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Started by ll l ll l lll ll, Jul 19, 01:43 PM 2011

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ll l ll l lll ll

Quote from: superman on Jul 22, 03:20 PM 2011

I totally agree with that statement.

OK, I have added your progression method to it, please see attached file and check the progression is moving properly up and down, I must say the weak progression is a grind.

Let me know if I am doing it wrong please

If everything you did do was correct, you can see you reached +9 units right from the start.  Then you went down to -22 units BUT you were never betting higher than 2 units (2c) at any time and you recovered.  If you had entered the game here, it recovered all the way up to a +7.  If I was going for a modest +3 session goal or +5, this is very possible to bet HIGH units such as $500 or $1,000 chips.  If I had to bet up to 2c in this example, I would only be risking 2 units per spin.

warrior

barcode my apologies i went back and check my results i found my mistakes .

ll l ll l lll ll

Quote from: warrior on Jul 22, 07:29 PM 2011
barcode my apologies I went back and check my results I found my mistakes .

No problem!

superman

QuoteSomething is not right.  What does "last 4 mean?"

Last4 dc,db,db,da Decision db

Last 4 is the last 4 dozens to show, from left to right in the above dc came out last.

The progression, I hope I was wrong, if it gets to 1b and has a win I go back to the first level of 1a, if a win happens in 2a I go back to the start of 1a so its moving right 1 step after a loss and left 3 or more steps on a win, in your first post you said go back to the previous level, you didn't state what part of the previous level, each level has 3 parts, so which do we go back to, I think this is where I got it wrong, you said

QuoteIf the next 3 spins produces a winner, we move to the left back to 1c

To the start of 1c? that's what I am doing currently

111,111,111,222,... if a win on the bold 2 I am putting progression back to the bold 1

QuoteSuperman.  Why don't you run a double test.  One with barcode's bet selection and the same numbers betting for the last dozen to repeat.  We'll see what we're really dealing with

@ George, need to get his progression right first, if I have it wrong, when he replies I will fix it, test it again and we can take it from there
There's only one way forward, follow random, don't fight with it!

Ignore a thread/topic that mentions 'stop loss', 'virtual loss' and also when a list is provided of a progression, mechanical does NOT work!

ll l ll l lll ll

Quote from: superman on Jul 23, 02:03 AM 2011

Last4 dc,db,db,da Decision db

Last 4 is the last 4 dozens to show, from left to right in the above dc came out last.

The progression, I hope I was wrong, if it gets to 1b and has a win I go back to the first level of 1a, if a win happens in 2a I go back to the start of 1a so its moving right 1 step after a loss and left 3 or more steps on a win, in your first post you said go back to the previous level, you didn't state what part of the previous level, each level has 3 parts, so which do we go back to, I think this is where I got it wrong, you said
 
To the start of 1c? that's what I am doing currently

111,111,111,222,... if a win on the bold 2 I am putting progression back to the bold 1
 
@ George, need to get his progression right first, if I have it wrong, when he replies I will fix it, test it again and we can take it from there

As far as the "last 4" go to make a decision on the "most dominant dozen," it is NOT always determined in the last 4 spins.  Remember I said it can happen in as quickly as 2 spins.  Don't get caught up in how many spins it takes.  It can take 2 spins, 3 spins or 4 spins, it's always changing.  The solid rule is the first dozen to appear twice.

Your progression is wrong.  It's always moving exactly one step to the right on a loss and one step to the left on a win.  I never said it moves "3-steps" to the left on a win, I always said only one step in either direction, very simple. 

Example:  On consecutive losing sets we play: 1a, 1a, 1a, 1b, 1b, 1b, 1c, 1c, 1c, 2a, 2a, 2a, 2b, 2b, 2b, 2c, 2c, 2c, 3a, etc.

On consecutive winning sets we play: 3a, 2c, 2c, 2c, 2b, 2b, 2b, 2a, 2a, 2a, 1c, 1c, 1c, 1b, 1b, 1b, 1a, 1a, 1a

This is YOUR example: "111,111,111,222,... if a win on the bold 2 I am putting progression back to the bold 1."  ....This is wrong.

This is the correct way.  If you have 111, 111, 111, 2,2,2....if win on the middle bold 2, you are still staying in that same 2 unit set but moving backwards to the first 2.  If you get 2 out of 3 winners of that set, then you move back to the third set of 1's.  Like this 111, 111, 111, 222

The goal is always to get back to 1a.  That's why your test was such a slow grind, b/c where you should have been quickly recovering your profits in the 2's, you went too far back to the 1's.  Try replaying your exact numbers on your first test with this correct progression, i'm sure your recovery and profits would be higher.

londonboy85

How do we deal with 0, ex:

6, 26, 0, 5, 20,33
d1,d3,0,d1,d2,d3


Do we ignore 0 so that the dominant dozen is d1, or any number coming before 0 should not be counted towards the dominant dozen.

superman

QuoteIt can take 2 spins, 3 spins or 4 spins, it's always changing.  The solid rule is the first dozen to appear twice

Yeah, if you looked at the decision you would see I am taking UP TO the last 4, if da,da was last it would only check that far, bet selection is ok as far as I am concerned.

QuoteIf you have 111, 111, 111, 2,2,2....if win on the middle bold 2, you are still staying in that same 2 unit

If that is so then why complicate the progression, this is a simple D' Alembert progression, up on loss and down on a win, because this statement goes against what you just posted

QuoteIf the next 3 spins produces a winner, we move to the left back to 1c

As you could be at the 3rd level of 2a and moving back to any part of 1c would mean more than 1 jump backwards. That's how I read it anyway, not picking a fight, just explaining how I got the wrong end of the stick. Will set it up D' Alembert style, much easier all round
There's only one way forward, follow random, don't fight with it!

