Unified abstract Number Field theory + Systems

[RBR7]

Unified abstract Number Field theory + Systems

This post is related, to my previous topic ÂÃ,»Roulette theories â€ââ,¬Å" New theory need itÂÃ,«. In this post I will not try to unified numbers field yet, because I would like to give some understanding and reasoning  about numbers, combinations and distances as connecting element.

To get unified abstract number field, we must use this elements to form a different equal number of states, that will be observe in vector space and calculate the most probable future state of the system as a whole. â€ââ,¬Å" But in later posts!!!


Roulette numbers

Roulette is composed from 37 (36+1) numbers, that are randomly placed on the wheel. The probability say, that there is no difference between the wheel or layout order, so we will be focusing only on 36 (leaving zero out for now) numbers,  their values and combination on betting layout . The main focus is on distances, hence the distances are part of the combinations between 2 numbers. Roulette have 666* different combinations (for 37 numbers, without repeat), which is equal to sum of all 36+1 (because zero have 0 value).


Distances (mathematical)

Distances are game product, between exit numbers, that also must behave on law of probability. Entropy is increased by each new number, so we should focus only on numbers that are close to each other on the time line. Distance is effect of two numbers, that can be related in various ways.

1.   Numbers on the same column are related by distances:
+-3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, (36/0 when number repeat)

2.   Numbers in different dozens and same positions in the dozen(also must be in same column):
+-12, 24, 36/0 (36/0 when number repeat)

3.   Numbers of the same figure (same number base value):
9, 18, 27, 36/0 (36/0 when number repeat)

4.   Numbers that have same last digits (same tens):
+- 10, 20, 30

5.   Numbers that are not related with the above distances (they are not in the same columns):
+-1,+-2, combined with other 369 distances (like +-5=+-2+-3 and same for all others).
But is is important to say also that +-5, +-7 combined is related to +-12 in dozens and still connect with other columns. +-5,7 will be discuss in later posts.

All distances are then further divided to produce odd/even, high low, by column, dozen..etc.


Mathematically most probable combinations

Most probable combinations between 2 numbers  are combinations that have fixed sum 37 and by summing several combinations we have 37+37+37=111....6x111=666 overall sum. This might sound a little esoteric, but it is a fact that combinations on these values will be hit the most constantly, but the catch is that we don't know which  numbers will be part of the combinations.

For this problem we can use conditions and play only other parts of the combinations that can be calculated from given conditions. The conditions must provide some equality for complete number field, that must be unified first. Lets look the most probable combinations (sum =37)  between 2 numbers.

1+36=37, 2+35=37, 3+34=37, 4+33=37, 5+32=37, 6+31=37, 7+30=37, 8+29=37, 9+28=37, 10+27=37, 11+26=37, 12+25=37, 13+24=37, 14+23=37, 15+22=37, 16+21=37, 17+20=37, 18+19=37

From this combinations it is obvious that first and third column together and second alone produce most probable combinations of sum 37. This can give as the idea, that we should look for conditions to apply other combinations when 3 different columns hit together in the time line.
When we have a condition of 3 different columns together, we know that next result will produce missing  distances 369 (look distances 1., 2., 3.), other might be produced already from the combination between 3 different column.

Next we need to calculate combinations that will be placed with some equality over betting layout. Since we already have numbers in the 3 different columns, we can calculated result for each column in various ways, but lets see another set of combinations that produce result on higher order.

37+37+37=111 sum of 2x3=6 numbers, have equal combinations on this level with different sums
19+55+37=111 sum of 2x3=6 numbers, with different sets, which allow much more combinatorics

S=19-> 1+18=19, 2+17=19, 3+16=, 4+15=19, 5+14=19, 6+13=19, 7+12=19, 8+11=19, 10+9=19

S=55-> 19+36=55, 20+35=55, 21+34=55, 22+33=55, 23+32=55, 24+31=55, 25+30=55, 26+29=55, 27+28=55

It is obviously that combinations between the columns are the same as for result 37. If we combine this combinations for 3 different columns, we get result (all possible sums) 111=19+55+37  or 74 as overall sum, 3x74=222 which is 1/3 of overall sum.

