Idea for new strategy based on sleepers/uniques

[falkor2k15]

I've decided to track for 3 repeats as optimum then move to remaining positions to also try to reach 3 repeats:

Format is: Positions @ 3 repeats, Spin #, Appearance #s for remaining Positions/Sections

HighL

4

rb3 oe3 d2 c2 q2 ds2

OddE RedB

5

d2 c2 q2 ds2

Col

7

d3 q2 ds2

Doz

9

q3 ds3

Quads Lines

11

RedB

5

lh3 oe3 d2 c2 q2 ds2

OddE

6

lh3 d3 c3 q2 ds2

HighL Doz

7

c3 q2 ds3

Col

8

q2 ds3

Quads Lines

10

OddE

5

lh3 rb3 d2 c3 q2 ds2

RedB

6

lh3 d3 c3 q3 ds2

HighL Doz Col

7

q3 ds2

Quads

8

ds3

Lines

11

HighL

5

rb3 oe3 d2 c3 q2 ds2

OddE

6

rb3 d3 c3 q3 ds2

RedB

7

d3 c3 q3 ds2

Doz Col Quads

8

ds3

Lines

11

OddE

4

lh3 rb2 d3 c2 q2 ds2

HighL Doz

5

rb3 c3 q2 ds3

RedB

6

c3 q2 ds3

Col

7

q3 ds3

Quads

8

ds3

Lines

14

HighL

5

rb3 oe3 d3 c2 q2 ds2

OddE RedB

7

d3 c3 q3 ds2

Doz Quads

8

c3 ds3

Col Lines

9

HighL

5

rb3 oe3 d3 c2 q2 ds2

Doz

7

rb3 oe3 c3 q3 ds2

OddE RedB Col

8

q3 ds2

Quads

12

ds3

Lines

14

HighL Doz Lines

4

HighL OddE RedB Quads

5

d3 c2 ds3

Col

9

d3 ds3

Doz

10

ds3

Lines

15

OddE

5

lh3 rb3 d2 c3 q2 ds2

HighL

6

rb3 d3 c3 q2 ds2

RedB Col

7

d3 q2 ds2

Doz

9

q3 ds3

Quads

10

ds3

Lines

12

OddE

6

lh3 rb3 d2 c2 q2 ds2

HighL RedB Col

8

d3 q3 ds2

Doz Quads

10

ds3

Lines

15

OddE

5

lh3 rb2 d2 c3 q2 ds1

HighL

6

rb3 d2 c3 q2 ds2

RedB Doz Col

8

q2 ds2

Quads Lines

11

OddE

5

lh3 rb3 d2 c2 q3 ds2

HighL RedB

6

d3 c3 q3 ds3

Col

7

d3 q3 ds3

Doz

8

q3 ds3

Lines

9

OddE

4

lh2 rb3 d2 c3 q1 ds1

RedB

5

lh3 d3 c3 q2 ds2

Doz

6

lh3 c3 q2 ds2

HighL Col

7

q2 ds2

Quads Lines

12

HighL OddE

5

rb3 d3 c2 q3 ds2

RedB

7

d3 c3 q3 ds2

Col

8

d3 q3 ds2

Doz

9

q3 ds2

Quads

11

ds3

Lines

13

RedB

5

lh3 oe2 d2 c2 q2 ds2

HighL

7

oe3 d3 c2 q3 ds3

OddE

8

d3 c3 q3 ds3

Doz Col

9

q3 ds3

Quads

11

ds3

Lines

17

HighL OddE Col

5

rb3 d2 q3 ds2

Quads

6

rb3 d3 ds2

RedB

7

d3 ds3

Doz Lines

8

RedB

4

lh3 oe2 d2 c2 q2 ds1

HighL

5

oe3 d3 c2 q3 ds2

OddE

6

d3 c3 q3 ds2

Doz

7

c3 q3 ds2

Col

8

q3 ds2

Quads Lines

12

HighL OddE RedB

5

d2 c3 q2 ds2

Col

6

d3 q2 ds2

Doz

8

q3 ds2

Quads

9

ds3

Lines

11

HighL RedB Doz

5

oe3 c3 q2 ds3

OddE Col

6

q2 ds3

Lines

7