Ignore a thread/topic that mentions 'stop loss', 'virtual loss' and also when a list is provided of a progression, mechanical does NOT work!

ll l ll l lll ll

Quote from: superman on Jul 23, 01:20 PM 2011

 
If that is so then why complicate the progression, this is a simple D' Alembert progression, up on loss and down on a win, because this statement goes against what you just posted
 

I don't see how it goes against what I posted?  From the begining I've always said we move to the right on a loss and to the left on a win, per SET.

ll l ll l lll ll

Quote from: superman on Jul 23, 01:20 PM 2011

As you could be at the 3rd level of 2a and moving back to any part of 1c would mean more than 1 jump backwards.

This statement is wrong.  Once I've entered a "set," such as 2a, position does not matter.  2a, 2a, 2a: It does not matter which 2a it is.  My goal is to win at LEAST 2 out of 3.  If I accomplish this, I then move back to set 1c.  Now I am in set 1c, 1c, 1c.  Position again does not matter in 1c, my goal is to win at LEAST 2 out of 3 in 1c.  If I win 2 out of 3 in set 1c, I then move back to set 1b, 1b, 1b.  Again, position does NOT matter within the same set, my one and ONLY goal is to win at least 2 out of 3 per SET.  If a set wins I move to the next "set" to the left, if a set loses I move to the next "set" to the right.  I don't know how to explain it any more simple than I already have for you?

ll l ll l lll ll

Quote from: londonboy85 on Jul 23, 12:57 PM 2011
How do we deal with 0, ex:

6, 26, 0, 5, 20,33
d1,d3,0,d1,d2,d3


Do we ignore 0 so that the dominant dozen is d1, or any number coming before 0 should not be counted towards the dominant dozen.

Exactly.  Ignore the zero like it never happend and take the loss.  The dominant dozen is D1.  If you are betting a 3 spin set and a zero comes, that is a loss on that spin.  That means you need to win the next 2 spins to "win" that set.  But if you only win one spin, then you have won 1 out of 3 for that set and you broke even.  You stay right where you are, and play the "new" most dominante dozen at the same unit.

londonboy85

Just tested some live casino result from smart live and result after 176 spins is -3. Started really badly and was up to a low of -37.

If I was actually playing, I would have stop at +1 around 100 spin mark. I used the new progression of glc.

GLC

Quote from: londonboy85 on Jul 23, 04:59 PM 2011
Just tested some live casino result from smart live and result after 176 spins is -3. Started really badly and was up to a low of -37.

If I was actually playing, I would have stop at +1 around 100 spin mark. I used the new progression of glc.


I just want to inform everybody that I realized that barcode isn't betting the way I outlined in my penthouse post.  The penthouse is based on playing continuously whereas barcode's system is based on playing in sets of 3 bets then decide what you should do, drop back, stay put or move on.


I'm not saying the penthouse progression isn't a very good progression and should hold it's own with any single dozen/column bet selection there is.  It just may not perform as well on a system designed for sets of three.


Might be interesting to play those same 185 spins and use barcode's bet method and see how it did next to the penthouse idea.


Sorry if my post caused any confusion.


George
In my case it doesn't matter.  I'm both!

ll l ll l lll ll

Quote from: londonboy85 on Jul 23, 04:59 PM 2011
Just tested some live casino result from smart live and result after 176 spins is -3. Started really badly and was up to a low of -37.

If I was actually playing, I would have stop at +1 around 100 spin mark. I used the new progression of glc.

I just played the first 29 numbers of the numbers you provided with the way I play.  I got off to a slow start and only reached 2c of the progression and then went into profit of +3 at spin #23 which was number 35.  I then contined to play and reached +6 at spin 29 which was #15.  If I was betting $1,000 chips in the casino I just walked out with $6,000 in 29 spins, while never betting more than 2 units ($2k) per spin. 

I said it from the begining, my aim is to win only 3 units.  If I can do that consistently with such a small progression where my betting units are never more than 3 units, I have acheived a method that I like to play in a real casino which is play big for minimal time.  Imagine building up your bankroll and playing with $5,000 chips.  3 units is $15,000. 

ll l ll l lll ll

update:

Very interesting.  I just played 7 separate 100 spin sessions FLAT betting and the results are impressive.

Session 1: +15
Session 2: +12
Session 3: +10
Session 4: +18
Session 5: +15
Session 6: +14
Session 7: +9

These are the high's for each of the 100 spin sessions FLAT BETTING.  I think I "may" re-evaluate my stance on a need for a progression.  This bet selection is very effective, and with a proper Stop-loss, could be an overall winner.  I will continue to test this.  If this keeps up, I may just go with flat betting and keep the progression in my back pocket to play from time to time.

If flat betting wins at a higher than normal rate, it could be effective walking up to a table and playing a 3 spin set.  If you win, you stay and keep playing.  If you lose, you walk to another table and casually play another 3 spin set.  The goal would be to obviously have more winning sets than losing sets by the end of the night.

GLC

Barcode,


I don't mean to be negative, but this method of selecting a bet isn't that unique.  Nor is betting in sets of 3 that unique.  It's the wedding of the two together that is giving this system legs, IMO.


I guess flat betting can't do no harm, but I'm pretty sure you're going to find that your progression is worth buying in for a few more units.


GLC
In my case it doesn't matter.  I'm both!

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