Question about a 2 number system

[soggett]

Hi all

I was wondering, if we play a 2 number system for 37 spins, what are the odds we will win/lose?
I calculated but i'm not sure if I got it right, I got 12,8% a chance of loss, is that right?

Also do you know of any good 2 number system?
I was thinking of running 37 spins then chooseing the newest two numbers that appeared twice and betting on them for the next 37 numbers till a hit. I figured that way we dont bet cold or hot numbers cause cold numbers can stay cold and hot numbers can go cold, we bet on the "warm" middle
Works fine for now, no losses yet, sometimes even 2 or 3 hits come early, what do you think?
And is betting just 2 numbers a good idea?

[nitrix]

If you can get an answer from Mr.J that would be perfect. I remember him saying we're all fools playing more than 2 numbers so you guys would get along

[soggett]

Yes, his thoughts would be highly appreciated because I know he plays only up to 4 numbers and I'm thinking going the same way 

[MrJ]

If you can get an answer from Mr.J that would be perfect. I remember him saying we're all fools playing more than 2 numbers so you guys would get along

Come on, I never said 'fools'.

Ken

[soggett]

Hello MrJ
I would love to hear your thoughts about the above system or if you have any system you would like to recommend... I'm all ears 

[soggett]

Anyone?
Is it really 12,8%?
Have I calculated right?

[Proofreaders2000]

2/37=0.054 chance of a hit for betting on two numbers for one spin.  x37(spins) roughly 2% chance of getting a hit.

A popular tactic is playing the most repeated numbers over a number of spins (which may or may not win).

Here's my favorite two number system.  Victor One link:://rouletteforum.cc/index.php?topic=1759.0

[soggett]

Thank you very much Proofreaders2000
I'll have a look at the system, thanks