Doz

4

lh3 rb2 oe3 c3 q3 ds3

HighL OddE Col

5

rb3 q3 ds3

RedB

6

q3 ds3

Quads Lines

9

HighL Col

5

rb3 oe3 d3 q3 ds2

OddE RedB Doz

7

q3 ds3

Quads Lines

10

OddE

4

lh3 rb2 d2 c2 q2 ds1

HighL RedB

7

d3 c3 q2 ds3

Doz Lines

8

OddE RedB

5

lh3 d3 c3 q2 ds2

HighL Doz

6

c3 q3 ds2

Col Quads

8

ds3

Lines

9

HighL OddE

4

rb3 d3 c2 q3 ds2

RedB

5

d3 c3 q3 ds2

Col

6

d3 q3 ds2

Doz

10

q3 ds3

Quads

11

ds3

Lines

13

OddE

5

lh3 rb3 d3 c2 q2 ds3

RedB

6

lh3 d3 c2 q2 ds3

HighL Doz

7

c3 q3 ds3

Quads

8

c3 ds3

Lines

9

HighL Doz

5

rb3 oe3 c2 q3 ds2

OddE Quads

6

rb3 c2 ds3

RedB

7

c3 ds3

Col

9

ds3

Lines

13

OddE

4

lh2 rb2 d3 c2 q2 ds2

HighL RedB

6

d3 c3 q2 ds2

Col

8

d3 q3 ds2

Doz Quads

9

ds2

Lines

13

OddE

5

lh3 rb3 d3 c3 q2 ds2

RedB Col

6

lh3 d3 q2 ds2

HighL

7

d3 q2 ds2

Doz

9

q3 ds2

Quads

11

ds3

Lines

15

Col

4

lh3 rb2 oe2 d3 q3 ds3

HighL Quads

5

rb3 oe3 d3 ds3

OddE

6

rb3 d3 ds3

RedB Doz

7

ds3

Lines

16

HighL

5

rb3 oe3 d3 c3 q3 ds2

RedB

6

oe3 d3 c3 q3 ds2

OddE Doz Quads

7

c3 ds3

Col

8

ds3

Lines

11

HighL RedB

5

oe3 d3 c3 q3 ds3

Doz Quads Lines

6

RedB

5

lh3 oe3 d2 c3 q2 ds1

HighL OddE Col

6

d3 q3 ds2

Doz Quads

7

ds3

Lines

11

RedB Col

4

lh3 oe3 d2 q2 ds1

HighL OddE

5

d3 q3 ds2

Doz

9

q3 ds2

Quads

11

ds3

Lines

13

HighL RedB

4

oe2 d3 c2 q2 ds2

Doz

5

oe3 c3 q3 ds2

OddE

6

c3 q3 ds2

Col Quads

7

ds3

Lines

9

HighL Quads

5

rb3 oe3 d3 c2 ds3

Doz Lines

6

OddE Col

5

lh2 rb3 d2 q2 ds1

RedB

7

lh3 d2 q2 ds2

HighL

8

d3 q2 ds2

Doz

11

q3 ds2

Quads

13

ds3

Lines

19

RedB Col

7

lh3 oe3 d3 q2 ds3

HighL OddE Doz

8

q3 ds3

Quads

12

ds3

Lines

14

RedB

4

lh2 oe3 d2 c2 q2 ds1

OddE

5

lh3 d2 c3 q2 ds2

Col

6

lh3 d3 q2 ds2

HighL Doz

7

q3 ds3

Quads Lines

9

OddE RedB

6

lh3 d3 c3 q2 ds2

Col

7

lh3 d3 q2 ds2

HighL Doz

8

q3 ds3

Quads

9

ds3

Lines

16

RedB

4

lh2 oe3 d2 c2 q2 ds1

OddE

5

lh3 d3 c2 q2 ds2

HighL Doz

7

c3 q3 ds2

Col Quads

8

ds3

Lines

15

OddE

4

lh3 rb3 d2 c2 q2 ds2

HighL

6

rb3 d2 c3 q2 ds2

RedB

7

d3 c3 q2 ds2

Doz

9

c3 q3 ds3

Col

10

q3 ds3

Quads Lines

11

OddE

5

lh3 rb3 d3 c3 q2 ds2

HighL RedB

6

d3 c3 q3 ds2

Doz

7

c3 q3 ds2

Col

8

q3 ds3

Quads

9

ds3

Lines

16

[ego]

