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Completely Perplexed...HELP!

Started by ScoobyDoo, Feb 16, 04:37 PM 2011

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ScoobyDoo

Hi Guys,

Ok, let me get right to the point.

In a Matrix that is Seven-Spaces wide we are writing the dozens in the squares from left to right and the dropping to the next row below and continuing.

We are lookingt for 4-vertical dozens that are the same. Now here is the question:

Once you have one vertical group of four of the same dozen, what is the percentage chance that you could have four more groups of four vertical dozens before you have one group of three vertical dozens with a different dozen making up the forth dozen in the vertical colume?

I hope I have explained it correctly. If you don't understand it, please feel free to contact me. any help will be GREATLY appreciated.

Scooby Doo

marivo

Quote from: ScoobyDoo on Feb 16, 04:37 PM 2011
Hi Guys,

Ok, let me get right to the point.

In a Matrix that is Seven-Spaces wide we are writing the dozens in the squares from left to right and the dropping to the next row below and continuing.

We are lookingt for 4-vertical dozens that are the same. Now here is the question:

Once you have one vertical group of four of the same dozen, what is the percentage chance that you could have four more groups of four vertical dozens before you have one group of three vertical dozens with a different dozen making up the forth dozen in the vertical colume?

I hope I have explained it correctly. If you don't understand it, please feel free to contact me. any help will be GREATLY appreciated.

Scooby Doo

Don't understand this, can you wright an example?

ScoobyDoo

Hi Marivo,

Here is an example:

231
213
233
212<-- here in the first vertical colume you will see 4 vertical dozens of the same (Doz 2)

Continuing on in this colume of three dozens, writing new dozens across underneath, I want to know the percentage chance that there will be one more occasion, two more occasions, three more occasions or four more occasions of four vertical dozens happening without any vertical dozenswith just three dozens and then a different dozen.

2    1
2    1
2    1
1    3<--Like these two examples

Any help you can give me will really be appreciated

Scooby Doo

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