAA    6=CAB

we have now just lost on the C column AS WE HAVE A REPEAT OF AB....we will transfer that bet to the next available trio...we will not bet against this c column now until we either win or lose next two bets on next column A or B ...c column has now given itself a cycle of 4....2 from 6 =4..so we expect it to come out every 4th cycle so on cycles numbers 10..14..18..etc

next out is b..a..c..that cycle on b was due on the 7th cycle so we could have won that but lost cycle 1 on a..but still would have been up as we would have bet both...
SO WE NOW HAVE     4=ABC    1 =BBC   2=CAB
                                  5=ACB     3=BAA    6=CAB
                                                   7=BAC

we also would have won the transferred bet on the 1st spin result A....as we are always betting against the top row...

so simple way to bet ..shift bets about..and find the cycle...which you will see pretty much confirms to order in a lot of sessions..hope its clearly explained...

i find cycles with lower gaps between 1 and 3 are more accurate than larger ones

[NextYear]

Thanks 6th!

Will need some time to digest it, but have nice feeling when I see new topic from long term member.

[RouletteGhost]

Thanks for the mention

I will investigate this week