Here we go F ...
If you read the first document you will see that he belive he fully understand Eriscott method - but hes assumptions is wrong as i solve the puzzel and can cover all possiblitys with wagering options from beginning to end using Eriscott method with 99% probability.

After you read this two document i can show you the solution if you want me to do so.

Cheers

[falkor2k15]

Thanks for sharing these docs ego!

I can see that those PPB examples would resemble EC Triplets in Roulette reminiscent of Priyanka's Dozen Triplets, by betting only on the last element, law of the third style. Is EIRESCOTT really using the Birthday Paradox or just trying to bet PHP? What's interesting is that he only tries - based on the last element - to match a previous triplet providing there's only one possible triplet that can repeat. If there's a clash then he doesn't bet. Sounds like what we were doing with VdW that time. Also, like VdW, he looks at the LLW or LLLLW combinations - i.e. apples and pears post-processing. He seems to think that LLW is more common than LLL? Apart from that I see he uses a basic progression. Is there anything else of significance that I missed? Which part of his strategy uses the Birthday Paradox? Is it that more birthday matches is bad for us in roulette or good for us? We trying to get more bday matches or avoid them?

[falkor2k15]

My understanding of the birthday paradox is that we are trying to get 2 pigeons in one hole using PHP, so the pigeonhole represents the birthday and then we have lot's of people trying to match up to specific pigeonholes.

PPB > PP... here we bet B because PHP says there's more chance for a repeat - but there's only 1 person trying to complete the match. To get more than 1 person affecting the same repeat I think we need parallel games? For example:
H...
Dozen 3...

We should bet the common numbers between High and Dozen 3 as there are 2 people attempting the same repeat within that common area.

Edit: not a good example. I think we need parallel games of 2+ unrelated events that are affecting the same area of the board.

[maestro]

can read here a bit more if want to...

link:s://betterexplained.com/articles/understanding-the-birthday-paradox/#Ok_fine_humans_are_awful_Show_me_the_math

[falkor2k15]

can read here a bit more if want to...

link:s://betterexplained.com/articles/understanding-the-birthday-paradox/#Ok_fine_humans_are_awful_Show_me_the_math

Still doesn't help us translate to roulette terms. What represents the birthday and what represents the people?

Scott
Birthday = repeat
People = number of pigeonholes with 1 appearance?

My Understanding
Birthday = repeat
People = number of parallel uniques affecting same area of board that has yet to repeat.

It's quite hard to explain what represents the people... I can't seem to express it properly.

[falkor2k15]

Back to repeaters system... starting conditions are same as with sleepers: mostly single, double or triple EC to repeat first (or give up it's sleepers first):

