Smart Progression

[Kali49]

hey guys if you pay attention to the example I started with, 6 spins * 3 lines = 18 spins total, in which 9 spins should be Red, Smart Progression uses only 6 red spins to complete the session.

So even if black was the dominant color, we only need 6 out of the theoretical 9 Reds to finish the session. And that is lovely.

[Person S]

It seems I'm starting to understand.
We have 1 line, and we need to bet until it plays (it depends on the length that we choose).
Then we play game 2 and place bets on line 2 at the points where the loss occurred. It looks like a virtual game ...
I think the problem is that we do not know at what points 6 red will appear.
Are rates on line 2-3 also flat or do they need to be increased by 1 unit?

[Person S]

I wanted to make sure that I understood correctly. I will play for R / B.
1.RRRRRR
   + - + - + -
2.RBBRRB
   0 - 0 - 0 -
3.RRRRBB
   0 - 0 +0+
Everything is flat bet.

[Kali49]

I wanted to make sure that I understood correctly. I will play for R / B.
1.RRRRRR
   + - + - + -
2.RBBRRB
   0 - 0 - 0 -
3.RRRRBB
   0 - 0 +0+
Everything is flat bet.

We are going to mix flat betting with a progression.

You only play red or you only play black.

Let's play red with your example:

1- RRRRRR (+1+1+1+1+1+1) +6
Session completed in 1 line.

Let's play black with your example:

1- RRRRRR (-1 -1 -1 -1 -1 -1)
When this happens don't  move to the next line yet extend Line 1 to 12 spins or more flat 1  unit, till you almost breakeven. Then move to Line 2.

1- RRRRRR         RBBRRB
    (-1-1-1-1-1-1  -1 +1 +1 -1 -1 +1 )

[quos]

Hi Kali, thanks for your explanation. It is very interesting.
In this example:

1- RRRRRR RBBRRB
    (-1-1-1-1-1-1 -1 +1 +1 -1 -1 +1)

Result is -6, Still not close to balance, would we play another 6 more spins in the 1 line?

What would be the balance to be achieved before moving to line 2?

Thanks!!!

[Person S]

If you play for black it will kill.
1 line - 9
2 line (bet 2 units on L) - 13
total minus 21 units.
There is a 3 line, but it does not change anything.
As someone wrote R / B alternation, it is better than betting on 1 color.

[Kali49]

If you play for black it will kill.
1 line - 9
2 line (bet 2 units on L) - 13
total minus 21 units.
There is a 3 line, but it does not change anything.
As someone wrote R / B alternation, it is better than betting on 1 color.

That is why I recommend larger sessions to avoid the fluctuations that exists in short term permutations.

It is preferable to play same as last color or different than last color.

I said just red or just black and I used 6  spin sessions to ease explanation.

[Kali49]

Hi Kali, thanks for your explanation. It is very interesting.
In this example:

1- RRRRRR RBBRRB
    (-1-1-1-1-1-1 -1 +1 +1 -1 -1 +1)

Result is -6, Still not close to balance, would we play another 6 more spins in the 1 line?

What would be the balance to be achieved before moving to line 2?

Thanks!!!

If you look a little deeper you will start to see probability distribution taking place equally within your session, take notes and bet accordingly.

Say for 20 spins in Line 1 you get around 40 % Red 60 % black then move to Line 2.

Smart progression is even better if your Betselection is a smart one as well.

[Kali49]

To understand the concept behind this method think in terms of "utility functions".
If I am expecting 50% probability of delivery say 9 red numbers in 18 spins,
and my method only needs 30% delivery to profit. That is a good use of the utility function concept.

[Kali49]

More on the expected utility function in game theory here :
link:s://youtu.be/qwN55kzmojM

[Kali49]

Demonstration Session:
Playing Six spin Sessions with same as last bet selection:

Numbers were:



Session graph :



+1
-1. +2
+1
+1
+1
-1. +2

+6 units

[quos]

Hey Kali ! I think I am understanding but I have some doubts regarding line 2.

spin    R/B          Result
1          Black                           next spin we bet Black
2          Black      +1                 next spin we bet Black
3          Red         -1                 next spin we bet Red
4          Red         +1                next spin we bet Red
5          Red         +1                next spin we bet Red
6          Red         +1                next spin we bet Red
7          Black       -1                Here we have 4 hits and 2 failures. Your method only needs 30% delivery to profit and in this case
                                                we have 66%. It is right?

Here and at this moment is where I have doubts. At first I thought we would have to play another 6 spins and only bet on spins 2 and 6 of line 2, but from what I see it is not so. you only play 2 more spins (spins 8 and 9). It is right?

for spin 8 (belonging to line 2) do you play the same color as in spin 7? that is, would we bet on black?
for spin 9 (belonging to line 2) do you play the same color as in spin 8? that is, would we bet on black?

Thanks in advance!!!

[Kali49]

Hey Kali ! I think I am understanding but I have some doubts regarding line 2.

spin    R/B          Result
1          Black                           next spin we bet Black
2          Black      +1                 next spin we bet Black
3          Red         -1                 next spin we bet Red
4          Red         +1                next spin we bet Red
5          Red         +1                next spin we bet Red
6          Red         +1                next spin we bet Red
7          Black       -1                Here we have 4 hits and 2 failures. Your method only needs 30% delivery to profit and in this case
                                                we have 66%. It is right?

Here and at this moment is where I have doubts. At first I thought we would have to play another 6 spins and only bet on spins 2 and 6 of line 2, but from what I see it is not so. you only play 2 more spins (spins 8 and 9). It is right?

for spin 8 (belonging to line 2) do you play the same color as in spin 7? that is, would we bet on black?
for spin 9 (belonging to line 2) do you play the same color as in spin 8? that is, would we bet on black?

Thanks in advance!!!

There are three things you can do once you complete Line 1:

1- you can end the session right there in Line 1 and call it a winning session, lock in the profit.

2- you can move to Line 2 and play six more spins and only bet the corresponding two bets that lost in Line 1.

3- just play two more spins that are needed to complete the session without playing 0 bets on bets that won on line 1.

[Person S]

2- you can move to Line 2 and play six more spins and only bet the corresponding two bets that lost in Line 1.

3- just play two more spins that are needed to complete the session without playing 0 bets on bets that won on line 1.

Thanks, I wonder what is the likelihood that method 2 will be better than 3?

[Kali49]

Thanks, I wonder what is the likelihood that method 2 will be better than 3?

That's where game theory comes into play.