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4 Chips, only 3 numbers not covered

Started by Jkirb07, Feb 01, 07:35 PM 2019

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Jkirb07

Hello everyone, I have not been playing roulette very long at all but, I have learned a lot about it. Anyway, I was playing around the other day and placed only 4 chips and was covering all but 3 numbers, which are 0, 14, 23. My problem is I know it needs more chips in certain places so that each spin will either break even or profit. I am so bad with numbers and math which, I know sounds silly since I want to play roulette. I really need someone to do the math on this for me on how many chips should be placed where in order to break even if I don't land in a profit area or to just profit on every spin if it's possible. I really appreciate anyone's input on this. Thank you so much! Also, please just tell me if it's a garbage strategy or if you think a tweak to where the chips are placed should be made. Thanks

buffalowizard

Quote from: Jkirb07 on Feb 01, 07:35 PM 2019
Hello everyone, I have not been playing roulette very long at all but, I have learned a lot about it. Anyway, I was playing around the other day and placed only 4 chips and was covering all but 3 numbers, which are 0, 14, 23. My problem is I know it needs more chips in certain places so that each spin will either break even or profit. I am so bad with numbers and math which, I know sounds silly since I want to play roulette. I really need someone to do the math on this for me on how many chips should be placed where in order to break even if I don't land in a profit area or to just profit on every spin if it's possible. I really appreciate anyone's input on this. Thank you so much! Also, please just tell me if it's a garbage strategy or if you think a tweak to where the chips are placed should be made. Thanks

Hi Jkir, looks like you are covering 30 numbers there. I advise you definitely do not attempt any kind of rapidly rising progressions - keep it simple, set stops that you do not go beyond. Don't be afraid to reset and go again. Test and run trials, learn off members here, read and research and learn what kind of strategy best suits you and your personality. Problem with starting out,e specially with covering a large chunk of the board is, you get lots of wins in a row and think you've cracked it and that you're invincible. Never get that mindset, always be cautious and don't outstay your welcome because the wheel will have your guts for garters if you hang around long enough. Enough of me droning, but best of luck and I actually like the bet you have. Maybe wait for the middle dozen to hit consecutively, and then use your bet to get one hit. Stop, retrack. Etc.

Bigbroben

It's impossible to always be in profit or breakeven on a hit with this setting.

Your chips on dozens must have at least a third of table value each.
The chip on the EC must have half the total value.
The line must have 1/6th of the value at least.

2x 1/3 + 1/2 + 1/6 = 4/3.  Bigger than overunity...

Consider changing the EC for a corner in doz2 and slide the line left or right.  You will then be able to portion the values properly.

Or have a look st the Romanovsky bet.
Life is hard, and then you die.
Mes pensées sont le dernier retranchement de ma liberté.

Ricky

Quote from: Jkirb07 on Feb 01, 07:35 PM 2019
Hello everyone, I have not been playing roulette very long at all but, I have learned a lot about it. Anyway, I was playing around the other day and placed only 4 chips and was covering all but 3 numbers, which are 0, 14, 23. My problem is I know it needs more chips in certain places so that each spin will either break even or profit. I am so bad with numbers and math which, I know sounds silly since I want to play roulette. I really need someone to do the math on this for me on how many chips should be placed where in order to break even if I don't land in a profit area or to just profit on every spin if it's possible. I really appreciate anyone's input on this. Thank you so much! Also, please just tell me if it's a garbage strategy or if you think a tweak to where the chips are placed should be made. Thanks

Hi Jkirb07,
It seems you are on your way to building a 100% WIN at roulette strategy.  :thumbsup:

Now here is the maths
                                 W                                       L
Black                         1                                       1
Dozens                     1                                       2
Line                           5                                       1
8 Combinations
B+D+L                     1+1+5 = 7W                                       
B+D-L                      1+1-1=   1W                       
B-D+L                      1-2+5=   4W                       
B-D-L                       1-1-1 =   1L                                           
-B+D+L                     -1+1+5= 5W
-B+D-L                     -1+1-5  = 5L
-B-D+L                     -1-2+5  = 2W                 
-B-D-L                      -1-2-1 = 4L (Lose all bets)

