Gentlemen,
I believe,
many here,
 has headache,
how,
to minimize,

STAKING,

THUS, I think...

Bet only RED,
or
only BLACK,
of,
only a single dozen...bet.

WHAT YOU THINK??
below,

 an EXAMPLE...

of bet only
DOZEN ONE.

BLACK ONLY.

RED ONLY...

Red  =
(5,  1,  9, 7, 12, 3.)

Black=
(4, 2,  6, 11, 8, 10.)


Black
4=EMPTY
2=X
6=X
11=X
8=X

Red   
5=X
1=X
9=XX
7=EMPTY
12=X
3=EMPTY

Roulette,
Number of
DOZEN ONE,

hit after 37spins

=1,2,5,6,8,9,9,11,12

Refer to kario's image on reply#30

Thanks for confirming Vaddis...appreciate it...

You may bet,

ie.

Only, HALF of the wheel,

Black numbers only,
Etc.

Bet for,

EVENT,
THAT MUST HAPPEN, IN NEXT 36SPINS!

(4,2, 6,11, 8, 10,5, 1,9, 7, 12, 3)

Arrange above numbers to bet as a group in dz one, see how they, linear wise, single or double, triple...in 36spins.

They represent the dz1 numbers on the wheel, as clockwise, so if the wheel bias, then half of the numbers will hit more than the other half.

It is not true, I gave him only a false hope, lol he was so happy and think he finally have something.

long time vaddis just tried to pm you it won,t let me...wanted to ask you a simple question...might as well ask here...is it true you gave roulettepassion ..aka sergio..your bet..

this is simply curiosity as he did go on a bit about it that you did...

I THINK,
To avoid huge staking,
which may cause
losses, even we win a few hit,

we bet only, a third of the numbers.

In OVERSIMPLIFIED EXAMPLE.

We bet just dozen-one
"123456789,10,11,12".

Since, the averages, of 36spins=24,

then, divided by three=8...
Then ,
after 36spins,
a dozen ,
averages hit=8numbers.
12-8=4 empty BLOCK space.

Thus, if after, say, 18spins, only 4 numbers hit, in dz1, then there's, eight numbers BLOCKS left,
unhit,
with averages,
of four numbers,
MAY hit, in next 18spins.


There's never, a single dz sleep for, 36spins, thou theoritically,
12 numbers possibly sleep after 37spins.

Thus, if you bet just dz1, and lose,

then dz2 and dz3,
had hit, with more than eight numbers each...


Thus, every, session, we have, averages...
1/3, to lose,
and 2/3 to win.

This is just too hard, you are on the wrong path, it can't lead you to holly grail.

this AI no really reliable, but four groups not missing, is something to look into, maybe someone could help with their millions data? thanks

dozen one.
A=  05 ,07.
B = 11
C= 9, 12
D= 4, 6 ,8,
E= 1 ,3
F= 2 ,10


what the combination of missing groups? in ...

AI.Gimini reply.
Yes, the data processing is finally complete! Thank you for your patience. Here are the results from the analysis of your European Roulette data:
Frequency of Numbers 1-12 in Overlapping 36-Spin Sequences
Across all the overlapping 36-spin sequences in your data, here's how many times each number from 1 to 12 appeared with different frequencies within those sequences:


| Number | Appeared Once | Appeared Twice | Appeared Thrice | Appeared 4+ Times |
|---|---|---|---|---|
| 1 | 15 | 12 | 5 | 2 |
| 2 | 18 | 10 | 3 | 1 |
| 3 | 16 | 11 | 4 | 1 |
| 4 | 17 | 9 | 5 | 1 |
| 5 | 14 | 13 | 4 | 1 |
| 6 | 19 | 8 | 4 | 1 |
| 7 | 15 | 12 | 6 | 1 |
| 8 | 16 | 10 | 5 | 1 |
| 9 | 17 | 11 | 3 | 1 |
| 10 | 18 | 9 | 4 | 1 |
| 11 | 14 | 14 | 3 | 1 |
| 12 | 16 | 10 | 5 | 1 |
Note: The total number of overlapping 36-spin sequences analyzed depends on the total number of spins in your provided data.
Missing Groups of Numbers (A-F) in Overlapping 36-Spin Sequences
Here's a summary of how many times each individual group and their combinations were completely absent in the overlapping 36-spin sequences:
| Missing Group(s) | Number of Occurrences |
|---|---|
| A | 45 |
| B | 62 |
| C | 58 |
| D | 38 |
| E | 51 |
| F | 49 |
| AB | 12 |
| AC | 15 |
| AD | 9 |
| AE | 11 |
| AF | 13 |
| BC | 18 |
| BD | 10 |
| BE | 14 |
| BF | 16 |
| CD | 8 |
| CE | 12 |
| CF | 14 |
| DE | 7 |
| DF | 9 |
| EF | 10 |
| ABC | 3 |
| ABD | 2 |
| ABE | 3 |
| ABF | 4 |
| ACD | 1 |
| ACE | 2 |
| ACF | 3 |
| ADE | 1 |
| ADF | 2 |
| AEF | 2 |
| BCD | 2 |
| BCE | 3 |
| BCF | 4 |
| BDE | 1 |
| BDF | 2 |
| BEF | 3 |
| CDE | 1 |
| CDF | 2 |
| CEF | 3 |
| DEF | 1 |
| ABCD | 0 |
| ABCE | 0 |
| ABCF | 0 |
| ABDE | 0 |
| ABDF | 0 |
| ABEF | 0 |
| ACDE | 0 |
| ACDF | 0 |
| ACEF | 0 |
| ADEF | 0 |
| BCDE | 0 |
| BCDF | 0 |
| BCEF | 0 |
| BDEF | 0 |
| CDEF | 0 |
| ABCDE | 0 |
| ABCDF | 0 |
| ABCEF | 0 |
| ABDEF | 0 |
| ACDEF | 0 |
| BCDEF | 0 |
| ABCDEF | 0 |
It appears that in the analyzed data, there were no instances where four or more of the defined number groups were simultaneously missing in any of the overlapping 36-spin sequences.
I hope this detailed breakdown is what you were looking for. Let me know if you have any further questions or if there's anything else I can assist you with!