1+36=37, 1+18=19, 19+36=55 or 18+19=37, 1+18=19, 19+36=55 or full sum 1+18+19+36=74

2+35=37, 2+17=19, 20+35=55 or 17+20=37, 2+17=19, 20+35=55 or full sum 2+17+20+35=74

3+34=37, 3+16=19, 21+34=55 or 16+21=37, 3+16=19, 21+34=55 or full sum 3+16+21+34=74


Systems on distances and combinations

Understanding the combinations related to distances, offer many different systems. Systems that will be described are not using full potential of unified number field dynamics, which will be discuss in later posts.

Systems/bet selections can be classified by the need it information for the condition, that will allow calculations, or in other words, they need different numbers of bits (yes/no questions). Bit is the information that can be only answer in 2 ways, yes/ no and the numbers of question that we use before calculation will tell us how many bits system needs for the condition on which system is made it. Basic setup for condition of 3 different columns on the table, which is 2 bit condition. We ask only 2 questions. First...is the number that hit, part of  different  column as previous number. If the question is yes, we continue and we ask question for the next extraction...is the number that hit in different column then previous 2 numbers. If the answer is yes we do calculation or continue with questions to get more bits of information.

Bets selection classifications:

1.   2 Bit bet selections that only need 2 questions and it is part of basic setup. System based on dozens distances is based on 2 Bits.
2.   3 Bits bet selections that beside basic setup information (3 different columns) , use another conditions which is the question, if the fixed result has show yet or not.
3.   4 Bits bet selections use all the same information then 3 bits, with another bit for certain  distance between numbers sets and it is not yet defined.


Dozen/sestina distance bet selections with basic condition setup

This is very simple bet selection and can be used in many different system setups (system setup will be discussed later). All you need is wait that 3 numbers from different columns hit  (basic condition) and then we can do simple calculation +-6 +-12/24 which will gives us number in 3 columns and in 3 dozens.
Example on real permanences,  with systems setup to play 6 spins with 2 conditions. If we win on first spin we play 2 more, if we win later we play one more...after any win we play another spin with same bet selection. This setup is just to observe performance and it should be modified  for actual play. Calculation + 6 and then apply + -12/24 yield exactly same selection as -6 and then apply + -12/24, by looking numbers in circular way.

Note:
All examples for systems/bet selection will show basic mechanics and ration of W/L is meaningless. I don't want to mislead you by the performance in this short examples and long run will probably fail the same as any other system. Short run system testing is absolutely meaningless and is other part of gamblers illusions, how system will perform in  a long run.

Zero can be played if we have number 26/32 in the condition. It is not the rule, but rather personal choice, because 0 is placed between 26/32 on the wheel.

Examples on real permanences:

Spielbank Wiesbaden Permanenzen

Tisch:     T2
Datum:   2010-12-17

********* Gewinnzahlen ********
N  Z  R

34
15
13
33
9
27 * 27+-6=24+-12/24=33.21.9.
19 * 19+-6=25+-12/24=25.13.1.
32 * 32+-6=26+-12/24=26.14.2.
2W
28L
1W
22L
12
13
1
21
33
8
9
20
27
15
12
36 * 30.18.6.
22 * 28.16.4.
5 * 11.23.35.
6W
34L
2L
14 * 8.20.32.
13 * 7.19.31.
36 * 30.18.6.
8W
35L
25L
23
21
14
14 * 20.32.8.
1  * 7.19.31.
33 * 27.15.3.
31W
27W
32W
10L
19
25
34 * 28.16.4.
15 * 21.33.9.
2 * 8.20.32.
17L
24L
25L
27W
18L


Columns combinations with the fixed value bet selection

This is also very simple bet selection, made on exactly the same conditional setup then previous, with  fixed value (37) result check. Here we also wait that 3 different columns to show together in the time line and the we use the fixed formula 19+37+55=111 to calculate numbers in 3 columns or in other words, we look what numbers are missing from the full combinations of the 4 numbers for each column and we also check if numbers in already  have result 19, 37, 55 between 1st and 3rd column extraction and if they do we find another precious ectraction od 1st or 3rd columns put full combination of 12 numbers in the game.