Now bet these to the correct ratio and sized correctly for each spin of your cycle in addition to another bet that will grant you a profit 100% of the time and you have yourself a HG

good Luck

Ricky

Ricky

Correction
Now here is the maths
                                 W                                       L
Black                         1                                       1
Dozens                     1                                       2
Line                           5                                       1
8 Combinations
B+D+L                     1+1+5 = 7W                                       
B+D-L                      1+1-1=   1W                       
B-D+L                      1-2+5=   4W                       
B-D-L                       1-2-1 =   2L                                           
-B+D+L                     -1+1+5= 5W
-B+D-L                     -1+1-1  = 1L
-B-D+L                     -1-2+5  = 2W                 
-B-D-L                      -1-2-1 = 4L (Lose all bets)

Ricky

Hint, note how many ways you can win and how many you can lose. Very well done  :thumbsup:
And you say you are just starting out at roulette. Well I think you may be going places :-X


Ricky

My Apologies I have not taken my medication today    :'(
Correction
Now here is the maths
                                 W                                       L
Black                         1                                       1
Dozens                     1                                       2
Line                           5                                       1
8 Combinations
B+D+L                     1+1+5 = 7W                                      
B+D-L                      1+1-1=   1W                       
B-D+L                      1-2+5=   4W                       
B-D-L                       1-2-1 =   2L                                           
-B+D+L                     -1+1+5= 5W
-B+D-L                     -1+1-1  = 1L
-B-D+L                     -1-2+5  = 2W                 
-B-D-L                      -1-2-1 = 4L (Lose all bets)

You cannot win the Dozen and Line so these combinations are struck out

Sorry, in my excitement I thought you had something. Unfortunately this combination does not provide you an advantage. But there is one that does so I will allow others to ponder.

Cheers,
Ricky

Ricky


Jkirb07

@Buffalowizard Thank you so much for the input! I am actually covering 34 numbers because of the EC Black

Jkirb07

@Bigbroben Thanks a lot for replying

Jkirb07

Quote from: Ricky on Feb 01, 09:01 PM 2019
My Apologies I have not taken my medication today    :'(
Correction
Now here is the maths
                                 W                                       L
Black                         1                                       1
Dozens                     1                                       2
Line                           5                                       1
8 Combinations
B+D+L                     1+1+5 = 7W                                      
B+D-L                      1+1-1=   1W                       
B-D+L                      1-2+5=   4W                       
B-D-L                       1-2-1 =   2L                                           
-B+D+L                     -1+1+5= 5W
-B+D-L                     -1+1-1  = 1L
-B-D+L                     -1-2+5  = 2W                 
-B-D-L                      -1-2-1 = 4L (Lose all bets)

You cannot win the Dozen and Line so these combinations are struck out

Sorry, in my excitement I thought you had something. Unfortunately this combination does not provide you an advantage. But there is one that does so I will allow others to ponder.

Cheers,
Ricky

Ricky, Thank you so much for all of your replies, I really appreciate it. I finally figured out how to properly respond to people, Lol

Jkirb07

Quote from: Ricky on Feb 01, 09:01 PM 2019
My Apologies I have not taken my medication today    :'(
Correction
Now here is the maths
                                 W                                       L
Black                         1                                       1
Dozens                     1                                       2
Line                           5                                       1
8 Combinations
B+D+L                     1+1+5 = 7W                                      
B+D-L                      1+1-1=   1W                       
B-D+L                      1-2+5=   4W                       
B-D-L                       1-2-1 =   2L                                           
-B+D+L                     -1+1+5= 5W
-B+D-L                     -1+1-1  = 1L
-B-D+L                     -1-2+5  = 2W                 
-B-D-L                      -1-2-1 = 4L (Lose all bets)

You cannot win the Dozen and Line so these combinations are struck out

Sorry, in my excitement I thought you had something. Unfortunately this combination does not provide you an advantage. But there is one that does so I will allow others to ponder.