OddE	16650	19%
RedB	16198	19%
HighL	12241	14%
OddE RedB	5692	7%
HighL OddE	4416	5%
HighL RedB	4390	5%
Col	4083	5%
HighL OddE RedB	2803	3%
HighL Doz	2387	3%
RedB Col	1681	2%
Doz	1413	2%
OddE Col	1364	2%
HighL Doz Quads	1037	1%
HighL Col	969	1%
HighL Quads	918	1%
OddE RedB Col	892	1%
HighL OddE Doz	886	1%
HighL RedB Doz	800	1%
HighL OddE RedB Doz	794	1%
HighL OddE RedB Col	706	1%
HighL RedB Col	648	1%
HighL OddE Col	558	1%
HighL Doz Quads Lines	533	1%
RedB Doz	514	1%
OddE Doz	465	1%
HighL OddE RedB Doz Quads	368	0%
HighL OddE RedB Quads	272	0%
HighL Doz Col	234	0%
HighL OddE Doz Quads	232	0%
HighL RedB Doz Quads	232	0%
HighL OddE RedB Doz Col	212	0%
HighL Doz Lines	199	0%
HighL OddE RedB Doz Quads Lines	195	0%
HighL OddE Quads	156	0%
OddE RedB Doz	152	0%
HighL RedB Doz Col	150	0%
HighL RedB Quads	149	0%
Doz Col	107	0%
HighL OddE Doz Col	106	0%
HighL Doz Col Quads	96	0%
HighL OddE RedB Doz Col Quads	83	0%
HighL Col Quads	82	0%
HighL OddE Doz Lines	78	0%
HighL RedB Doz Quads Lines	67	0%
HighL OddE Doz Quads Lines	67	0%
HighL RedB Doz Lines	66	0%
RedB Doz Col	66	0%
OddE Doz Col	64	0%
HighL OddE RedB Col Quads	56	0%
HighL Doz Col Quads Lines	42	0%
HighL OddE RedB Doz Col Quads Lines	41	0%
HighL OddE RedB Doz Lines	40	0%
HighL RedB Doz Col Quads	39	0%
HighL OddE Doz Col Quads	38	0%
HighL RedB Doz Col Lines	19	0%
HighL RedB Doz Col Quads Lines	17	0%
HighL RedB Col Quads	16	0%
OddE RedB Doz Col	14	0%
HighL OddE RedB Doz Col Lines	13	0%
HighL OddE Col Quads	12	0%
HighL OddE Doz Col Quads Lines	11	0%
HighL Doz Col Lines	7	0%
HighL OddE Doz Col Lines	5	0%
	86841

The above was the first to get to 3 repeats (4 appearances), including simultaneous sections to get there at the same time.

[falkor2k15]

Interesting stats here... these first events all took the longest to get to their second event:

Even 1	Spin	Apperances	Event 2	Spin
HighL OddE RedB Doz Col Quads	6	ds3	Lines	13
HighL OddE RedB Doz Col Quads	6	ds3	Lines	13
HighL OddE RedB Doz Col Quads	9	ds2	Lines	15
HighL OddE RedB Doz Col Quads	7	ds2	Lines	13
HighL OddE RedB Doz	11	c3 q3 ds3	Col	14
HighL OddE RedB Doz Col Quads	8	ds3	Lines	15
HighL OddE RedB Doz Col	7	q2 ds2	Quads Lines	13
HighL OddE RedB Col	9	d3 q3 ds2	Doz	13
HighL OddE RedB Doz Col Quads	6	ds3	Lines	16
HighL OddE RedB Doz Col	5	q2 ds2	Quads	13
HighL OddE RedB Doz Col	7	q2 ds2	Quads	13
HighL OddE RedB Doz Col Quads	7	ds2	Lines	15
HighL OddE RedB Doz Col	8	q2 ds2	Quads Lines	13
HighL OddE RedB Doz Col Quads	7	ds2	Lines	15
HighL OddE RedB Doz Col Quads	7	ds2	Lines	14
HighL OddE RedB Doz Col Quads	7	ds2	Lines	14
HighL OddE RedB Doz Col Quads	8	ds2	Lines	13
HighL OddE RedB Doz Col Quads	6	ds2	Lines	13
HighL OddE RedB Doz Col Quads	6	ds3	Lines	15
HighL OddE RedB Doz Col Quads	7	ds3	Lines	13
HighL OddE RedB Doz Col Quads	7	ds2	Lines	13
HighL OddE RedB Doz Col Quads	7	ds2	Lines	13
HighL OddE RedB Doz Col Quads	7	ds3	Lines	13
HighL OddE RedB Doz Col Quads	7	ds2	Lines	17
HighL OddE RedB Doz Col	6	q3 ds2	Quads	13
HighL OddE RedB Doz Col	6	q2 ds2	Quads	13
HighL OddE RedB Doz Col Quads	6	ds3	Lines	14
HighL OddE RedB Doz Col	8	q3 ds2	Lines	13
HighL OddE RedB Doz Col	5	q3 ds3	Quads	13
HighL OddE RedB Doz Col Quads	7	ds2	Lines	15
HighL OddE RedB Doz Col	7	q3 ds3	Quads	13
HighL OddE RedB Doz Col	8	q3 ds3	Quads	13
HighL OddE RedB Doz Col Quads	7	ds2	Lines	16
HighL OddE RedB Doz Col Quads	5	ds3	Lines	14
HighL OddE RedB Doz Col Quads	7	ds3	Lines	13
HighL OddE RedB Doz Col Quads	5	ds3	Lines	15

