10 million: Searching for the perfect progression

[FreeRoulette]

Hey all,

Before I test other progression calculations, I wanted run this by someone.

The chart on the following link shows that picking 2 numbers will hit 50% of the time within 13 spins.
link:://:.loothog.com/Systems/Stats/2.html


Using the progression calculator for 2 numbers. I found the following progression:
link:://:.loothog.com/Systems/prog.html


1) Bet: $ 2 on 2 spots. Profit on a Win: $ 68 Bankroll Needed: $4
2) Bet: $ 2 on 2 spots. Profit on a Win: $ 64 Bankroll Needed: $8
3) Bet: $ 2 on 2 spots. Profit on a Win: $ 60 Bankroll Needed: $12
4) Bet: $ 2 on 2 spots. Profit on a Win: $ 56 Bankroll Needed: $16
5) Bet: $ 2 on 2 spots. Profit on a Win: $ 52 Bankroll Needed: $20
6) Bet: $ 2 on 2 spots. Profit on a Win: $ 48 Bankroll Needed: $24
7) Bet: $ 2 on 2 spots. Profit on a Win: $ 44 Bankroll Needed: $28
8) Bet: $ 2 on 2 spots. Profit on a Win: $ 40 Bankroll Needed: $32
9) Bet: $ 2 on 2 spots. Profit on a Win: $ 36 Bankroll Needed: $36
10) Bet: $ 2 on 2 spots. Profit on a Win: $ 32 Bankroll Needed: $40
11) Bet: $ 2 on 2 spots. Profit on a Win: $ 28 Bankroll Needed: $44
12) Bet: $ 2 on 2 spots. Profit on a Win: $ 24 Bankroll Needed: $48
13) Bet: $ 2 on 2 spots. Profit on a Win: $ 20 Bankroll Needed: $52


So what this means is that 50% of the time I will lose the progression and 50% of the time I will win.

Loss on progression: $52
Minimum win on progression: $20
Maximum win on progression: $68


Playing 100 games should produce the following results:

Loss = $52 * (100 * .50) = $2600
Win Min = $20 * (100 *.50) = $1000
Win Max = $68 * (100 *.50) = $3400

Average (68+64+60+56+52+48+44+40+36+32+28+24+20)/13 = 44

Win Avg = $44 * (100 *.50) = $2200


So from this particular test, I can see that the average doesn't meet or exceed the loss.

I'm not a math wizard so I'm wondering if this approach would be viable if I can find a progression
where the average exceeds the loss.

Thanks for your advice,
FreeRoulette