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@ turbo

Started by Steve, Dec 29, 07:00 AM 2016

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0 Members and 93 Guests are viewing this topic.

falkor2k15

The distance between hits is like the cycle lengths inside the bigger number cycle, so with dozens we predict the repeat on spin 3, and we can stitch it spin-by-spin:
1... bet 2+3 or don't bet at all = expecting a unique
12... bet 1+2 = repeat

So we got our repeat on the 1s on the 3rd spin as predicted and played it spin-by-spin. Of course what we class as repeats depend on what has come before during the cycle. At the end of the day it's all just break even. It would be nice to get deeper into Non-Random, but all I can say for now is that what happens inside a cycle is governed by stats that are accurate and stable compared to playing random games/sessions. So I think the exploit, if it exists, is based around those fixed stats.

Remember, if I was playing "bet dozen 1+3 after X" outside of a non-random framework I could easily curve fit the results to win for a given dataset, but with Non-Random there's no curve fitting possible - or if we do find a way to curve fit then it will curve fit for all datasets.
"Trotity trot, trotity trot, the noughts became overtly hot! Merily, merily, merily, merily, the 2s went gently down the stream..."¸¸.•*¨*•♫♪:

The General

Falkor/Turbo,

In the random game, the number of pockets on the wheel at each spin determines the probability of a number winning, correct?

If so, then how could a number possibly reach forward in time, from the past, and change the number of pockets that remain on the wheel?

Logic, it's always in the way!  ::)

Basic probability and The General are your friend.
(Now hiring minions, apply within.)

Steve

The gap is still based on past spins. I don't know why this part is not understood.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

falkor2k15

Quote from: The General on Jun 26, 03:27 AM 2018
Falkor/Turbo,

In the random game, the number of pockets on the wheel at each spin determines the probability of a number winning, correct?

If so, then how could a number possibly reach forward in time, from the past, and change the number of pockets that remain on the wheel?
See my previous quote - we can designate a dozen to be a repeat or a unique by looking at any past spins:
21 = unique
121 = 1st repeat
12131 = 2nd repeat

So we aren't changing the number of pockets/partitions, but we are just establishing an interval/framework on when we change our bets and to what template. Again, no prediction involved - still break even.

You can increase pockets by betting the next 2 spins, but you will increase the house edge in the process:
--Bet Red, if win then bet number 1.
--We are now betting for 1/72 over the course of 2 spins.

Again, break even and an increase in the house advantage. Also, you cannot cover more than about 36/72 pockets at the same time stitching EC and numbers. Dozens and Streets might work better for achieving 72 number roulette.

Roulette is not about 36 numbers though - it's about how to escape break even (and on top of that the added house edge)
"Trotity trot, trotity trot, the noughts became overtly hot! Merily, merily, merily, merily, the 2s went gently down the stream..."¸¸.•*¨*•♫♪:

Steve

Also i dont know of anything turbo said to indicate he looks at gaps.

I already pretty much know his system from the information he gave. But what's more important is the supposed working principles, which aren't better than random. Its actually easy to prove, but he dodges even basic questions then gets all defensive. Again anyone who thinks they know better should just go win.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

MoneyT101

Quote from: The General on Jun 26, 03:21 AM 2018
Ermm nope. The same number of pockets exist at every spin, so each spin is independent.    ::)

Yes the same number of pockets exist each spin.  That is correct i am glad you noticed and pointed that out.  I would have never thought about that  :yawn:

You still dont pay attention... close minded will get you no where
Simple once you get it!  Chased all the pigeons away and they were already in their hole

The General

Falkor,

What might help us understand what you've written is if you could provide some examples using some of your colorful tables, charts and graphs. 

Please create several large examples.

Maybe...just maybe it will help people like Steve and myself understand what you're saying.

Basic probability and The General are your friend.
(Now hiring minions, apply within.)

MoneyT101

Quote from: Steve on Jun 26, 03:29 AM 2018
The gap is still based on past spins. I don't know why this part is not understood.