Cheers,
Ricky

Yea, hopefully someone can figure out a good tweak to this strategy.


Jkirb07

So this is the current amount I am getting back from these bets using only 1 unit on each place for now.. 4 units total

Returns:
7 if hits black inside split street
5 if hits red inside split street
4 if hits black in 2 dozens that are covered
2 if hits red in the 2 dozens that are covered
1 if hits black in the uncovered dozen, outside of split street

Is it possible to tweak this by putting more units in one or more of the bets I placed or more units somewhere else on the board OR switch them around all together so that I can at least breakeven on spins if I dnt hit a profit area? The last 2 I listed are, of course, the bets I am not at least breaking even on. People have already been helping out a lot with input. Just wondering if someone can really figure this out for me or if its just not a good strategy. Thanks so much!



ignatus

Hi JKIRB07 :)

Well, i've coded this bet and tried all kinds of triggers/progression, and then Finally i found the solution to this Riddle with this bet. (ofc, it's a "BAD betselection" but point here now is,(How to make it profitable?) --IF you play this bet, *and imagine only the middle LINE-bet exist,* so then, you play this bet with a ordinary 6 numbers negative progression (or Use the one in the code, AND then, you RESET ONLY the negative progressionline (6 numbers or whatever progression you want to use) WHEN the 6 numbers middle LINE BET Hits.

That's what i figure, anyway,

cheers  O0

TEST 1-2 RNG/LIVE

RX-code

system "4 Chips Bet"
//(copyright) ignatus 2019

method "main"
begin
while starting a new session
begin
          Set List[1,2,3,5,7,9,11,12,14,16,18,20,22,25,28,30,32,35,40,45,50,55,60,70,80,90,100,
                        110,130,150,190,230,275,350]
       to Record "progression" Data
end
put 0 to Record "Highest Bankroll" Data

        Copy List [Black, 1st dozen, 3rd dozen, Line(16-21)] to Record "Bet" Layout



  while on each spin
  begin


  if total bankroll >= 3000 each time
begin
  stop session
end

if total bankroll <= -1000 each time
begin
  stop session
end



{If any inside bet lost each
begin
add 1 on Record "progression" Data Index
end
}


add 1 on Record "progression" Data Index


If Any inside bet won each
begin

if Bankroll > Record "Highest Bankroll" Data
begin
  clear Record "Highest Bankroll" Data
  put 5000% Bankroll to Record "Highest Bankroll" Data
  put 1 on Record "progression" Data Index
end

end




put 100% of Record "progression" Data on Record "Bet" Layout list


If Record "progression" Data Index >
  Record "progression" Data Count
    Begin
     Put 1 on Record "progression" Data Index
     End

  end
END
If you like to donate link::[url="//paypal.me/ignatus1"]//paypal.me/ignatus1[/url]

"Focus on predicting wheel sectors where the ball is expected to land" ~Steve

Bigbroben

What you described is a play on 34nrs.  You'll make 2u on every hit if they all are balanced equally.  With the overlaping color, not all nrs will give equal return.  But all sums will equal zero.

Say you had 12u on doz1, 12u on doz2, 6u on line 13-18, 4u on corner 19-23.  All 34 nrs will be covered equally, with 0,21,24 free.
You could guess and say (gf) :  doz 3 hasnt hit in 3 spins, I'll call it sleepy and will go 11-13 on doz 1-3 or any other ponderation.

You could also say (gf): doz2  hasnt hit in 5 spins, I'll add a unit on line 13-18 and hope for the best.  A hit on line 13-18 will give you 7u profit, a hit elsewhere will give you 1u, a loss will get you to -35.

Up to you, really.

Is there a reason you play color with dozens?
Life is hard, and then you die.
Mes pensées sont le dernier retranchement de ma liberté.

-