So the less simultaneous repeats in the first event means that the next event will come quicker.

[falkor2k15]

How do I rate my own post above? 

[falkor2k15]

Left = events that took the longest; Right = a small sample of the quickest events.

Event A	Spin	Appearances	Event B	Spin	Distance		Event A	Spin	Appearances	Event B	Spin	Distance
HighL OddE Doz Col Quads	6	ds3	Lines	21	15		HighL	4	rb3 oe3 d2 c2 q2 ds2	OddE RedB	5	1
HighL OddE RedB Doz Quads	5	ds3	Lines	18	13		RedB	5	lh3 oe3 d2 c2 q2 ds2	OddE	6	1
RedB Quads	7	ds3	Lines	20	13		OddE	5	lh3 rb3 d2 c3 q2 ds2	RedB	6	1
OddE RedB Col	8	ds3	Lines	20	12		OddE	4	lh3 rb2 d3 c2 q2 ds2	HighL Doz	5	1
OddE RedB Col	7	ds3	Lines	19	12		OddE	5	lh3 rb3 d2 c3 q2 ds2	HighL	6	1
HighL RedB Doz Quads	6	ds3	Lines	18	12		OddE	5	lh3 rb2 d2 c3 q2 ds1	HighL	6	1
HighL OddE RedB Doz Quads	6	ds3	Lines	18	12		OddE	5	lh3 rb3 d2 c2 q3 ds2	HighL RedB	6	1
Doz Quads	7	ds3	Lines	19	12		OddE	4	lh2 rb3 d2 c3 q1 ds1	RedB	5	1
OddE RedB Col Quads	7	ds3	Lines	19	12		RedB	4	lh3 oe2 d2 c2 q2 ds1	HighL	5	1
OddE RedB Col	5	ds3	Lines	17	12		HighL OddE RedB	5	d2 c3 q2 ds2	Col	6	1
Col	8	ds3	Lines	20	12		HighL RedB Doz	5	oe3 c3 q2 ds3	OddE Col	6	1
OddE Doz Col Quads	6	ds3	Lines	18	12		Doz	4	lh3 rb2 oe3 c3 q3 ds3	HighL OddE Col	5	1
Quads	7	ds3	Lines	19	12		OddE RedB	5	lh3 d3 c3 q2 ds2	HighL Doz	6	1
OddE RedB Doz Quads	7	ds3	Lines	19	12		HighL OddE	4	rb3 d3 c2 q3 ds2	RedB	5	1
OddE	10	ds3	Lines	22	12		OddE	5	lh3 rb3 d3 c2 q2 ds3	RedB	6	1
HighL OddE Doz Quads	7	ds3	Lines	19	12		OddE	5	lh3 rb3 d3 c3 q2 ds2	RedB Col	6	1
Col	8	ds3	Lines	20	12		Col	4	lh3 rb2 oe2 d3 q3 ds3	HighL Quads	5	1
Doz Col Quads	7	ds3	Lines	19	12		HighL	5	rb3 oe3 d3 c3 q3 ds2	RedB	6	1
Doz Col Quads	7	ds3	Lines	19	12		HighL RedB	5	oe3 d3 c3 q3 ds3	Doz Quads Lines	6	1
RedB Doz Col Quads	7	ds3	Lines	19	12		RedB Col	4	lh3 oe3 d2 q2 ds1	HighL OddE	5	1
Quads	7	ds3	Lines	19	12		HighL RedB	4	oe2 d3 c2 q2 ds2	Doz	5	1
OddE Quads	7	ds3	Lines	19	12		RedB Col	7	lh3 oe3 d3 q2 ds3	HighL OddE Doz	8	1
OddE RedB Doz Quads	7	ds3	Lines	19	12		RedB	4	lh2 oe3 d2 c2 q2 ds1	OddE	5	1
Quads	7	ds3	Lines	19	12		OddE RedB	6	lh3 d3 c3 q2 ds2	Col	7	1
Doz Quads	8	ds3	Lines	20	12		RedB	4	lh2 oe3 d2 c2 q2 ds1	OddE	5	1
Col	10	ds3	Lines	22	12		OddE	5	lh3 rb3 d3 c3 q2 ds2	HighL RedB	6	1
Col	9	ds3	Lines	21	12		HighL OddE	5	rb3 d2 c2 q3 ds2	Quads	6	1
OddE Doz Col Quads	9	ds3	Lines	20	11		HighL	5	rb3 oe3 d2 c3 q3 ds2	OddE RedB	6	1
OddE RedB Quads	6	ds3	Lines	17	11		HighL OddE RedB	5	d3 c3 q3 ds2	Doz	6	1
HighL Doz Col Quads	7	ds3	Lines	18	11		RedB	6	lh3 oe3 d3 c3 q3 ds3	HighL OddE	7	1
HighL Doz Col Quads	7	ds3	Lines	18	11		HighL OddE RedB Quads	5	d3 c2 ds3	Doz	6	1
HighL Doz Col Quads	6	ds3	Lines	17	11		OddE	6	lh3 rb3 d3 c2 q3 ds2	HighL RedB Doz	7	1