Examples on real permanences:

Spielbank Wiesbaden Permanenzen

Tisch:     T2
Datum:   2010-12-17

********* Gewinnzahlen ********
N  Z  R

34
15
13
33
9
27 * 27+10=37, 27+28=55, 10+9=19, 9+28=37, missing numbers 9.10.28.
19 * 19+18=37, 19+36=55, 18+1=19, 1+36=37, missing numbers 1.18.36.
32 * 32+5=37, 32+23=55, 5+14=19, 14+23=37, missing numbers 5.14.23.
2L
28W
1W
22L
12
13
1
21
33
8
9
20
27
15
12
36 * 1.18.19.
22 * 15.4.33.
5 * 14.23.32.
6L
34L
2L
14W
13L
36  
8
35
25 * 12.7.30.
23 * 5.14.32.
21 * 16.3.34.
14W
14W
1L
33
31 * 6.13.24.
27 * 10.9.28.
32 * 5.14.23.
10W
19L
25L
34 * 3.16.21.
15 * 4.22.33.
2 * 17.20.35.
17W
24L
25L
27
18
3
22

In this example we have 2x26 and this combination is also valid because we treated repeat as only one number extraction

34 *3.16.21.
26 *11.8.29.
26 repeat
9 *27.28.10.
28W
2L
6L
27
36 * 1.18.19.
13 * 6.23.31.
11 * 8.26.29.
27L
21L
28L
13L
11L *26.8.29. combinations is use right away since we already get new condition to play without hitting
7L * 30.12.25.  first condition
15L * 4.22.33.
5L
30W
3L
24
6
15
2
5*14.23.32.
19*1.18.36.
30*7.12.25.
10L
36W
21L
35*2.17.20.
12*7.30.25.
1*18.19.36.
22L
14L
25W
16L
8*11.26.29.
7*30.12.25.
3*34.16.21.
26W
14L
25W
20L
3
6
1
0
32
4
4
34
0
12
13
31
0
3*16.21.34.
26*29.8.11.
10*27.28.9.
19L
29W

Here is the example when the result of 19,37,55 is already happen 31+6=37 so both numbers 31 and 6 are part of same number combination group, therefore will give us only 8 numbers. To avoid that and still use the combination we must look back on spins** and find 1st or 3rd column number that is not part of 6.13.24.31 combination and caluculate the result and put full combination for all numbers. In this case we have **3.16.21.34., 8.11.26.29., 6.13.24.31.


3L **3.16.21.34. combination that was calculate because 3 numbers already have result 37
29*8.11.26.29.
31*6.13.24.31.
6*
28L
34W
34W
1L


Feedback & opinions

I would like to ask the readers to give some feedback, opinions or questions about this first part of my theory, so that I can re-think and possibly modified the next part of my theory that will use 4 bit (qubit) of information to calculate the numbers and it will try to represent unified number field in abstract vector space and possibly use some quantum mechanics principles (not sure yet), without using complex number. Basicly matrices are use to calculated positions in vector space, which can be simply use for number calculations if we have equal harmonic relations between numbers, with distances.

Please do not post or quote probability theory statements, about how past doesn’t matter, because this is not the intention of this theory. I accept that probbailty theory is the only one correct out there, until proven otherwise and I don’t need to hear it repeatedly.


Regards

[hanshuckebein]

this is a great piece of thought and work you posted here. thank you very much.