If i sit down at the table write down spin 1.... thats my current spin.  once i get to spin 10

spin 1 is still my current spin for me because its in my session of 37 spin.  No past spins!!!

what is so confusing about that..... you keep arguing the same points and you keep getting answers! 

anything before spin 1 is not part of the session because you werent present.  Thats past spins for turbo!
Simple once you get it!  Chased all the pigeons away and they were already in their hole

The General

Quote from: MoneyT101 on Jun 26, 03:38 AM 2018
Yes the same number of pockets exist each spin.  That is correct i am glad you noticed and pointed that out.  I would have never thought about that  :yawn:


If the same number of pockets remain on the wheel at each spin, then why would the odds change?  Afterall, don't the number of pockets determine the odds of a number winning on the next spin, on the next series of spins, and in the long run?

Again, logic is in the way!

Basic probability and The General are your friend.
(Now hiring minions, apply within.)

falkor2k15

Quote from: The General on Jun 26, 03:40 AM 2018
Falkor,

What might help us understand what you've written is if you could provide some examples using some of your colorful tables, charts and graphs. 

Please create several large examples.

Maybe...just maybe it will help people like Steve and myself understand what your saying.
Which part you need more detail/examples about?
"Trotity trot, trotity trot, the noughts became overtly hot! Merily, merily, merily, merily, the 2s went gently down the stream..."¸¸.•*¨*•♫♪:

The General

Never mind Falkor
Basic probability and The General are your friend.
(Now hiring minions, apply within.)

Steve

Quote from: MoneyT101 on Jun 26, 03:41 AM 2018
If i sit down at the table write down spin 1.... thats my current spin.

How do you know the first spin without it being the past?

Or dont you agree that the past is something that already happened?

What's your definition of the past?
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

falkor2k15

Quote from: MoneyT101 on Jun 26, 03:41 AM 2018
If i sit down at the table write down spin 1.... thats my current spin.  once i get to spin 10

spin 1 is still my current spin for me because its in my session of 37 spin.  No past spins!!!

what is so confusing about that..... you keep arguing the same points and you keep getting answers! 

anything before spin 1 is not part of the session because you werent present.  Thats past spins for turbo!
Right, so they are past spins, but within the current session or frame. In other words, those are the numbers you choose to help determine relationships when playing the next bet. Repeats or Uniques is just a label - neither are better than the other hence results in break even, but we use them to keep within the limits of stable stats.
"Trotity trot, trotity trot, the noughts became overtly hot! Merily, merily, merily, merily, the 2s went gently down the stream..."¸¸.•*¨*•♫♪:

falkor2k15

Quote from: The General on Jun 26, 03:42 AM 2018
If the same number of pockets remain on the wheel at each spin, then why would the odds change?  Afterall, don't the number of pockets determine the odds of a number winning on the next spin, on the next series of spins, and in the long run?

Again, logic is in the way!
You can change the odds by stitching 2 spins, but you proportionately change the cost, so is still break even (see previous example about 72 number roulette). So the break even problem is to do with unfair payout odds. I was convinced that we could bet for 2 things to happen in 2 spins and somehow gain edge based on the way we was stitching and expressing our bets, but I don't believe this is possible now as I've never been able to achieve it.
"Trotity trot, trotity trot, the noughts became overtly hot! Merily, merily, merily, merily, the 2s went gently down the stream..."¸¸.•*¨*•♫♪:

MoneyT101

Quote from: The General on Jun 26, 03:42 AM 2018
If the same number of pockets remain on the wheel at each spin, then why would the odds change?  Afterall, don't the number of pockets determine the odds of a number winning on the next spin, on the next series of spins, and in the long run?

No one has mentioned Odds

But if you want to get into that, by the way this is general info with some thinking since you guys cant do it yourselves.

The odds for each spin is 1/37...spin by spin

The odds in 37 spins average are .... 24 numbers(12 repeats) and 13 numbers missing

so talk about those odds.... lets say after 24 spins you have 18 numbers plus 6 repeats.

from spin 25 to 37..... based on the overall avg we need 6 more new numbers and 6 repeats.

13 spins... 6 repeats.... how many do you need to win?

if i can just win on 1 repeat, do i beat the odds? Think before you answer......13 spins to complete my session and about 6 will repeat.

what if those 6 repeats only came out 2 in total.... so the math says some will be 3

so 6 numbers in 13 spins ?  How many I need to win to beat the odds?

If this doesnt shed light to it the idea for you...I cant help you any further on this subject!
Simple once you get it!  Chased all the pigeons away and they were already in their hole

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