[praline]

After you read this two document i can show you the solution if you want me to do so.

I want you to do so!

[goldrosen]

I want you to do so!

　
Might need our clever master ego to explain on this more! Thanks in advance Guru!
　

I get so good results with this method, so i been thinking to play with real money.

How to cover 24 unique outcomes with only 15 placed bets.

Lets take clustering patterns into lines of three.
Principal of 1/3.

This is 8 unique combinations/patterns.
I can cover all possibilities for each patter will not have a show once.

1. BBB
2. BPB
3. BPP
4. BBP
5. PPP
6. PBP
7. PBB
8. PPB

To be continued - i have to think how to explain this extreme method.
There is also version where you can reduce the bets even more.

- - -

Ok let me start with how i come up with the idea.
I just wanted to reduce bets.

Lets say you have four formations.

XXX
XOX
XXO
OXX

Then if i get

XXX

Then i do nothing and just wait for the next outcome

XXX
O

Now if the formation will repeat, then i will get following formation OO if not then i get a new formation

XXX
OXO

Then i have placed one bet only and wait for next outcome

XXX
OXO
X

Well now i have to wait again for one more outcome because the formation can be any of the previous two, they can start with XX or OX¨

XXX
OXO
XO

Now i will bet for a repeat of the previos formation as we have a match, that is XOX and only one bet

XXX
OXO
XOO

I miss again and have 3 uique formation with 9 trails and i have only placed two bets
Now i wait for one new outcome before next decision

XXX
OXO
XOO
X

Now i have to play XO as i have two shows of it

XXX
OXO
XOO
XX

I miss and that was the third bet, now if next bet dont win with XXX formation, then i will have 4 unique formation with 12 trails and i make a total of 4 bets

XXX
OXO
XOO
XXO

This is how i started the experiment.
Place 4 bets and cover 12 unique trails or4 unique patterns.

To be continued ...

- - -


This is about that a dice with 8 sides will repeat at least once and not show each side once with no repeat.
A dice with 6 sides has 98.5% to show each side with no repeat and is more rare with 8 sides.
And it also capture zig zag ...

Now on topic.
You could see how you could betting against 4 formation to show once each with 4 bets, as i describe above.

Now if you would do the same thing with banker and player then you have add one more bet for each sequence.
Lets say you have BBB then you would start each bet with P as you would avoid to get 4 unique patterns that begin with banker.

