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Started by Blueprint, Jun 04, 09:37 AM 2023

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Blueprint

If your goal is to keep gathering unique spins, you can use a modified version of the system we have been discussing. Here are the steps you can follow:

Create a dynamic sequence of spins, just like we have been doing.
Generate a derived set of numbers based on the dynamic sequence, as we have been doing.
Identify the overlaps between the derived set and the dynamic sequence, as we have discussed earlier.
Bet on all the numbers that are not included in the derived set or the overlaps.
If you win, add the winning number to the dynamic sequence and repeat the process.
If you lose, do not add the losing number to the dynamic sequence, but repeat the process.
By betting on all the numbers that are not included in the derived set or the overlaps, you are essentially betting on the unique spins. If you win, you add the winning number to the dynamic sequence, which means you have another unique spin. If you lose, you do not add the losing number to the dynamic sequence, but you still have the spins you have gathered so far.

ᶦ ᵃᵐ|Ä-łëx

Blue are we on the same page as per Dynamic and Derived? rrbb has mentioned about the second stream something different!

Blueprint


Blueprint

By focusing on unique spins and maintaining the order of those unique numbers, we can observe certain patterns or sequences that may have statistical significance. For example, if we track the sequence 1, 3, 2, we can notice that there is no increasing or decreasing order within this sequence, which aligns with the Erdős-Szekeres theorem.

So, while the bets themselves are independent, the pattern or sequence of the unique spins can exhibit statistical relationships or conform to certain mathematical principles.

ᶦ ᵃᵐ|Ä-łëx

Quote from: Blueprint on Jun 15, 05:51 AM 2023if we track the sequence 1, 3, 2, we can notice that there is no increasing or decreasing order within this sequence, which aligns with the Erdős-Szekeres theorem.

1,3 is U
3,2 is D

Blueprint

1,2,3
3,2,1

Increasing and decreasing of length 3.

Yes, if you're looking for 2 then you have U and D of length 2 but 1, 3, 2 is not a strictly increasing sequence.

donik7777

From rrbb...

The erdos Szekeres theorem that states that: If there are m*n+1 unique numbers, than there must be a monotone subsequence of at least m+1 or n+1 (one is increasing, the other decreasing). Google cut the knot erdos Szekeres    for a very clear and concise treatise (select the result with increasing and decreasing sequences). However, a less used alternative is: in any unique number sequence of length N, there  is a increasing sequence of length U and a decreasing sequence of length D so that U*D>=N? Example: 1,2,5,9,3,4,7,8,6. N=9, U=6 (1,2,3,4,7,8), D=3 (9,7,6). There are typically more possibilities to for an increasing or decreasing sub sequence.

kurt123

You guys have a very serious approach to the game. I respect when people do something thinking and calculating.
Don't believe in the me that believe in you, don't believe in the you that believes in me, believe in yourself who believes in you!

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