BBB
BPB LL
BBP LL
BPP LLL

That is a total of seven bets.
Now you dont want 4 unique patterns that begin with player, so next bet you only have to bet once to avoid that.
Then you repeat the formula all over again.

BBB
BPB LL
BBP LL
BPP LLL
PPP L
PBP LL
PPB LL
PBB LLL

15 bets cover 24 unique trails to show or prevent 8 sides to show once each, alternate.

- - -

No matter what any one say so do i get very good results.
This is from todays random org file.

6 loses once during 300 trails or 3,5 shoe ...

2 1 2
1 1 2 W
1 1 2 LW
2 1 1 W
2 2 1 LL
1 1 1 W
1 2 2 LL
2 2 2 W
1 2 1 W
1 2 2 LW
2 2 2 W
1 2 1 W
2 1 1 W
2 1 1 LW
1 1 2 W
1 1 1 LW
1 2 2 LL
1 1 1 LW
1 2 2 LL
1 1 2 LL
2 1 1 W
1 2 1 W
2 2 2 W
1 1 2 W
2 2 2 W
1 1 2 W
2 2 1 W
1 2 2 W
1 1 1 LL
2 2 2 W
2 2 1 LW
1 2 2 W
2 2 1 W
1 1 2 W
1 1 2 LW
2 2 2 W
1 2 2 W
2 2 2 W
1 2 2 W
1 2 1 LW
2 2 2 W
1 1 2 W
2 1 2 W
1 2 1 W
1 2 2 LW
2 2 2 W
2 2 2 LW
1 1 2 W
1 2 1 LL
2 2 2 W
1 1 2 W
1 2 2 LL
2 2 1 W
2 2 1 LW
2 2 2 LW
2 1 1 LL
2 1 2 LW
2 1 2 LW
2 1 1 LW
1 2 1 W
2 1 2 W
1 1 1 W
1 2 2 LL
1 2 2 LW
1 2 1 LW
2 1 2 W
1 2 1 W
2 1 1 W
1 2 2 W
1 2 2 LW
1 1 2 LL
2 2 1 W
1 1 2 W
2 2 2 W
1 1 1 W
1 1 2 LW
2 1 1 W
2 2 2 LL
2 2 1 LL
2 1 1 LLW
2 2 2 LL
2 2 1 LL
1 1 1 W
1 1 1 LW
1 1 2 LW
1 2 2 LL
2 1 1 W
2 2 2 LL
2 2 1 LL
1 2 1 W
2 1 2 W
2 1 2 LW
2 2 2 LL
1 2 2 W
2 2 2 W
1 2 1 W
2 2 2 W
2 1 2 LL
1 1 1 W
1 1 1 LW
-----------------
　
Advance and deeper into equilibrium

As you can see we play against 4 banker patterns or 4 player patterns depending on what the first pattern is.
We bet against that all 8 will have a show each and its around 1% chance that will happen or 99% that we will catch at least one repeat.

But this method also use the law of series with a underlying march.
When we play for opposite to prevent all 4 to show with banker or player patterns.

PPP
PBP
PBB
PPB

And

BBB
BPB
BPP
BBP

Does two is also a 50/50 distribution.
And we have for example 1000 singles and 500 series of two and 250 series of three and 125 series of four.

So both repeats and the law of series contribute to the high strike ratio.

Follow the betting flow

2 1 2
1 1 1 W... i see banker pattern and play it will be player pattern and i won
1 1 2 LW... i have player pattern and play it will become banker patterns and lose, then i have 111 and will bet for a repeat 11 and won.
2 1 1 W... i have a player pattern and will play it will become a banker pattern and i win
2 2 2 LL... i have a banker patterns and will play for a player pattern, i lose and will bet for a repeat 21 and lose again.
2 1 2 LL... i have two banker patterns and will bet for a player pattern to show, i lose and play that one of the two previous banker pattern will have a repeat and i lose.
1 1 2 W... i have three banker patterns and will bet for a player pattern and i win.
1 2 1 LL
2 2 2 W
2 2 1 LW
1 2 2 W
1 2 1 LW
---------------
　
Ultimate Explanations
　
Both eriscott and the Author for the Birstday Paradox got it wrong and i have the solution.
You need to read both documents to understand the five bet solution to cover all compinations no matter what 6 uniq combinations you got with the random flow.

Here is one example where the assumption from both is wrong.
For example lets take this string of formations

PPB PPP PBP PBB BPP BBP

Now the assumption is that if you get PP next you can not match with PPB or PPP as both alredy has hit.
But this is wrong.

If you look at the sequense again you also see that all P combinations has hit.
So even if we would get PB we could not match with PBB or PBP as both alredy hit.

Here is the sequense again.

PPB PPP PBP PBB BPP BBP

Now you bet Before you have a result and you bet P once with one single bet and you cover all previos four patterns to have a chance to repeat once, no matter if you get PP or PB.

PPB PPP PBP  PBB BPP BBP P

Easy and it takes a total of five bets to cover all possibilitys from this position.
Assume you got a B result, then you can see above that we have BPP and BBP.
This means that if you get BP next you would bet P and if you got BB you would bet P next.

PPB PPP PBP PBB BPP BBP BP
PPB PPP PBP PBB BPP BBP BB

But lest say you have a new situtaion similiar towards the PPB and PPP example where you can not bet both.
For example BPP and BPB where both begin with BP and you not match your next bet to cover the two possibilitys.

And again the solution is similiar as the first one.
You only have to wait for one B to show and bet P next to cath the begining of the formation BP.
One single bet.

PPB PPP PBP PBB BPP BPB BP
PPB PPP PBP PBB BPP BPB BP

This work as a cancelation march where you then force for a non repating formation to show.
So we cover both situation with one single bet each.

Now to the final stage where you have seven formation and only one missing pattern to complete the hole cycle to alternate with no present repeats.

For example with following sequense:

PPB PPP PBP PBB BPP BBP BBB
PPB PPP PBP PBB BPP BBP BPB

Then you have to bet up to Three times to cover all possibilitys.
Total five bets with the othe two bets.

And again we are using the cancelation term.
As all four formations with P patterns has a show, then the only way to cover all possibilitys to Catch one repat among the them is to bet P once.
If a loss you force the beginning of the last B pattern to show, which is missing or will repeat.

PPB PPP PBP PBB BPP BBP BBB P
PPB PPP PBP PBB BPP BBP BPB B

Now assume we don't get a repeat of the previos P patterns and we get a B result.
Then we again face a situation where we have to patterns that begin with the same formation and end with two differen results, BPP BPB.
So our next bet after B show is for P once to cover the BP formation and cover both patterns BPP BPB to repeat once.

Now to the last final cancelation bet and we have lost four bets with no present repeat.

PPB PPP PBP PBB BPP BBP BBB BB

Here you simply bet for BBB to repat once and if not then you have 8 uniq patterns show with no present repeat.

This might not improve the original or change any thing, but i just want to show have you cover all possibilitys to repeat once with placing a total of five bets.
As the autors of both Writings argue you can not cover a situation where two similiar patterns has a show, which is wrong.

Cheers
Ego

PPB PPP PBP PBB BPP BBP BBB BBB
PPB PPP PBP PBB BPP BBP BBB BBP

Link to post: link:://:.rouletteforum.cc/index.php?topic=13600.0

*Don't bark about your "Troll" here as no one cares anymore anyway.*

[goldrosen]

The message body was left empty.

[falkor2k15]

I think ego might be onto something... this makes more sense reading from here...

PPB PPP PBP PBB BPP BBP

Now you bet Before you have a result and you bet P once with one single bet and you cover all previos four patterns to have a chance to repeat once, no matter if you get PP or PB.

PPB PPP PBP  PBB BPP BBP P

Easy and it takes a total of five bets to cover all possibilitys from this position.

[RouletteGhost]

　
Might need our clever master ego to explain on this more! Thanks in advance Guru!
　
Link to post: link:://:.rouletteforum.cc/index.php?topic=13600.0

*Don't bark about your "Troll" here as no one cares anymore anyway.*

You are top notch member.